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`y^(2)=-8x` |
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Answer» Given equation `y^(2)=-8x` Comparing with `y^(2)=-4ax` `4a=8" "rArr" "a=2` `:. "Coordinates of focus"-=(-a,0)-=(-2,0)` Axis of parabola of directrix : `x-a=0" "rArr" "a-2=0` Length of latus rectum `=4a=4xx2=8` |
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