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XIntegrate:(x+1)2 (x-1) |
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Answer» Answers explanation: ∫x+12x−1−−−−−√dx =12∫2x+22x−1−−−−−√dx =12∫2x−1+32x−1−−−−−√dx =12∫2x−12x−1−−−−−√dx+32∫12x−1−−−−−√dx =12∫(2x−1)12dx+32∫(2x−1)−12dx =14∫(2x−1)12D(2x)+34∫(2x−1)−12d(2x) =16(2x−1)32+32(2x−1)12+C =16(2x−1)12(2x−1+9)+C =16(2x−1)12(2x+8)+C I hope it HELP you! :) |
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