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`x(x^(2)-1)(dy)/(dx)=1` , y=0 यदि x=2 |
Answer» `x(x^(2)-1)(dy)/(dx)=1` `implies dy=(1)/(x(x-1)(x+1))dx` `impliesint dy=int{-(1)/(x)+(1)/(2(x+1))+(1)/(2(x-1))}dx+c` `implies y=-log x+(1)/(2)log(x+1)+(1)/(2)log(x-1)+c" ....(1)"` अब, x = 2 पर y = 0 `therefore 0=-log2+(1)/(2)log3+0+c` `implies c=(1)/(2)log.(4)/(3)` `therefore` समीकरण (1) से, `y=-logx+(1)/(2)log(x+1)+(1)/(2)log(x-1)+(1)/(2)log.(4)/(3)` जोकि अभीष्ट विशिष्ट हल है। |
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