1.

यदि (If) `ax^(2)+2hxy+by^(2)+2gx+2fy+c=0` ,(find) `(dy)/(dx)` निकालें ।

Answer» दिया है `ax^(2)+2hxy+by^(2)+2gx+2fy+c=0` … (1)
दोनों तरफ x के सापेक्ष अवकलित करने पर हमें मिलता है
`(d)/(dx)(ax^(2))+(d)/(dx)(2hxy)+(d)/(dx)(by^(2))+(d)/(dx)(2gx)+(d)/(dx)(2fy)+(d)/(dx)(c )=(d)/(dx)(0)`
या `a(d)/(dx)(x^(2))+2h(d)/(dx)(xy)+b(d)/(dx)(y^(2))+2"g"(d)/(dx)(x)+2"f"(d)/(dx)(y)+0=0`
या `2ax+2h(x(dy)/(dx)+y*1)+b*2y(dy)/(dx)+2g*1+2f*(dy)/(dx)=0`
या `(dy)/(dx)(2hx+2by+2f)+2ax+2hy+2g=0`
`therefore(dy)/(dx)=-(2(ax+hy+g))/(2(hx+by+f))=-((ax+hy+g)/(hx+by+f))`


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