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Write the expression an - ak for the A.P. a, a + d, a + 2d, ..........Hence, find the common difference of the A.P. for which(i)11th terms is 5 and 13th term is 79.(ii) a10 - a5 = 200(iii) 20th term is 10 more than the 18th term. |
Answer» Let nth term an = a + (n – 1) d = a + nd – d kth term, ak = a + (k – 1) d = a + kd – d Now, an - ak = (a + nd – d) – (a + kd – d) = nd – kd = d (n – k) (i) a11 = 5 a + 10d = 5 (i) a13 = 79 a + 12d = 79 (ii) By subtracting (i) from (ii), we get 2d = 74 d = 37 Hence, the common difference is 37 (ii) a10 = a + 9d (i) a5 = a + 4d (ii) a10 – a5 = a + 9d – a – 4d 200 = 5d d = 40 Hence, common difference is 40 (iii) a20 = a + 19d (i) a18 = a + 17d (ii) Given that a20 = a18 + 10 a + 19d = a + 17d + 10 2d = 10 d = 5 Hence, common difference is 5 |
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