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201.	A compound ‘P’ on treating with concentrated H2SO4 forms ‘R’. The product ‘R’ on heating at 460K forms a zwitter ionic compound. Identify P, R respectively.(a) Aniline; anilinium hydrogensulphate(b) Aniline; sulphanilic acid(c) Anilinium hydrogensulphate; sulphanilic acid(d) Sulphanilic acid; anilinium hydrogensulphateI had been asked this question during an online interview.I want to ask this question from Amines Chemical Reactions topic in division Amines of Chemistry – Class 12
Answer» The correct choice is (a) ANILINE; anilinium hydrogensulphate Easy EXPLANATION: Aniline (P) REACTS with conc. H2SO4 to form anilinium hydrogensulphate (R) which on heating at 453-473K produces sulphanilic acid (zwitter ionic compound).

202.	Which of the following is not a final product of the reaction between propylamine and nitrous acid?(a) CH3CH2CH2N2Cl(b) CH3CH2CH2OH(c) N2 gas(d) H2OThis question was addressed to me in an online quiz.Question is from Amines Chemical Reactions topic in division Amines of Chemistry – Class 12
Answer» The correct answer is (a) CH3CH2CH2N2Cl The explanation is: CH3CH2CH2N2Cl is a diazonium salt derivative of PROPANAMINE and is first formed when it REACTS with HNO2. This is a very unstable compound and IMMEDIATELY decomposes to GIVE propanol and evolves NITROGEN gas.

203.	The reaction between ethanamine and acetyl chloride will give N-ethylethanamide only in the presence of a strong base, like pyridine.(a) True(b) FalseI got this question in semester exam.My question is from Amines Chemical Reactions topic in portion Amines of Chemistry – Class 12
Answer» Right CHOICE is (b) False To explain: A base like pyridine may be USED in the acylation of amines only to increase the CONCENTRATION of the product FORMED. The base removes the HCl formed during the REACTION and shifts the equilibrium to the right-hand side.

204.	If x and y are the pKb values of p-methylaniline and N,N-dimethylaniline, what is the relation between x and y?(a) x > y(b) x < y(c) x = y(d) x >> yThe question was asked in examination.The origin of the question is Amines Chemical Reactions topic in chapter Amines of Chemistry – Class 12
Answer» The correct answer is (a) x > y To EXPLAIN: The basicity of N-methyl anilines is very slightly higher than that of ring SUBSTITUTED methyl anilines. This is because the methyl GROUP is directly attached to the N atom in N,N-dimethylaniline and the electron effect is more PRONOUNCED. But this is only a minute effect.

205.	Which of the following is least soluble in water?(a) CH3CH2NH2(b) CH3CH2OH(c) HCOOH(d) CH3NH2This question was addressed to me in examination.Question is from Amines Physical Properties topic in portion Amines of Chemistry – Class 12
Answer» CORRECT choice is (a) CH3CH2NH2 For explanation I would say: Lower amines are more soluble because of the smaller hydrophobic alkyl part. ALSO, ALCOHOLS and carboxylic ACIDS have higher solubility than amines because of the greater polarity of OH bond than NH bond.

206.	If ‘x’ ml of butan-1amine and ‘y’ ml of butan-1-ol is completely soluble in 100ml of water each, what is the relation between x and y?(a) x > y(b) x < y(c) x = y(d) x + y = 100I got this question in homework.This intriguing question comes from Amines Physical Properties topic in portion Amines of Chemistry – Class 12
Answer» Right option is (b) x < y To ELABORATE: Alcohols are more polar than amines of COMPARABLE MOLECULAR masses and form STRONGER intermolecular hydrogen bonds with water. Therefore, the solubility of butan-1-ol is more than that of butan-1-amine.

207.	What is obtained when the following compound undergoes ammonolysis in a sealed tube at 373K with iodomethane?(a) Dimethylamine(b) N-Iodo-N-methylmethanamine(c) Tetramethyl ammonium iodide(d) No reactionThe question was asked in an international level competition.The question is from Preparation of Amines topic in division Amines of Chemistry – Class 12
Answer» Right option is (c) Tetramethyl ammonium iodide The BEST EXPLANATION: Tertiary amines are formed as the ammonolysis of alkyl halides PROCEEDS to form 1° and 2° amines, which further reacts with the alkyl halide. The compound SHOWN is trimethylamine which reacts with iodomethane (alkyl halide) to form a quaternary ammonium salt [(CH3)4N^+]I^–.

208.	Which of the following names are incorrect according to IUPAC?(a) 1-Phenylethanamine(b) N-Methylaniline(c) N-Butylaminoethane(d) Propane-1,2-diamineI have been asked this question in a job interview.The question is from Amines Nomenclature topic in chapter Amines of Chemistry – Class 12
Answer» The CORRECT option is (c) N-Butylaminoethane The explanation: The larger alkyl GROUP should be CONSIDERED as parent CHAIN, which in this case is butyl group. THUS, the correct name will be N-ethylbutanamine.

209.	What is the IUPAC name of CH3-NH-CH2-CH(NO2)-CH3 ?(a) N-Methyl-2-nitropropanamine(b) 1-Aminomethyl-2-nitropropane(c) N-(2-Nitropropyl)methanamine(d) N-Methyl-2-methylnitropropanamineI have been asked this question in unit test.This is a very interesting question from Amines Nomenclature topic in section Amines of Chemistry – Class 12
Answer» Correct OPTION is (a) N-Methyl-2-nitropropanamine The EXPLANATION is: This compound contains all substituent FUNCTIONAL GROUPS, and is named as a derivative of the compound containing the functional group which occurs first in alphabetical ORDER, i.e., amino group.

210.	Identify the correct name of the shown compound.(a) 4-Amino-1,1-Dimethylcyclohexane(b) 4,4-Dimethylcyclohexan-1-amine(c) 4,4-Dimethylaniline(d) N-(4,4-Dimethylcyclohexyl)amineThis question was addressed to me by my school teacher while I was bunking the class.My question is based upon Amines Nomenclature in chapter Amines of Chemistry – Class 12
Answer» Right CHOICE is (b) 4,4-Dimethylcyclohexan-1-amine Explanation: This is an ALIPHATIC primary amine which is CYCLIC in structure. The two METHYL groups at C-4 position act as substituents of the CYCLOHEXYL ring with the amino group at C-1 position.

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