Which quantity out of `Delta_(r)G` and`Delta_(r)G^(c-)` will be zero at equilibrium ?

Which quantity out of `Delta_(r)G` and`Delta_(r)G^(c-)` will be zero a

1.	Which quantity out of `Delta_(r)G` and`Delta_(r)G^(c-)` will be zero at equilibrium ?
Answer» `Delta_(r)G= Delta_(r)G^(@) + RT ln K`. When reaction attains equilibrium `Delta_(r) G=0` so that`Delta_(r)G^(@)=- RT` ln K . Thus `Delta_(r)G^(@) =0` only when `K+1` . For all other values of `K, Delta_(r)G^(@) ` will be non-zero.

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Which quantity out of `Delta_(r)G` and`Delta_(r)G^(c-)` will be zero at equilibrium ?

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