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InterviewSolution
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Which quantity out of `Delta_(r)G " and " Delta_(r) G^(Θ)` will be zero at equilibrium ? |
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Answer» Gibbs energy for a reaction in which all reactants and products are in standard state. `Delta_(r)G^(Θ)` is related to the equilibrium constant of the reaction as follows `Delta_(r)G = Delta_(r)G^(Θ) + RT ln K` At equilibrium, `0 = Delta_(r) G^(@) + RT ln K " " ( :. Delta_(r) G = 0)` or `Delta_(r) G^(Θ) = - RT ln K` `Delta_(r) G^(Θ) = 0` When `K = 1` For all other values of `K, Delta_(r)G^(Θ)` will be non-zero. |
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