1.

XIntegrate:(x+1)2 (x-1)​

Answer»

Answers

explanation:

∫x+12x−1−−−−−√dx

=12∫2x+22x−1−−−−−√dx

=12∫2x−1+32x−1−−−−−√dx

=12∫2x−12x−1−−−−−√dx+32∫12x−1−−−−−√dx

=12∫(2x−1)12dx+32∫(2x−1)−12dx

=14∫(2x−1)12D(2x)+34∫(2x−1)−12d(2x)

=16(2x−1)32+32(2x−1)12+C

=16(2x−1)12(2x−1+9)+C

=16(2x−1)12(2x+8)+C

I hope it HELP you!

:)



Discussion

No Comment Found