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Which term of the A.P. 14, 9, 4, – I, – 6, ... is – 41 ? |
Answer» Here, a = 14, d = 9 – 14 = –5 and an = –41 To find : n We have, an = a + (n – 1)d ⇒ –41 = 14 + (n – 1) × (–5) ⇒ –41 = 14 – 5n + 5 ⇒ –41 = 19 – 5n ⇒ – 41 – 19 = –5n ⇒ –60 = –5n ⇒ n = 12 Therefore, the 12th term of the given AP is –41. |
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