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Which term of the AP 4. 9, 14, …. is 254? |
Answer» Given A. P 4, 9, 14, ………… First term (a) = 4 Common difference (d) = a2 – a1 = 9 – 4 = 5 We know that, nth term (an) = a + (n – 1)d And, given nth term is 254 4 + (n – 1)5 = 254 (n – 1)∙5 = 250 n – 1 = 250/5 = 50 n = 51 ∴ 51th term in the A.P is 254. |
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