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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

101.

A system has a voltage of 15V and it produces a total current of 1300μA. Find the power of system?(a) 0.025W(b) 0.035W(c) 0.0195W(d) 0.045WThe question was posed to me in exam.I'd like to ask this question from Spectrum of Multitone Signal in section Amplitude Modulation of Analog Communications

Answer»

The correct answer is (c) 0.0195W

To EXPLAIN: ELECTRICAL power is the rate at which electrical energy is converted to another FORM, such as MOTION, heat, or an electromagnetic field.

Power, P = 15 x 1300 x 10^-6 = 0.0195W.

102.

Find the number of pulses, if the number of level is 128 in PCM?(a) 3(b) 6(c) 4(d) 7The question was posed to me by my college director while I was bunking the class.The above asked question is from Power Calculation topic in chapter Amplitude Modulation of Analog Communications

Answer» RIGHT choice is (d) 7

Best explanation: A PULSE in signal PROCESSING is a rapid, transient change in the amplitude of a signal from a baseline VALUE to a HIGHER or lower value, followed by a rapid return to the baseline value.

Therefore,

2^n = 128, so n = 7.
103.

Video signals are transmitted through ________(a) Frequency Modulation(b) Amplitude Modulation(c) Pulse Modulation(d) Either frequency or amplitude modulationThis question was posed to me in final exam.My query is from Spectrum of Multitone Signal in portion Amplitude Modulation of Analog Communications

Answer» CORRECT choice is (b) Amplitude Modulation

Easy explanation: Video SIGNALS require a large transmission bandwidth for transmission. So modulation of video signals is possible only by amplitude modulation. It is executed using Vestigial SIDEBAND modulation, where either of the two sidebands is FULLY transmitted and the other sideband is partly transmitted.
104.

What you understand by the term discone antenna?(a) combination of disc and cone(b) combination of disc and cone with a spacing of ʎ/4(c) combination of disc and cone with a spacing of ʎ/2(d) same as a simple antennaThis question was posed to me during an interview for a job.I need to ask this question from Spectrum of Multitone Signal topic in chapter Amplitude Modulation of Analog Communications

Answer»

Correct answer is (a) combination of DISC and cone

Explanation: Discone ANTENNA is a combination of disc and cone. A discone antenna is a version of a biconical antenna in which ONE of the cones is REPLACED by a disc. It is usually mounted vertically, with the disc at the TOP and the cone beneath. It is usually vertically mounted, with disc at top and the cone beneath.

105.

An input resistance of 20 Kῼ causes a noise voltage of 10μV. Suppose two input resistance each of 20 Kῼ are connected in parallel, then find the total noise voltage?(a) 8μV(b) 10μV(c) 20μV(d) 13μVI got this question in unit test.My question is based upon Spectrum of Multitone Signal topic in portion Amplitude Modulation of Analog Communications

Answer»

Right OPTION is (a) 8μV

The EXPLANATION is: Thermal noise is DISTINCT from shotnoise, which CONSISTS of ADDITIONAL current fluctuations that occur when a voltage is applied and a macroscopic current starts to flow.

106.

Modem is combination of both modulator and demodulator.(a) True(b) FalseThis question was posed to me in my homework.I would like to ask this question from Spectrum of Multitone Signal topic in chapter Amplitude Modulation of Analog Communications

Answer»

Right choice is (a) True

Easiest EXPLANATION: A MODEM (modulator-demodulator) is used to modulate one or more message signals USING one or more carrier WAVES on the transmitting side. It also demodulates the RECEIVED encoded signal to get the original information signal.

107.

Any signal and its Hilbert transform are mutually orthogonal.(a) True(b) FalseThe question was posed to me by my college professor while I was bunking the class.My doubt stems from Spectrum of Multitone Signal topic in division Amplitude Modulation of Analog Communications

Answer»

Right CHOICE is (a) True

To ELABORATE: HILBERT Transform of any signal produces a signal which has same amplitude as that of the original signal but suffers a phase-shift of -90 DEGREE. Consider f(t) be any signal and fh(t) is it’s Hilbert transform.

If we integrate both of them under proper boundary conditions, we get 0 which shows that both are mutually PERPENDICULAR i.e.

