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Answer» Hey ur method is below
Dear Here we will use the method of Power = voltage2resistance method .please follow the TOTAL solution you will understand the problem as I trying do it with simple words and simple method to solve this problem . The rating of the BULB is 200 V -100 W . So the RESISTANCE of the bulb is , R =V2P=(200)2100=400 Ω Now the bulb burn for 4 hours /DAY . So , the energy CONSUMED by the bulb is , E =V2R×t=100×4=400 Wh=4001000=0·4 BOT unit Now the cost of one unit energy is rupees 4·60 then the cost of energy consumed by the bulb is ,4·60×0·4=1·84 rupees Regards
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