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`Zn+2H^(+)toZn^(2+)+H_(2)` Half-life period is independent of concentration of zinc at constant pH. For the constant concentraio of Zn, rate becomes `100` times when pH is decreased from 3 "to" 2. Hence,A. `(dx)/(dt)=k[Xn]^(0)[H^(+)]^(2)`B. `((dx)/(dt))=k[Zn][H^(+)]^(2)`C. rate is not affected if connentration of zinc is made fourn times and that of `H^(+)` ion is halvedD. rate becomes four times if concentration of `H^(+)` ions is doubled at constant Zn concentration. |
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Answer» Correct Answer - B::C::D |
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