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Write order and degree (if defined)of differential equations: \(\sqrt{1-y^2}dx+\sqrt{1-x^2}dy=0\)√(1-y2)dx+√(1-x2)dy=0 |
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Answer» The order of a differential equation is the order of the highest derivative involved in the equation. So, the order comes out to be 1 as we have \(\sqrt{1-y^2}dx+\sqrt{1-x^2}dy=0\) \(\cfrac{dy}{dx}=-\cfrac{\sqrt{1-y^2}}{\sqrt{1-x^2}}\) and the degree is the highest power to which a derivative is raised. So the power at this order is 1. So the answer is 1, 1. |
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