Saved Bookmarks
| 1. |
यदि `""^(2n+1)P_(n-1): ""^(2n-1)P_(n) = 3:5, n` का मान निकालिए |
|
Answer» प्रश्न से , `""^(2n+1)P_(n-1): ""^(2n-1)P_(n) = 3:5, n` ` therefore ((2n+1)!)/((n+2)!) : ((2n-1)!)/((n-1)!) = 3:5"या " ((2n +1)!)/((n+2)!) xx((n-1)!)/((2n-1)!) = (3)/(5)` या `((2n+1)!)/((2n-1)) : ((n-1)!)/((n+1)!) = 3/5" या " ((2n +1).2n)/((n+2)(n+1)n)= 3/5` या ` 10(2n+1)= 3(n+1)(n+2) "या " 3n^(2) - 1 1 n - 4 = 0 ` या `(n-4)(3n+1) = 0 therefore n=4 , -(1)/(3) ` लेकिन ` n ne - (1)/(3) therefore n = 4 ` |
|