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251.

Which of the following compound will not undergo azo coupling reaction with benzene diazonium chloride.(i) Aniline(ii) Phenol(iii) Anisole(iv) Nitrobenzene

Answer»

(iv) Nitrobenzene

252.

Among the following amines, the strongest Brönsted base is __________.

Answer» The correct answer is (iv)
253.

Which of the following compounds is the weakest Brönsted base?

Answer» The correct answer is (iii)
254.

During the reduction of nitro compound to an amine the oxidation number of nitrogen changes byA. six unitsB. five unitsC. four unitsD. three units

Answer» Correct Answer - A
`Ar-overset(+3)(N)overset(H_(2)" Catalyst")underset(underset((2)OH^(-))(or(1)F,HCl))rarrAr-overset(-3)(N)H_(2)`
Overall, this is a `6ebar` rediuction as the oxidation number of N changes `+3` to `-3`
255.

Arenediazonium ion are weak electrophiles, they react with highly reactive aromatic compounds with phenols and tertiary aryl amines to yeild azo compounds. This electrophilic substitution is often called a diazo coupling reaction. What is the major product of given reaction? A. Balz Schiemenn reactionB. Gattermann reactionC. Carbylamines reactionD. Diazotization reaction

Answer» Correct Answer - D
256.

Arenediazonium ion are weak electrophiles, they react with highly reactive aromatic compounds with phenols and tertiary aryl amines to yeild azo compounds. This electrophilic substitution is often called a diazo coupling reaction. What is the major product of given reaction? The product (P) isA. B. C. D.

Answer» Correct Answer - A
257.

Which of the following is the weakest Brönsted base?

Answer»

The correct answer is (i)

258.

Which of the following reagents would not be a good choice for reducing an aryl nitro compound to an amine?(i) H2 (excess)/Pt(ii) LiAlH4 in ether(iii) Fe and HCl(iv) Sn and HCl

Answer»

(ii) LiAlH4 in ether

259.

Benzylamine may be alkylated as shown in the following equation :C6H5CH2NH2 + R—X → C6H5CH2NHRWhich of the following alkylhalides is best suited for this reaction through SN1 mechanism?(i) CH3Br(ii) C6H5Br(iii) C6H5CH2Br(iv) C2H5 Br

Answer»

(iii) C6H5CH2Br

260.

Statement -1: Tertiary amines have lower boiling point than secondary amine. and Statement-2: Hydrogen bonding is often responsible for increases in boiling point.A. Statement-1 is true, Statement-2 is true, statement-2 is a correct explanation for statement-8B. Statement-1 is true, statement-2 is true, statement-2 is not a correct explanation for statement-8C. Statement-1 is true, statement-2 is FalseD. Statement-1 is False, Statement-2 is True.

Answer» Correct Answer - A
261.

A mixture containing primary, secondary and tertiary amine is treated with diethyl oxalate. Choose the correct statementA. The distillate of the mixture after treatment mainly contains `1^(2)` amine.B. `3^(@)` amine do not react with diethyl oxalateC. This is Hinsberg method of separating `1^(@), 2^(@)` & `3^(@)` amines.D. `3^(@)` amine is removed by filtration

Answer» Correct Answer - B
262.

Incorrect statement among the following isA. `-NO_(2)` is a deactivating groupB. Causes the substitution to occur at meta-positionC. Nucleophilic ring substitution in nitrobenzene occurs at ortho and para positionD. Hydrolysis of picryl chloride requires higher temperature than chlorobenzene.

Answer» Correct Answer - D
263.

For carbylamine reaction, we need hot alc. KOH andA. any primary amine and chloroformB. chloroform and silver powderC. a primary amine and an alkyl halideD. a mono alkyl amine and trichloromethane

Answer» Correct Answer - A
Aliphatic and aromatic primary amines when warmed with chloroform and an alcoholic solution of KOH, form isocyanide or carbylamine which has very unpleasant smell.
`CH_(3)CH_(2)NH_(2)+CHCl_(3)+3KOH overset("Warm")to CH_(3)CH_(2)NC+3KCl+3H_(2)O`
264.

Indicate which nitrogen compund amongst the following would undergo Hofimann reaction ? .A. `RCONHCH_(3)`B. `RCO ONH_(4)`C. `RCONH_(4)`D. `RCONHOH`

Answer» Correct Answer - C
When amides react with bromine in the presence of caustic alkali to form a primary amine carrying one carbon atom less than the parent amide, then the reaction is known as Hofmann bromamide reaction.
`RCONH_(2)+Br_(2)+4KOH overset("Heat")to RNH_(2)+K_(2)CO_(3)+2KBr+2H_(2)O`
265.

