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151.	A 1000KHz carrier is modulated by 100Hz and 200Hz waves, then which of the following frequencies cannot be present at the output?(a) 1000.1KHz(b) 999.9KHz(c) 1000.2KHz(d) 999.7KHzThe question was posed to me in an online interview.This intriguing question originated from Average Power For Sinusoidal AM in portion Amplitude Modulation of Analog Communications
Answer» CORRECT answer is (d) 999.7KHz For EXPLANATION I would SAY: FREQUENCIES present at OUTPUT will be 1000 ± 0.1 KHz = 1000.1KHZ and 999.9KHz and 1000 ± 0.2 KHz = 1000.2KHZ and 999.8KHz. Therefore, Only, 999.7KHzis out of the range.

152.	Aspect ratio is the ratio of ________(a) width to height(b) height to width(c) power to width(d) width to powerThe question was posed to me in quiz.The doubt is from Average Power For Sinusoidal AM topic in chapter Amplitude Modulation of Analog Communications
Answer» Right choice is (a) width to height Best explanation: Aspect ratio, being one of the crucial ATTRIBUTES in IMAGE projection, DESCRIBES the varying RELATIONSHIP between the width of the image and it’s height. Thus, Aspect ratio is the ratio of width to the height of image (screen).

153.	If the levels in PCM are transmitted in 10 unit code having sampling frequency equals to 20KHz. What is its bandwidth?(a) 150KHz(b) 125KHz(c) 100KHz(d) 110KHzThis question was posed to me in final exam.My doubt is from Average Power For Sinusoidal AM topic in section Amplitude Modulation of Analog Communications
Answer» Right ANSWER is (c) 100KHz To explain I would say: PCM bandwidth is half of Bit rate. Bit Rate = 10 X 20 = 200 Bandwidth = 200/2 = 100 KHZ.

154.	Carrier frequency is given by the formula ________(a) \(\frac{1}{2 \pi \sqrt{LC}}\)(b) \(\frac{1}{2 \pi \sqrt{L}}\)(c) \(\frac{1}{2 \pi \sqrt{C}}\)(d) \(\frac{1}{\pi \sqrt{LC}}\)The question was asked in a national level competition.The doubt is from Average Power For Sinusoidal AM topic in chapter Amplitude Modulation of Analog Communications
Answer» The correct ANSWER is (a) \(\frac{1}{2 \pi \sqrt{LC}}\) EXPLANATION: Carrier wave is a high FREQUENCY signal whose CERTAIN characteristics, like amplitude, phase and frequency, are varied with respect to the instantaneous amplitude of the baseband signal (message signal). This variation is called modulation. Carrier frequency is given by the formula, fc = \(\frac{1}{2 \pi \sqrt{LC}}\) where L is INDUCTANCE and C is Capacitance.

155.	Find the carrier frequency if the inductance and capacitance are 30μH and 10nF respectively?(a) 244KHz(b) 523KHz(c) 290KHZ(d) 300KHzThis question was posed to me by my college director while I was bunking the class.Query is from Average Power For Sinusoidal AM in division Amplitude Modulation of Analog Communications
Answer» Correct option is (c) 290KHZ For explanation I WOULD say: CARRIER frequency is a waveform (usually sinusoidal) that is MODULATED (modified) with an input signal for the purpose of CONVEYING information.

156.	Among all amplifiers, Common Collector has highest power gain.(a) True(b) FalseThis question was addressed to me in unit test.The doubt is from Average Power For Sinusoidal AM in portion Amplitude Modulation of Analog Communications
Answer» Correct CHOICE is (b) False The best explanation: An amplifier is an electronic DEVICE that increases the voltage, current, or power of a signal. Amplifiers are used in wireless communications and broadcasting, and in audio equipment of all kinds.It is common emitter which has HIGHEST power gain. Common emitter has a very high voltage gain and also has good AMOUNT of current, so its power gain is high.

157.	Helical antenna is used to obtain ________ polarization.(a) elliptical(b) circular(c) linear(d) perpendicularI got this question during a job interview.I need to ask this question from Average Power For Sinusoidal AM topic in section Amplitude Modulation of Analog Communications
Answer» The correct option is (B) circular Easy explanation: A helical antenna is an antenna made of one or more conducting wires wound in the form of a HELIX. It PRODUCES circular polarization, because of which it is highly used in RADIO TELEMETRY.

158.	What is number of possible outputs if there is 6 line digital input?(a) 64(b) 32(c) 16(d) 128The question was asked in an interview.My doubt stems from Average Power For Sinusoidal AM in section Amplitude Modulation of Analog Communications
Answer» Correct option is (a) 64 Explanation: TOTAL possible outputs will be 2^n = 2^6 which is EQUAL to 64.

159.	Push pull amplifier is a class B amplifier.(a) True(b) FalseI got this question during an interview.My question is based upon Average Power For Sinusoidal AM topic in chapter Amplitude Modulation of Analog Communications
Answer» Right CHOICE is (a) True Best explanation: A push PULL amplifier is an amplifier which has an output stage that can drive a current in EITHER direction through through the load. Push pull amplifier uses a pair of active devices that alternately SUPPLY current to a connected load and also absorb current from a connected load. It is a class B amplifier.

160.	For removing unwanted signals we should use ________(a) mixing method(b) filter method(c) modulation method(d) detecting methodI got this question in final exam.Origin of the question is Average Power For Sinusoidal AM in division Amplitude Modulation of Analog Communications
Answer» CORRECT OPTION is (b) filter method The explanation: FILTERATION method is used to remove unwanted components from the signal. It is mainly used to eliminate noise.

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