108.

What Squelch circuit does?(a) helps to receive signals that are useful for the system(b) helps to make channel noise free(c) helps to receive two or more than two signals at once(d) helps to suppress the audio output in the absence of sufficiently strong desired signalI have been asked this question in an international level competition.Query is from Spectrum of Multitone Signal in section Amplitude Modulation of Analog Communications

Answer»

The correct choice is (d) helps to suppress the audio OUTPUT in the ABSENCE of sufficiently strong desired signal

The explanation is: A SQUELCH is a circuit which is a mean to impede, but not destroy a signal. It circuit blocks the output in the absence of sufficiently strong desired signal. It is widely used in two-way RADIOS to suppress the annoying sounds.

109.

Mostly used radio receivers are?(a) pulsed receivers(b) CW receivers(c) TRF receivers(d) super heterodyne receiversI have been asked this question during an online interview.My query is from Spectrum of Multitone Signal in chapter Amplitude Modulation of Analog Communications

Answer»

Correct choice is (d) super heterodyne receivers

The best explanation: SUPERHETERODYNE Receivers are radio receivers that use frequency mixing to convert a received high frequency signal to a fixed lower intermediate frequency which can be PROCESSED more conveniently. It is ALSO the most used receivers. It is used in a variety of applications from broadcast receivers to two-way radio COMMUNICATION links as WELL as many mobile radio communications systems.

110.

Find the step size of a signal with peak to peak amplitude of 4V and is quantized into 64 levels?(a) 32.3 x 10^-3(b) 30.23 x 10^-3(c) 62.5 x 10^-3(d) 53.3 x 10^-3The question was asked in exam.I would like to ask this question from Spectrum of Multitone Signal topic in chapter Amplitude Modulation of Analog Communications

Answer»

Correct answer is (C) 62.5 X 10^-3

Easy EXPLANATION: STEP size is the voltage difference between one digital level (i.e. 0001) and the next one (i.e. 0010 or 0000). Quantization step size is the smallest possible difference in amplitude.

Therefore,

Step size,

111.

If the step size of a system is 0.0625, find its quantization power?(a) 3.25 x 10^-3(b) 3.25 x 10^-4(c) 3.25 x 10^-2(d) 3.25 x 10^-1I have been asked this question in an interview for job.My query is from Spectrum of Multitone Signal topic in division Amplitude Modulation of Analog Communications

Answer»

The correct OPTION is (B) 3.25 x 10^-4

Best explanation: Quantization noise is a model of quantization ERROR introduced by quantization in the ANALOG-to-digital conversion (ADC) in telecommunication systems and signal processing. It is a rounding error between the analog input voltage to the ADC and the OUTPUT digitized value.

Therefore,

112.

The approximate aspect ratio for television is ________(a) 2 : 1(b) 3 : 2(c) 4 : 3(d) 3 : 4I have been asked this question by my school teacher while I was bunking the class.This intriguing question originated from Modulation Using Non-Linear Devices (Balanced Modulator) in division Amplitude Modulation of Analog Communications

Answer»

Right ANSWER is (C) 4 : 3

For EXPLANATION: Aspect ratio is an image projection attribute that describes the PROPORTIONAL relationship between the width of an image and its HEIGHT. The most common video-graphic aspect ratio is 4:3.

113.

What is the use of SSB?(a) It has lesser bandwidth(b) It has large bandwidth(c) It has infinite bandwidth(d) It has zero bandwidthI got this question in class test.Question is taken from Modulation Using Non-Linear Devices (Balanced Modulator) topic in division Amplitude Modulation of Analog Communications

Answer»

The correct OPTION is (a) It has LESSER bandwidth

Explanation: In SSB-SC(Single Side Band Suppressed CARRIER), the carrier is suppressed and either of the UPPER side-band and lower-sideband, are transmitted. This reduces it’s bandwidth to the frequency of the message signal.

114.

