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Write the equilibrium expressions (K_(C )) for the decomposition of 2 moles of sulphur trioxide and relate it to K_(C ) of the reaction carried out with 1 mole and 4 moles of SO_(3), respectively. |
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Answer» Solution :`K_(c )` value for the equilibrium REACTION `2SO_(3) implies 2SO_(2)+O_(2)` is `K_(c_(1))`=([SO_(2)]^(2)[O_(2)])/(SO_(3)]^(2))` `K_(c )` value for the equilibrium reaction `SO_(3) implies SO_(2)+(1)/(2)O_(2)` is `K_(c_(2))=([SO_(2)][O_(2)]^(1/2))/([SO_(3)])` `therefore_(c_(2))=K_(c_(1))^(2)` `K_(c )` value for the equilibrium reaction `4SO_(3) implies 4SO_(2)+2O_(2)` is `K_(c_(3))=([SO_(2)]^(4)[O_(2)]^(2))/([SO_(3)]^(4)` `THEREFORE K_(c_(3))=sqrt(K_(c_(1)))` |
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