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Which one of the following is the formula standard-state free energies?(a) -dF = 2.303 R log k(b) -dF = RT log k(c) -dF = 2.303 RT log k(d) -dF = 2.303 RT log TI have been asked this question in semester exam.My question is from Catalyst in portion Hydrocarbon Synthesis and Hydroformylation of Unit Processes

Answer»

Right OPTION is (c) -dF = 2.303 RT log k

For explanation: The EQUILIBRIUM constants were CALCULATED from the standard-state free energies,-dF = 2.303 RT log k. where R is the gas constant and T the absolute temperature in DEGREES Kelvin.



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