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InterviewSolution
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Without using trigonometric table, evaluate:(i) \(\frac{cos35°}{sin55°}\)(ii) \(\frac{cosec42°}{sec48°}\)(iii) \(\frac{cot38°}{tan52°}\) |
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Answer» (i) \(\frac{cos35°}{sin55°}\) = \(\frac{cos(90°-55°)}{sin55°}\) = \(\frac{sin55°}{sin55°}\) [∵ sin(90 - θ) = cos θ] = 1 (ii) \(\frac{cosec42°}{sec48°}\) = \(\frac{cosec(90°-48°)}{sec48°}\) = \(\frac{sec48°}{sec48°}\) [∵ sec(90 - θ) = cosec θ] = 1 (iii) \(\frac{cot38°}{tan52°}\) = \(\frac{cot(90°-52°)}{tan52°}\) = \(\frac{tan52°}{tan52°}\) [∵ tan(90 - θ) = cot θ] = 1 |
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