Signal to Noise ratio for a hi-fi system is equal to ________(a) 50 dB(b) 100 dB(c) 75 dB(d) 10 dBThe question was asked in a job interview.This key question is from Modulation Using Non-Linear Devices (Balanced Modulator) in section Amplitude Modulation of Analog Communications

Answer»

Correct answer is (a) 50 dB

For explanation: SIGNAL to Noise ratio compares signal power to noise power. It determines how much signal is PRESENT in a transmitted wave compared to PRESENCE of noise. It is generally expressed in decibels(dB). For a hi-fi SYSTEM, it should be EQUAL to 50dB.

115.

Approximate how many times odd and even fields of television system are scanned?(a) 25 times each(b) 50 times each(c) 50 times each but alternately(d) 25 times each but alternatelyI have been asked this question by my college professor while I was bunking the class.My question is based upon Modulation Using Non-Linear Devices (Balanced Modulator) topic in chapter Amplitude Modulation of Analog Communications

Answer»

Correct option is (d) 25 TIMES each but alternately

Easiest explanation: In TELEVISION system in INDIA, each of odd and even fields are scanned 25 times but alternately.

116.

Any signal and its Hilbert transform have same energy density spectrum.(a) True(b) FalseThis question was addressed to me in an interview.My doubt is from Modulation Using Non-Linear Devices (Balanced Modulator) in division Amplitude Modulation of Analog Communications

Answer»

The correct answer is (a) True

The best I can explain: HILBERT transform of a signal results in a signal with same amplitude but a phase SHIFT of -90 degrees. Thus, a signal and it’s Hilbert transform have same amplitude SPECTRUM i.e. they have same energy density spectrum and also correlation spectrum.

117.

If the spectrum of a narrow band noise is symmetrical and it has a power density spectrum 4×10-6. Power density of quadrature component is ________(a) 2 x 10^-6(b) 5 x 10^-6(c) 3 x 10^-6(d) 4 x 10^-6I got this question in homework.The above asked question is from Modulation Using Non-Linear Devices (Balanced Modulator) topic in section Amplitude Modulation of Analog Communications

Answer» CORRECT option is (a) 2 x 10^-6

For explanation: POWER density is the amount of power per unit volume. Quadrature COMPONENT is a amplitude modulated sinusoid which is OFFSET in phase by one QUARTER cycle.

Power density of quadrature component is
118.

What is the capacitive reactance for DC signals?(a) zero(b) very low(c) equal to one(d) infiniteI got this question in class test.Question is from Modulation Using Non-Linear Devices (Balanced Modulator) in portion Amplitude Modulation of Analog Communications

Answer»

The CORRECT answer is (d) infinite

To elaborate: Frequency of DC signals is zero. For zero frequency, CAPACITIVE reactance XC is infinite as XC = 1/(f*C), where f is the frequency and C is the capacitance.

119.

If a FM signal having modulation index mf is passed through a frequency tripler, then the modulation index of output of frequency tripler is ________(a) mf(b) 3mf(c) ^1⁄3 mf(d) ^1⁄9 mfI had been asked this question in an online quiz.My question comes from Modulation Using Non-Linear Devices (Balanced Modulator) in section Amplitude Modulation of Analog Communications

Answer»

Correct choice is (B) 3mf

Explanation: A frequency TRIPLER is a frequency multiplier in which an electronic circuitgenerates an output signal WHOSE output frequency is a harmonic (multiple) of its input frequency. When a FM signal is passed through a frequency tripler, it INCREASES its modulation index 3 times. So the modulation index of output is 3mf.

120.

Beam width of antenna is expressed in ________(a) metres(b) degrees(c) radian(d) voltThis question was posed to me in my homework.My question comes from Modulation Using Non-Linear Devices (Balanced Modulator) topic in chapter Amplitude Modulation of Analog Communications

Answer»

Correct answer is (b) degrees

To explain: ANGULAR separation between the two half-power (-3DB) POINTS is KNOWN as beam width. It is usually EXPRESSED in degrees.

121.

