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Which term of the progression 18, -12, 8, … is 512/729 ? |
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Answer» By using the formula, Tn = arn-1 a = 18 r = t2/t1 = (-12/18) = -2/3 Tn = 512/729 n = ? Tn = arn-1 512/729 = 18 (-2/3)n-1 29/(729 × 18) = (-2/3)n-1 29/36 × 1/2×32 = (-2/3)n-1 (2/3)8 = (-1)n-1 (2/3)n-1 8 = n – 1 n = 8 + 1 = 9 ∴ 9th term of the Progression is 512/729 |
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