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यदि `sin theta-cos theta=1/2,` तब `(1)/(sin theta+cos theta)` का मान ज्ञात कीजिए. |
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Answer» यहाँ `sin theta -cos theta =1/2 implies(sin theta-cos theta)^(2)=((1)/(2))^(2)` ` implies2sin theta*cos theta=3/4" "...(1)` अब, `(sin theta+cos theta)^(2)=sin^(2)theta+cos ^(2)theta+2 sin theta cos theta=1+3/4` `implies(sintheta+cos theta)=sqrt((7)/(4))` `implies(1)/(sin theta+cos theta)=(2)/(sqrt7)=(2sqrt7)/(7)*` |
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