What are the two major drawbacks of delta modulation?(a) Slope Overload and Granular noise(b) Slope Overload and Serration noise(c) Serration noise and Granular noise(d) Slope Overload and Channel NoiseThe question was posed to me by my college professor while I was bunking the class.My doubt stems from Modulation Using Non-Linear Devices (Balanced Modulator) topic in division Amplitude Modulation of Analog Communications

Answer»

The correct ANSWER is (a) Slope Overload and Granular noise

The explanation is: DELTA modulation is an analog-to-digital and digital-to-analog signal conversion technique used for transmission of voice information where quality is not of primary importance. It is the simplest form of differential pulse-code modulation (DPCM) where the difference between SUCCESSIVE samples are ENCODED into n-bit data streams. The two major drawbacks in delta modulation are slope overload and granular noise. When step size becomes too small to track the original waveform it generates an error known as slope overload and granularity occurs when step size is too large.

122.

SWR is 1 for ________(a) Open or Short Circuit(b) Open circuit only(c) Short circuit only(d) Series or Parallel CircuitThis question was addressed to me by my school principal while I was bunking the class.This interesting question is from Generation of AM Using Amplifiers topic in portion Amplitude Modulation of Analog Communications

Answer»

The correct answer is (a) Open or Short Circuit

To EXPLAIN: Standing Wave Ratio (SWR) is defined as the ratio of the maximum radio-frequency (RF) voltage to the MINIMUM RF voltage along the line. If the line is open or short circuited, SWR is always 1.

123.

Consider a wave, v = 15 sin (3πt + 5sin1300t), what is the carrier and signal frequency?(a) 2.5Hz and 200Hz(b) 1.5Hz and 100Hz(c) 1.5Hz and 207Hz(d) 5.5Hz and 500HzThis question was addressed to me in quiz.I would like to ask this question from Generation of AM Using Amplifiers topic in portion Amplitude Modulation of Analog Communications

Answer»

The CORRECT choice is (c) 1.5Hz and 207Hz

For explanation: Comparing with the GENERAL FM EQUATION,

FM(t) = Ac sin(2πfct + βsin(2πfmt)),

Therefore,

Signal and Carrier frequency are RESPECTIVELY

124.

The resonance frequency of an amplifier is 7MHz and it is having a bandwidth of 10KHz. What is its Q factor?(a) 7000(b) 70(c) 700(d) 7The question was asked in an interview for internship.The origin of the question is Generation of AM Using Amplifiers topic in division Amplitude Modulation of Analog Communications

Answer»

The CORRECT CHOICE is (C) 700

Explanation: Q FACTOR = Frequency/Bandwidth

= 7MHz/10KHz = 700.

125.

Which chart is used for calculations of transmission lines?(a) Andre chart(b) Smith chart(c) Wilson chart(d) Federer chartI have been asked this question in an interview.This intriguing question originated from Generation of AM Using Amplifiers topic in chapter Amplitude Modulation of Analog Communications

Answer»

Right option is (B) Smith chart

To explain: Smith chart is highly used in RADIO frequency engineering. Because it is highly USEFUL in solving problems related with TRANSMISSION lines and matching circuits. It is highly useful for DISPLAYING multiple parameters like impedance, admittance etc simultaneously.

126.

Field intensity follows ________(a) Bragg’s law(b) Inverse square law(c) Coulomb’s law(d) Gauss’s lawI have been asked this question in a national level competition.Query is from Generation of AM Using Amplifiers topic in section Amplitude Modulation of Analog Communications

Answer» RIGHT answer is (b) Inverse square law

The explanation is: Strength of an electric field due to a CHARGE Q is inversely proportional to the square of the distance from the SOURCE. In electrostatics, inverse square law is ALSO known as Coulomb’s Law.
127.

What is the effective power if the transmitted power of 5W is increased to 50dB?(a) 100KW(b) 300KW(c) 500KW(d) 700KWThis question was posed to me in an interview.I'm obligated to ask this question of Generation of AM Using Amplifiers topic in chapter Amplitude Modulation of Analog Communications

Answer» CORRECT CHOICE is (c) 500KW

For EXPLANATION I would SAY: According to given problem, 10log10 (P/Pt) = 50,

10log10 (P/5) = 50.

So, P = 500KW.

Where, P = Effective Power, Pt = Transmitted Power.
128.

