`(x+y)(dy)/(dx)=-1`

1.	`(x+y)(dy)/(dx)=-1`
Answer» `(x+y)(dy)/(dx)=1 implies (dx)/(dy)=x+y` `implies (dx)/(dy)-x=y` यहाँ, P=-1, Q=y `I.F.=e^(intPdy)=e^(int-1dy)=e^(-y)` और व्यापक हल : `x(e^(-y))=intye^(-y)dy+c` `impliesxe^(-y)=y(-e^(-y))-int1(-e^(-y))dy+c` `=-ye^(-y)-e^(-y)+c` `impliesx=-y-1+ce^(y)` `impliesx+y+1=ce^(y)`

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