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यदि `tan(theta_(1)+theta_(2))=(tan theta_(1)+tan theta_(2))/(1-tantheta_(1)tan theta_(2)), theta_(1)` व `theta_(1)` न्यूनकोण है तब `theta_(1)+theta_(2)` का मान ज्ञात कीजिए यदि `tan theta_(1)=1/2` व `tan theta_(2)=1/3` |
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Answer» दिया है `tan (theta_(1)+theta_(2))=(tan theta_(1)+tan theta_(2))/(1-tan theta_(1)tan theta_(2))` `(1/2+1/3)/(1-1/2xx1/3)=((3+2)/(6))/(1-1/6)=(5/6)/(5/6)=1" "(because tan theta_(1)=1/2` व `tan theta_(2)=1/2)` `impliestan(theta_(1)+theta_(2))=1impliestheta_(1)+theta_(2)=45^(@)` |
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