If the power density at a given distance ‘R’ is one microwatt per square meter and the effective area of antenna is one square meter then the power captured by antenna is one microwatt.(a) True(b) FalseI have been asked this question during a job interview.This intriguing question originated from Generation of AM Using Amplifiers topic in chapter Amplitude Modulation of Analog Communications

Answer»

The CORRECT answer is (a) TRUE

Easiest EXPLANATION: The above STATEMENT is true because power density is EQUAL to

where,

Power Density = 1 mW

Pt = Power captured by antenna,

Area of antenna = 4πR^2 = 1m^2.

129.

The gain of antenna (G) is the ratio of power radiated in a particular direction to the power radiated from an isotropic antenna.(a) True(b) FalseThis question was posed to me at a job interview.The doubt is from Generation of AM Using Amplifiers in chapter Amplitude Modulation of Analog Communications

Answer» RIGHT answer is (a) True

For EXPLANATION I would SAY: Gain of antenna,
130.

EM waves are attenuated as they travel.(a) True(b) FalseI have been asked this question in class test.Origin of the question is Generation of AM Using Amplifiers in division Amplitude Modulation of Analog Communications

Answer»

Correct answer is (a) True

For explanation I would say: ELECTROMAGNETIC radiation can travel through many forms of medium. They travel at the speed of light in air or free space, which are ideal MEDIA. However conductive media like metals form a barrier through which they do not travel. There are also some media through which when they travel, GET attenuated. EM waves are attenuated as they travel because both field and power DECREASE as distance increases.

131.

Effective radiated power (ERP) is equal to ________(a) Pt×Gt×Pd(b) Pt×Pd(c) Gt×Pd(d) Pt×GtI got this question in an online quiz.I would like to ask this question from Envelope Detector in section Amplitude Modulation of Analog Communications

Answer»

The correct choice is (d) Pt×Gt

The explanation: Effective RADIATED Power (ERP) measures the combination of the power emitted by the transmitter and the ability of the antenna to DIRECT that power in a GIVEN direction. Thus, Effective Radiated Power is equal to the PRODUCT of antenna GAIN (Gt) and power transmitted (Pt).

132.

Envelope Detector is a/an ________(a) Coherent detector(b) Asynchronous Detector(c) Synchronous Detector(d) Product DemodulatorThis question was addressed to me in an internship interview.My question is based upon Envelope Detector in division Amplitude Modulation of Analog Communications

Answer» RIGHT choice is (b) ASYNCHRONOUS Detector

Explanation: An envelope detector is used to demodulate a previously modulated signal by removing all high frequency components of the signal. The capacitor and resistor form a low-pass filter to filter out the carrier frequency. Envelope detectors are asynchronous in nature. The advantage of asynchronous over synchronous is that it is simple, CHEAP and SETUP is FASTER.
133.

Power density from an isotropic antenna is equal to ________(a) \(\frac{P_t}{4 \pi R^2}\)(b) \(\frac{P_c}{4 \pi R^2}\)(c) \(\frac{P_t}{2 \pi R^2}\)(d) \(\frac{P_t}{4 \pi R}\)I have been asked this question during an interview.The question is from Envelope Detector topic in section Amplitude Modulation of Analog Communications

Answer»

Right option is (a) \(\frac{P_t}{4 \pi R^2}\)

For EXPLANATION: POWER of a transmitter that is radiated from an isotropic antenna will have a uniform power density in all direction. An isotropic antenna is an ideal antenna that radiates its power UNIFORMLY in all directions. There is no actual physical isotropic antenna. However, an isotropic antenna is often used as a reference antenna for the antenna gain. The power density at any distance ‘R’ for an isotropic antenna is EQUAL to \(\frac{P_t}{4 \pi R^2}\).

134.

Compact discs mainly use ________(a) optical recording(b) magnetic recording(c) magnetic retrieval(d) both optical and magnetic recordingThis question was addressed to me in a job interview.The above asked question is from Envelope Detector in chapter Amplitude Modulation of Analog Communications

Answer»

The correct CHOICE is (a) OPTICAL recording

For explanation I WOULD say: Compact DISK (CD) is mainly used for storage of DATA. It was developed only for store and play only audio but was later adapted for storage of data also. It mainly used optical recording and retrieval.

135.

