here is your answer please start following me and DROP me some thanksExplanation:Your program should contain the following FUNCTIONS:// Compute the mean of an array of double values double mean(const double x[], int size) // Compute the deviation of double values double deviation(const double x[], int size) Write a TEST program that prompts the user to ENTER 10 numbers and displays the mean and deviation, as shown in the following sample run:ex:Enter TEN numbers: 1.9 2.5 3.7 2 1 6 3 4 5 2The mean is 3.11The standard deviation is 1.55738So this what I have: #include #include using namespace std;void displayVals(int vals[], int numVals, int sum);void getVals(int vals[], int numVals);double average(int sum, int numVals);double stanDev(int vals[], double mean, int numVals);int main(){    int numVals=10;    int sum = 0;    int vals[9];    getVals(vals, numVals);    cout << endl;    displayVals(vals, numVals, sum);    cout << endl;}void getVals(int vals[], int numVals){    int index;    cout << "Enter ten numbers :" << "\n";    for (index = 0; index < numVals; index++) {        cout << index + 1;        cin >> vals[index];    }}void displayVals(int vals[], int numVals, int sum){    int index;    for (index = 0; index < numVals; index++) {        cout << index + 1;        cout << vals[index] << ".\n";    }    cout << endl;    cout << "The mean is ";    cout << average(vals, numVals, sum) << ".\n";    cout << endl;    cout << "The standard deviation is: ";    cout << stanDev(vals, numVals, sum) << ".\n";}double average(int sum, int numVals){    double dsum = (double)sum;    double dnumVals = (double)numVals;    return dsum / dnumVals;}double stanDev(int vals[], double mean, int numVals){    double sum = 0, dVals = 0, value = 0, variance = 0;    for (int i = 0; i < numVals; i++)    {        dVals = (double)vals[i];        value = (dVals - mean)*(dVals - mean);        sum += value;        variance = sum / (numVals);    }    return sqrt(variance);