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InterviewSolution
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Without using trigonometric table, evalute:(i) \(\frac{sin16°}{cos74°}\)(ii) \(\frac{sec11°}{cosec79°}\)(iii) \(\frac{tan21°}{cot63°}\) |
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Answer» (i) \(\frac{sin16°}{cos74°}\) = \(\frac{sin(90°-74°)}{cos74°}\) = \(\frac{cos74°}{cos74°}\) [∵ sin(90 - θ) = cos θ] = 1 (ii) \(\frac{sec11°}{cosec79°}\) = \(\frac{sec(90°- 79°)}{cosec79°}\) = \(\frac{cosec79°}{cosec79°}\) [∵ sec(90 - θ) = cosec θ] = 1 (iii) \(\frac{tan27°}{cot63°}\) = \(\frac{tan(90°- 63°)}{cot63°}\) = \(\frac{cos63°}{cos63°}\) [∵ tan(90 - θ) = cot θ] = 1 |
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