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`x^(2)=-16y` |
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Answer» Given equation `x^(2)=-16y` Comparing with `x^(2)=-4ay`, `4a=16" "rArr" "a=4` `:. "Coordinates of focus"-=(0,-a)-=(0,-4)` Axis of parabola : x=0 Equation of directrix : y-a=0 `rArr" "y-4=0` Length of latus rectum `=4a=4xx4xx=16` |
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