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यदि किसी `triangleABC` में `A = 30^(@)` तथा `B = 60^(@)` हो तो `a : b:c` ज्ञात करें | |
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Answer» `because A + B + C = 180^(@) therefore 30^(@) + 60^(@) + C = 180^(@)` `therefore C = 180^(@) - 90^(@) = 90^(@)` अब सूत्र से, `(a)/(sin A) = (b)/(sin B) = (c)/(sinC)` `therefore a : b : c = sin A : sin B : sin C` ` = sin 30^(@) : sin60^(@) : sin 90^(@) = (1)/(2) : (sqrt(3))/(2) : 1 = 1 : sqrt(3) : 2` |
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