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Which one of the following is wrongly matchedA. Saponification of `CH_(3)COOC_(2)H_(5)` - Second order reactionB. Hydrolysis of `CH_(3)COOCH_(3)` - First order reactionC. Decomposition of `H_(2)O_(2)`- First order reactionD. Combination of `H_(2)` and `Br_(2)` to give HBr- Zero order reaction |
Answer» Correct Answer - d `H_(2) + Br_(2) hArr 2 HBr ` is a 1.5 order reaction i.e, `k= [H_(2)][Br_(2)]^(1//2)` . |
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