|x + 3| < 0.15 Express in interval and neighbourhood form

1.	\|x + 3\| < 0.15 Express in interval and neighbourhood form
Answer» Here, a = – 3: δ = 0.15 In Interval form : (a – δ, a + δ) \|x + 3\| < 0.15 = (- 3 – 0.15, – 3 + 0.15) = (- 3.15, – 2.85) In Neighbourhood form : N (a, δ) \|x + 3\| < 0.15 = N(-3, 0.15)

Answer»

Here, a = – 3: δ = 0.15

In Interval form : (a – δ, a + δ)

|x + 3| < 0.15 = (- 3 – 0.15, – 3 + 0.15)

= (- 3.15, – 2.85)

In Neighbourhood form : N (a, δ)

|x + 3| < 0.15 = N(-3, 0.15)

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