Write IUPAC name of

Answer»

4 - Methoxy benzene amine.

266.

Of the following amines how many can give carbyl amine reaction?

Answer» Correct Answer - 3
267.

Of the following reactions, how many reaction, are used for the preparation of amines? (a) `R-C-=N overset(LiAIh_(4))rarr` (b) `R-overset(O)overset(||)(C)-NH_(2)overset(LiAIH_(4))rarr` (c) `R-overset(O)overset(|)(C)-NH_(2) overset(Br_(2)+overset(Theta)(OH))rarr` (d) `R-overset(O)overset(||)(C)-CH_(3)+H_(3)C-NO_(2)overset(NaOH)rarr` (g) `R-overset(O)overset(||)(C)-NH_(2)overset(P_(2)O_(5))underset(D)rarr` (h) `R-CH_(2)-NO_(2) overset(H_(2),Ni)rarr`

Answer» Correct Answer - 5
268.

Which of the following give L Liebermann nitroso reaction?A. B. C. D.

Answer» Correct Answer - A::B
269.

A nitrile X is treated with `LiAIH_(4)` to obtain compound `Y(C_(2)H_(7)N)`. In a separate reaction X is hydrolysed in an acid medium to obtain Z. The product obtained after mixing Y and Z will be :A. `CH_(3)CONCH_(2)CH_(3)`B. `CH_(3)CH_(2)CONHCH_(2)CH_(3)`C. `(CH_(3)COO^(-)(CH_(3)CH_(2)NH_(3)^(+))`D. `(CH_(3)CH_(2)COO^(-))(CH_(3)NH_(2)^(+))`

Answer» Correct Answer - C
270.

Consider the structures: Which of the following statements are correct?A. Basic stength of II is greater than IB. Basic strength of II is less than that of IC. Basic strength of IV is greater than IIID. Basic strength of IV is less than that of III

Answer» Correct Answer - A::C
271.

What is the overall structure of diazepam?A. B. C. D.

Answer» Correct Answer - C
272.

Following is an outline for the synthesis of diazepam. A commonly used tranquilizer. The structure of [R] would beA. B. C. D.

Answer» Correct Answer - B
273.

Following is an outline for the synthesis of diazepam. A commonly used tranquilizer. The reagent [X] in the reaction could beA. `LiAlH_(4)`B. `NaBH_(4)`C. `OH^-//H_(2)O`D. `AlCl_(3)`

Answer» Correct Answer - C
274.

Match the following :

Answer» A(p,q,s), B(p,q,s), C(p,q,s,t), D( r)
275.

In which of the following reaction cyanide will be obtained as a major product?A. `Ph-overset(O)overset(||)C-CH_(3)overset((i) LiAlH_(4))underset((ii) H_(3)O)to`B. `Ph-overset(O)overset(||)C-NH_(2)overset(NaOH)underset(Br_(2))to`C. `Ph-overset(O)overset(||)C-NH_(2)overset(P_(4)O_(10))to`D. `Ph-overset(O)overset(||)C-O-H overset(SOCl_(2))tooverset(NH_(3))to`

Answer» Correct Answer - C
`Ph-overset(O)overset(||)C-NH_(2)overset(P_(4)O_(10))underset(dehydration)toPh-C-=N`
276.

The major product obtained in the reaction is A. B. C. D.

Answer» ( c) Hofmann elimination
277.

The gas evolved when methylamine reacts with nitrous acid is….A. `NH_(3)`B. `N_(2)`C. `H_(2)`D. `C_(2)H_(6)`

Answer» Correct Answer - B
278.

The gas evolved when methylamine reacts with nitrous acid is __________.(i) NH3(ii) N2(iii) H2(iv) C2H6

Answer»

The gas evolved when methylamine reacts with nitrous acid is N2.

279.

Consider the nitratio of benzene using mixed conc. `H_(2)SO_(4)` and `HNO_(3)`. If a large amount of `KHSO_(4)` is added to the mixture, the rate of nitration will be `:`A. slowerB. unchangedC. doubledD. faster

Answer» Correct Answer - A
In the nitration of benzene in the presence of conc. `H_(2)SO_(4) " and" HNO_(3)`, nitrobenzene is formed.
`HNO_(3)+H_(2)SO_(4) hArr NO_(2)^(+) + underset("Electrophile")(HSO_(4)^(-))+underset("Nucleophile")(H_(2)O)`
If large amount of `KHSO_(4)` is added to this mixture, more `HSO_(4)^(-)` ion furnishes and hence the concentration of `NO_(2)^(+)`, i.e., electrophile decreases.
As concentration of electrophile decreases, rate of electrophilic aromatic reaction also decreases.
280.

