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`x^(2)(dy)/(dx)+y^(2)=xy` |
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Answer» Correct Answer - `Cx=e^(x//y)` `x(dv)/(dx)=-v^(2) rArr -1/v^(2)dv=int-1/xdx rArr 1/v =logx +log C`. `therefore logCx=x/y rArr Cx=e^(x//y)` |
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