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यदि `""^(n)C_(8) = ""^(n)C_(6)` तो `""^(n)C_(2)` का मान ज्ञात कीजिए ।

Answer» दिया है - `""^(n)C_(8) = ""^(n)C_(6)`
`p = 8, q = 6`
हम जानतें हैं कि `""^(n)C_(p) = ""^(n)C_(q) rArr p = q` या `p+q = n`
यहाँ `p ne q ` इसलिए `p+ q = n rArr n = 8 + 6 = 14`
`:. ""^(n)C_(2) = ""^(14)C_(2) = (14.13)/(2!) = 91`


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