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`x^(2)dy+y(x+y)dx=0` |
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Answer» Correct Answer - `x^(2)y=C^(2)(y+2x)` `int(dv)/(v(v+2))=-int1/xdx` `rArr 1/2int{1/v-1/(v+2)}dv=-int1/xdx` [By Partial fractions] |
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