Write java program to find whether a number is buzz number with ternor

1.	Write java program to find whether a number is buzz number with ternory operator
Answer» Answer: A number is said to be a BUZZ number if it is divisible by 7 or has 7 as a digit in its unit place... Here is ur programming import java.util.; public CLASS BuzzNumberCheck { public static void main(String ARGS[]) { Scanner ob=new Scanner(System.in); System.out.println("ENTER the number to be checked."); int num=ob.nextInt(); if(num%10==7 \|\| num%7==0) { System.out.println(num+" is a Buzz Number."); } else { System.out.println(num+" is not a Buzz Number."); } } } please MARK me as brain list please Explanation:*

Write java program to find whether a number is buzz number with ternory operator

Answer»

Answer:

A number is said to be a BUZZ number if it is divisible by 7 or has 7 as a digit in its unit place...

Here is ur programming

import java.util.*;

public CLASS BuzzNumberCheck

{

public static void main(String ARGS[])

{

Scanner ob=new Scanner(System.in);

System.out.println("ENTER the number to be checked.");

int num=ob.nextInt();

if(num%10==7 || num%7==0)

{

System.out.println(num+" is a Buzz Number.");

}

else

{

System.out.println(num+" is not a Buzz Number.");

}

please MARK me as brain list please

Explanation: