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यदि `log_(0.3)(x-1) lt log_(0.09) (x-1)` हो , तो x स्थित हैA. `(2 , infty )`B. `(-2, -1)`C. (1, 2)D. इनमे से कोई नहीं |
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Answer» Correct Answer - A `log_(0.3)(x-1) lt log_((0.3)^(2))(x-1)` ` = 1/2 log_(0.3)(x-1)` ` :. 1/2 log_(0.3)(x-1) lt 0` अथवा `log_(0.3)(x-1) lt 0 = log 1` अथवा ` (x-1) gt 1` अथवा ` x gt 2` |
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