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your answer will un2. A farmer moves along theboundary of a square field of side10 m in 40 s. What will be themagnitude of displacement of thefarmer at the end of 2 minutes 20seconds from his initial position? |
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Answer» Total distance covered 10m in 40secTotal time taken= 2min 20sec= 140secTotal round completed = 140/40=3.5 rounds So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem. AC2= AB2+BC2AC2= (10)2+(10)2AC2= 100+100AC2=200 AC = (200)1/2AC= 10× (2)½ |
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