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यदि (If) `x=acos^(3)theta,y=asin^(3)theta`, (find) `(dy)/(dx)` ज्ञात करें । |
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Answer» `x=acos^(3)theta` `therefore(dx)/(d theta)=a(d)/(d costheta)(cos^(3)theta)*(d)/(d theta)(costheta)` या `(dx)/(d theta)=a.3cos^(2) theta(-sintheta)=-3a.cos^(2)theta.sintheta` … (1) पुनः `y=asin^(3)theta` `therefore(dy)/(d theta)=a(d (sin^(3)theta))/(dsintheta)*(d)/(d theta)(sintheta)` या `(dy)/(d theta)=a.3sin^(2) theta.cos=3a sin^(2) thetacostheta` ... (2) अब `(dy)/(dx)=((dy)/(d theta))/((dx)/(d theta))=(3a*sin^(2) theta*costheta)/(-3acos^(2) thetasin theta)=-tan theta` |
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