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`x(x^(2)-1)(dy)/(dx)=1` , y=0 यदि x=2

Answer» `x(x^(2)-1)(dy)/(dx)=1`
`implies dy=(1)/(x(x-1)(x+1))dx`
`impliesint dy=int{-(1)/(x)+(1)/(2(x+1))+(1)/(2(x-1))}dx+c`
`implies y=-log x+(1)/(2)log(x+1)+(1)/(2)log(x-1)+c" ....(1)"`
अब, x = 2 पर y = 0
`therefore 0=-log2+(1)/(2)log3+0+c`
`implies c=(1)/(2)log.(4)/(3)`
`therefore` समीकरण (1) से,
`y=-logx+(1)/(2)log(x+1)+(1)/(2)log(x-1)+(1)/(2)log.(4)/(3)`
जोकि अभीष्ट विशिष्ट हल है।


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