If the distance between antenna and source doubles, the received signal power decreases by ^1⁄4.(a) True(b) FalseI have been asked this question during an online exam.This key question is from Envelope Detector in chapter Amplitude Modulation of Analog Communications

Answer»

Correct option is (a) True

To ELABORATE: It is due to the R^2 term in formula, . Thus, the RECEIVED signal power is inversely PROPORTIONAL to the distance between antenna and SOURCE.

136.

Power density follows inverse square law.(a) True(b) FalseThis question was posed to me in an international level competition.I need to ask this question from Envelope Detector in division Amplitude Modulation of Analog Communications

Answer» RIGHT choice is (a) True

The best explanation: From the given formula, With increase in DISTANCE, power density decreases. So, we can ALSO SAY that power density is inversely related to distance. Thus, Power density follows inverse square law.
137.

There is no requirement of IF amplifier stages for a video monitor.(a) True(b) FalseThis question was posed to me in exam.Asked question is from Envelope Detector in division Amplitude Modulation of Analog Communications

Answer»

Right OPTION is (a) True

Explanation: IF amplifiers are used to change the frequency levels in CIRCUITS that are too SELECTIVE, difficult to tune, and unstable. However, VIDEO amplifier is used to amplify video signals before passing them to a Cathode ray tube. And there is no need of IF amplifier stages for a video monitor.

138.

Helical antenna is circularly polarized.(a) True(b) FalseI have been asked this question in an interview for job.My doubt is from Envelope Detector in portion Amplitude Modulation of Analog Communications

Answer»

Right choice is (a) True

The BEST I can explain: A helical ANTENNA is an antenna consisting of one or more conducting wires (monofilar, bifilar, or quadrifilar with 1, 2, or 4 wires respectively) wound in the form of a helix. In helical antenna, polarization is equally divided between vertical and horizontal components and thus it is circularly POLARIZED.

139.

The intermediate frequency of a superheterodyne receiver is 500KHz. What is the image frequency at 1200KHz?(a) 600KHz(b) 500KHz(c) 700KHz(d) 200KHzThis question was addressed to me in final exam.This intriguing question comes from Envelope Detector in section Amplitude Modulation of Analog Communications

Answer»

Correct option is (c) 700KHz

To elaborate: The image FREQUENCY is an undesired input frequency which is demodulated by superheterodyne RECEIVERS along with the desired incoming signal. This results in two stations being received at the same time, thus producing interference. In the GIVEN problem, Image frequency is equal to (1200 – 500) which is equal to 700KHz.

140.

Which of these amplifiers is used for impedance matching?(a) Common Base(b) Common Emitter(c) Common Collector(d) Common Base & EmitterThe question was asked during an interview for a job.Asked question is from Envelope Detector in chapter Amplitude Modulation of Analog Communications

Answer» RIGHT choice is (C) Common COLLECTOR

The explanation is: An amplifier is an electronic circuit that is used to amplify the voltage SIGNAL or a current signal. Output impedance of common collector amplifier is LOW and thus it is suitable for impedance matching.
141.

Discone antenna is mainly used in UHF range.(a) True(b) FalseThis question was posed to me during an online exam.I want to ask this question from Linear Modulation in portion Amplitude Modulation of Analog Communications

Answer»

Correct choice is (a) True

To explain: A discone antenna is a version of a biconical antenna in which one of the cones is REPLACED by a disc. It is usually mounted vertically, with the disc at the TOP and the cone beneath. Discone antenna is a combination of disc and cone. Discone antenna is omnidirectional so it is mainly used in UHF range. It is especially used in airports.

142.

Squelch circuit is normally inserted in receiver ________(a) after detector(b) before detector(c) before mixer(d) after power amplifierI got this question during an interview.I'm obligated to ask this question of Linear Modulation topic in portion Amplitude Modulation of Analog Communications

Answer»

Correct answer is (a) after detector

For explanation I would say: Squelch is a circuit that acts to SUPPRESS the audio (or video) OUTPUT of a receiver in the absence of a SUFFICIENTLY strong desired INPUT signal. Squelch is added to suppress NOISE. It is added after detector when there is no carrier.

143.

