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Which term of the arithmetic progression 8, 14, 20, 26,..... will be 72 more than its 41th term? |
Answer» a = 8, d = 6, Last term = an an = a + (n – 1) d = 8 + (n – 1) 6 = 2 + 6n (i) Let, 41st term, a41 = 8 + (41 – 1) 6 = 8 + 40 x 6 = 248 Now the term is 72 more than its 41st term an = 72 + a41 = 72 + 248 = 320 Putting this value in (i), we get 320 = 2 + 6n 6n = 318 n = 53 Hence, 53rd term of the given A.P. is 72 more than its 41st term |
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