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Write the sum of first n odd natural numbers. |
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Answer» First n odd numbers are 1, 3, 5, 7, 9........., (2n–1) which forms an A.P a= 1 l= 2n – 1 where l be the last term Sn = \(\frac{n}{2}\)(2a + (n–1) d) or \(\frac{n}{2}\)(a + l) = \(\frac{n}{2}\)(1 + 2n –1) = \(\frac{n}{2}\)(2n) =n (n) =n2 |
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