Each frequency gives rise to four side bands.(a) True(b) FalseThe question was posed to me in a job interview.This interesting question is from Linear Modulation topic in section Amplitude Modulation of Analog Communications

Answer» CORRECT option is (b) False

The best I can explain: Each frequency in communication gives rise to TWO SIDE bands, UPPER SIDEBAND and Lower Sideband.
144.

If the transmitted power is 100KW then the field at a distance ‘R’ is 60mV/m. Suppose if the transmitted power is reduced to 50KW then the field at same distance ‘R’ will be equal to ________(a) 50mV/m(b) 42mV/m(c) 45mV/m(d) 55mV/mThis question was posed to me during an interview.My question is taken from Linear Modulation in chapter Amplitude Modulation of Analog Communications

Answer»

Correct answer is (B) 42mV/m

Best EXPLANATION: SINCE, Field strength (E) is directly PROPORTIONAL to the square root of transmission power i.e. E ∝ √Pt. Thereforewhich gives x = 42mV/m

145.

Field strength (E) is directly proportional to the square of transmission power.(a) True(b) FalseThis question was addressed to me by my college professor while I was bunking the class.The query is from Linear Modulation in portion Amplitude Modulation of Analog Communications

Answer»

Right answer is (b) False

To explain: Field Strength is the intensity of an electric or MAGNETIC field. ACTUALLY the Field strength (E) is directly proportional to the square root of transmission POWER i.e. E ∝ √Pt.

146.

If the value of resistor becomes 16 times than its previous value then its noise voltage will become________(a) 16 times(b) 8 times(c) 4 times(d) 2 timesThis question was addressed to me in an interview for job.This key question is from Linear Modulation topic in division Amplitude Modulation of Analog Communications

Answer» CORRECT choice is (C) 4 TIMES

Easy explanation: Since the noise voltage is directly proportional to square ROOT of RESISTANCE so if the value of resistor increased to 16 times then its noise voltage will become 4 times.
147.

TV remote control used ultra violet light.(a) True(b) FalseThis question was posed to me in unit test.Enquiry is from Linear Modulation topic in chapter Amplitude Modulation of Analog Communications

Answer»

Correct option is (b) False

To elaborate: The infrared (IR) and the ultraviolet(UV) rays represent the two extremities of the visible spectrum (400-700nm). While IR represents electromagnetic RADIATION with WAVELENGTHS longer than those of visible light, UV represents wavelengths shorter than visible light. Each time we press any button of TV REMOTE, it sends a beam of infrared rays. For different commands, it sends out different BEAMS that are detected by a microchip lying INSIDE TV.

148.

What is the modulation index for a single tone modulation, given that positive peak of AM wave is 20V and minimum value is 2V?(a) 0.81(b) 0.91(c) 0.73(d) 1I have been asked this question during an online interview.I want to ask this question from Linear Modulation in section Amplitude Modulation of Analog Communications

Answer» RIGHT ANSWER is (a) 0.81

For EXPLANATION: Modulation Index (U) = (VMAX – Vmin)/(Vmax + Vmin)

= (20-2)/(20+2) = 9/11 = 0.81.
149.

How capacitance is related to thickness?(a) it is inversely proportional to thickness(b) it is directly proportional to thickness(c) it is inversely proportional to twice of thickness(d) it is directly proportional to twice of thicknessI have been asked this question in final exam.My query is from Linear Modulation topic in division Amplitude Modulation of Analog Communications

Answer»

Correct CHOICE is (a) it is INVERSELY proportional to thickness

Best explanation: The thickness of capacitor affects the VALUE of capacitance because capacitance is dependent on structure and distance between TWO plates.

Thus, Capacitance, C = ^A×∈⁄t so it is inversely proportional to thickness.

150.

Noise gets mixed with signal at ________(a) receiver(b) transmitter(c) transducer(d) channelI have been asked this question in my homework.The origin of the question is Linear Modulation in division Amplitude Modulation of Analog Communications

Answer»

The correct answer is (d) channel

Easy explanation: Channel acts as a path for taking SIGNALS to the receiver. It is a medium of transmission of data from SOURCE to DESTINATION. There is a high PROBABILITY of involving noise at the channel.