Arrange the following in decreasing order of their basic strength: C6H5NH2, C2H5 NH2, (C2H5)2NH, NH3 

Answer»

The decreasing order of basic strength of the above amines and ammonia follows the following order:

(C2H5)2NH > C2H5 NH2 > NH3 > C6H5NH

281.

Arrange the following compounds in the increasing order of their basic strength in aqueous solution. NH3, RNH2, R2NH,R3N (R=C2H5)

Answer»

NH< RNH2 < R3N < R2NH

282.

What is the decreasing order of basicity of `1^(@)2^(@)` and `3^(@)` ethy1 amines and ammonia ?A. `(C_(2)H_(5))_(2)NH gt C_(2)H_(5)NH_(2) gt (C_(2)H_(5))_(3)N gt NH_(3)`B. `(C_(2)H_(3))N gt (C_(2)H_(5))_(2)NH gt C_(2)H_(5)NH_(2) gt NH_(3)`C. `(C_(2)H_(2))_(2)NH gt (C_(2)H_(5))_(3)N gt C_(2)H_(5)NH_(2) gt NH_(3)`D. `NH_(3) gt C_(2)H_(5)NH_(2) gt (C_(2)H_(5))_(2)NH gt (C_(2)H_(5))_(3)N`

Answer» Correct Answer - C
In aq. Solution two factors operate simultaneously (i) inductive effect of alkyl group which tends to increase the basic strength and (ii) steric effect of alkyl group which tends to decrease the basic strength The combined effect of the two results in the following order
`NH_(3) lt C_(2)H_(5)NH_(2) lt (C_(2)H_(5))_(3)N lt (C_(2)H_(5))_(2)NH` .
283.

In the given reaction sequence `C_(6)H_(5)-CH_(2)-NH_(2) overset(CHCl_(3)//Alc.KOH)underset(Delta)rarr [X] overset(H_(2)O //NaOH)rarr [Y],[Y]` will be:A. `C_(6)H_(5)-CN`B. `C_(6)H_(5)NC`C. `C_(6)H_(5)-CH_(2)-NH_(2)`D. `C_(6)H_(5)-CH_(2)OH`

Answer» Correct Answer - C
284.

Explain why `MeNH_(2)` is stronger base than `MeOH`?

Answer» Basicity of `MeNH_(2)` and MeOH can be explained on their basis of electronegativity of N and O atom. `MeNH_(2)` is stronger base than MeOH because of low electronegativity value of N, it is easy for nitrogen to loose its lone pair readily than compared to MeOH.
285.

The conversion of an amide by reaction `NaOH` and `Br_(2)` to primary amine that has one carbon than the strating amide is known as Hofmann-Bromoamide reaction. `R-overset(O)overset(||)(C)-NH_(2) overset(Br_(2)+NaOH)underset(or NaOBr)rarr R-NH_(2)+NaBr +Na_(2)CO_(3)` Mechanism: A. B. C. D. all of these

Answer» Correct Answer - A
286.

The conversion of an amide by reaction `NaOH` and `Br_(2)` to primary amine that has one carbon than the strating amide is known as Hofmann-Bromoamide reaction. `R-overset(O)overset(||)(C)-NH_(2) overset(Br_(2)+NaOH)underset(or NaOBr)rarr R-NH_(2)+NaBr +Na_(2)CO_(3)` Mechanism: Number of moles of `NaOH` consumed in above reaction:A. 1B. 2C. 3D. 4

Answer» Correct Answer - D
287.

Choose the correct comparisons of basicity:A. B. C. D.

Answer» Correct Answer - A::B::C
288.

Which of the following order of basicity is correct in aqueous medium?A. `(CH_(3))_(2)NH gt (CH_(3))_(3)N gt CH_(3)NH_(2)`B. `(CH_(3))_(2)NH gt CH_(3)NH_(2) gt (CH_(3))_(3)N`C. `(C_(2)H_(5))_(2)NH gt (C_(2)H_(5))_(3)N gt C_(2)H_(5)NH_(2)`D. `(C_(2)H_(5))_(2)NH gt C_(2)H_(5)NH_(2) gt (C_(2)H_(5))_(3)N`

Answer» Correct Answer - B::C
289.

