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Your body is executing SHM with amplitude a and angular frequency Omega the root mean square speed of the body for one complete oscillation will be position of the particle at equal to zero is mean position |
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Answer» We know for a SHM velocity is v=ω[√(A²-x²)] by question speed is Aω/2 ∴A²ω²/4 =A²ω²-ω²x² solving we GET x²=3A²/4 so its displacement is ±√3A/2 from mean position |
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