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Write the K_(C ) value for the equilibrium N_(2(g))+3H_(2(g)) hArr 2NH_(3(g)) and relate it to the K_(C ) values for the following equilibria : (a) (1)/(2)N_(2(g))+(3)/(2)H_(2(g)) hArr NH_(3(g)) (b) 2N_(2(g)) +6H_(2(g)) hArr 4NH_(3(g)) |
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Answer» Solution :`N_(2)+3H_(2) hArr 2NH_(3)` `K_(c_(1))=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))` `(a) (1)/(2)N_(2(g))+(3)/(2)H_(2(g)) hArr NH` `K_(c_(2))=([NH_(3)])/([N_(2)]^(1/2)[H_(2)]^(3/2))` `K_(c_(2))=SQRT(K_(c_(1)))` (b) `2N_(2(g))+6H_(2(g)) hArr 4NH_(3(g))` `K_(c_(3))=([NH_(3)]^(4))/([N_(2)]^(2)[H_(2)]^(6))` `K_(c_(3))=K_(c_(1))^(2)` |
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