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Write the first terms of the sequences whose nth term are:an = (-1)n2n |
Answer» Given sequence whose an = (-1)n2n To get first five terms of the sequence, put n = 1, 2, 3, 4, 5 in the above. a1 = (-1)1.21 = (-1).2 = -2 a2 = (-1)2.22 = (-1).4 = 4 a3 = (-1)3.23 = (-1).8 = -8 a4 = (-1)4.24 = (-1).16 = 16 a5 = (-1)5.25 = (-1).32 = -32 ∴ The first five terms of the sequence are – 2, 4, – 8, 16, – 32. |
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