1.

`x^(2)=-16y`

Answer» Given equation `x^(2)=-16y`
Comparing with `x^(2)=-4ay`,
`4a=16" "rArr" "a=4`
`:. "Coordinates of focus"-=(0,-a)-=(0,-4)`
Axis of parabola : x=0
Equation of directrix : y-a=0
`rArr" "y-4=0`
Length of latus rectum `=4a=4xx4xx=16`


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