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`Zn|Zn^(2+)(c_(1)) || Zn^(2+)(c_(2))|Zn`. For this cell `DeltaG` is negative if `:`A. `C_(1)=C_(2)`B. `C_(1)gtC_(2)`C. `C_(2)gtC_(1)`D. none |
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Answer» Correct Answer - C `ZntoZn_((c_(1)))^(2+)+2e^(-)` `Zn_((c_(2)))^(2+)+2e^(-)toZn` `Zn_((c_(2)))^(2+)hArrZn_((c_(1)))^(2+)` `E=0-(0.0591)/(2)log((C_(1))/(C_(2)))` `Eto+ve` when `C_(1)ltC_(2)` |
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