The conversion of an amide by reaction `NaOH` and `Br_(2)` to primary amine that has one carbon than the strating amide is known as Hofmann-Bromoamide reaction. `R-overset(O)overset(||)(C)-NH_(2) overset(Br_(2)+NaOH)underset(or NaOBr)rarr R-NH_(2)+NaBr +Na_(2)CO_(3)` Mechanism: Find X and Y:A. B. C. D.

Answer» Correct Answer - B
290.

`CH_(3)CH_(2)NH_(2) overset((CH_(3)CO)_(2))underset(Delta) to A+B`, (A) and (B) areA. `CH_(3)CH_(2)NHCOCH_(2) + CH_(3)CH_(2)N-=C`B. `CH_(3)CH_(2)NO_(2) + CH_(3)COOH`C. `CH_(3)CH_(2)NHCOCH_(3)+CH_(3)COOH`D. `CH_(3)CH_(2)NO_(2)+CH_(3)CH_(2)NHCOCH_(3)`

Answer» Correct Answer - C
291.

If `pK_(b)` for the reaction of `MeNH_(2)` in water is `3.4` the `pK_(a)` for the conjugate acid `Meoverset(+)NH_(3)` will the .A. `14//3.4`B. `14+3.4`C. `(14)(3.4)`D. `14-3.4`

Answer» Correct Answer - D
Because
`pK_(a)+pK_(b)=pK_(w)=14 (at 25^(@)C)` .
292.

Which of the following iscorrect ? (a) the conjugate acid of `HO(CH_(2))_(3)NH_(2)` is `H_(2)overset(+)O(CH_(2))_(3)NH_(2)` is (b) The conjugate base of `HO(CH_(2))_(3)NH_(2)` is `barO (CH_(2))_(3)overset(+)underset(+)(N)H_(2)` (C ) The conjugate acid of `HO(CH_(2))_(3)NH_(2)` is `HO(CH_(2))_(3)NH_(2)` (d) The conjugate base of `HO(CH_(2))_(3)NH` .A. (b),(C )B. (a),(b)C. (c ),(d)D. (a),(d)

Answer» Correct Answer - A
Conjugate acid `hArr H^(+)` + conjugate base The conjugate acid of `HO(CH_(2))_(3)NH_(2)` is `HO(CH_(2))_(3) overset(+)NH_(3)` because `NH_(2)` is a more basic site than `oH` The conjugate base of `HO(CH_(2))` is `barO(CH_(2))_(3) NH_(2)` because `H-O` is more acidic than `H-N` .
293.

Give a simple chemical test to distinguish between the following pair of compounds : C6H5 - NH2 and C6H5 - NH - CH3

Answer»

     Add CHCI3 and alc. KOH,C6H5 - NH2 gives foul smell of isocyanide whereas C6H5 - NH - CH3 does not.     

294.

Identify the compound 'B' in the following series of reactions :Ethanenitrile \(\overset{Na/alcohol}{\longrightarrow}\)  'A' \(\overset{NaNO_2/dil.HCI}{\longrightarrow}\) 'B'(a) CH3-CH2-Cl(b) CH3-CH2-NH2(c) CH3-CH2-OH(d) CH3-CH2-CH2-OH

Answer»

Option : (c) CH3-CH2-OH

295.

Triethylamine when treated with nitrous acid gives :(a) an alcohol (b) a nitrosamine (c) a monoacetyl derivative (d) a soluble nitrite salt

Answer»

Option : (d) a soluble nitrite salt

296.

Which of the following does not reduce Tollens reagent .A. `CH_(3)CHO`B. `C_(6)H_(5)NHOH`C. `HCOOH`D. `C_(6)H_(5)NO_(2)`

Answer» Correct Answer - D
Like acetaldehyde and formic acid phenylhydro-oxylamine is a powerful reducing agent Thus it reduces ammonical silver nitrate (Tollens reagent ) and Fehling s solution Nitrobenzene fails to do so .
297.

is aA. Primary amineB. Secondary amineC. Tertiary amineD. Ammonium salt

Answer» Correct Answer - A
298.

The compound having the molecular formula `C_(3)H_(9)N` can representA. TrimethylamineB. n-propylamineC. IsopropylamineD. All the three

Answer» Correct Answer - D
299.

When acetamide is treated with `Br_(2)` and caustic soda, then we getA. Bromoacetic acidB. Acetic acidC. MethylamineD. Ethane

Answer» Correct Answer - C
300.

`-CONH_(2) overset("Reduction")to -CH_(2)NH_(2)` In above reaction hybridisation state of carbon changes fromA. `sp to sp^(2)`B. `sp to sp^(3)`C. `sp^(2) to sp^(3)`D. `sp^(2) to sp`

Answer» Correct Answer - C