Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

51.

What do you understand by the term “carrier”?(a) waveform with constant frequency, phase and amplitude(b) waveform for which frequency, amplitude or phase is varied(c) waveform with high amplitude, low frequency and constant phase(d) waveform to be transmittedI got this question during an online exam.My question is taken from Detection of AM Waves in section Amplitude Modulation of Analog Communications

Answer»

The correct choice is (b) waveform for which frequency, amplitude or PHASE is varied

The explanation: A carrier wave is modulated in terms of amplitude, frequency or phase, with RESPECT to an input SIGNAL for CONVEYING information. Carrier wave has GENERALLY higher frequency than the input signal.

52.

According to Fourier analysis, square wave can be represented as ________(a) fundamental sine wave and even harmonics(b) fundamental sine wave and odd harmonics(c) fundamental sine wave and harmonics(d) fundamental and sub harmonic sine waveThis question was posed to me during an online interview.The question is from Detection of AM Waves in division Amplitude Modulation of Analog Communications

Answer»

Right choice is (b) fundamental sine WAVE and ODD harmonics

The explanation: A square wave is a non-sinusoidal periodic waveform with STEADY frequency, in which the AMPLITUDE ALTERNATES between a fixed maximum and minimum value. According to Fourier analysis, an ideal square wave, with amplitude one, can be represented as an infinite sum of sinusoidal waves. An ideal square wave contains only components of odd integer harmonics.

53.

Mass of any moving system is represented by ________(a) a resistance(b) a conductance(c) a resistivity(d) an inductanceI had been asked this question in my homework.This intriguing question comes from Detection of AM Waves topic in section Amplitude Modulation of Analog Communications

Answer» CORRECT option is (d) an inductance

To elaborate: Inductance can also be seen as ELECTROMAGNETIC inertia, a property that opposes changes in ELECTRIC currents and magnetic FIELDS. Mass has inertia so it is represented by an inductance.
54.

Contrast function in TV is done by ________(a) Luminance amplifier(b) Schmitt trigger(c) Band Pass Filter(d) Chroma amplifierI had been asked this question at a job interview.The doubt is from Detection of AM Waves in division Amplitude Modulation of Analog Communications

Answer»

The correct choice is (a) Luminance amplifier

To explain I would SAY: Luminance amplifier is mostly used by the Contrast Function, in TV sets. It helps to changes the contrast or picture quality of television with respect to the received VISUAL SIGNALS, by MAKING the contrast optimum.

55.

Bandwidth of RF amplifier for a color TV receiver is ________(a) equal to channel width(b) more than channel width(c) less than channel width(d) twice of channel widthThe question was asked in quiz.This is a very interesting question from Detection of AM Waves in section Amplitude Modulation of Analog Communications

Answer» RIGHT answer is (b) more than channel width

Easiest explanation: RF AMPLIFIERS are tuned amplifiers in which the frequency of OPERATION is controlled by a tuned CIRCUIT. BANDWIDTH of RF amplifier is generally kept a little more than channel so that there is no problem in reception.
56.

FSK system involves ________(a) frequency modulation(b) pulse modulation(c) amplitude modulation(d) phase modulationI got this question in unit test.The above asked question is from Detection of AM Waves topic in portion Amplitude Modulation of Analog Communications

Answer»

Correct option is (a) frequency MODULATION

The explanation is: FSK (Frequency Shift Keying) is a method to transmit DIGITAL signals, which are in form of BINARY DATA. FSK i.e. Frequency Shift Keying involves frequency modulation that assigns bit values to discrete frequency while ASK assigns bit values to discrete AMPLITUDE.

57.

Diameter of antenna is doubled. The maximum range will ________(a) be doubled(b) be halved(c) become four times(d) decrease to one fourthThis question was addressed to me in exam.My question comes from Detection of AM Waves in chapter Amplitude Modulation of Analog Communications

Answer»

The correct OPTION is (a) be doubled

To EXPLAIN I would SAY: Range of antenna is DIRECTLY proportional to antenna diameter. So if diameter of antenna is doubled its range ALSO doubled.

58.

If the modulating frequency of a carrier wave varies between 700Hz and 7KHz, find it’s bandwidth?(a) 10 KHz(b) 23 KHz(c) 17.3 KHz(d) 12.6 KHzThis question was addressed to me by my college professor while I was bunking the class.This question is from Problems of AM in division Amplitude Modulation of Analog Communications

Answer»

The correct answer is (d) 12.6 KHz

To ELABORATE: MODULATING FREQUENCY (fm) = Vmax-Vmin, where,

Vmax = Maximum Amplitude of an amplitude modulated,

Vmin = Minimum amplitudeof an amplitude modulated,

fm = 7KHZ – 700Hz = 6.3KHz

Bandwidth = 2fm = 2 X 6.3 = 12.6 KHz.

59.

A 400W carrier wave is modulated to a depth of 65%. Find the total power of modulated wave?(a) 512.5W(b) 493W(c) 484.5W(d) 609.6WI got this question in an internship interview.This question is from Problems of AM in division Amplitude Modulation of Analog Communications

Answer» RIGHT answer is (c) 484.5W

Explanation: TOTAL power,Pt = PC (1 + ^µ^2⁄2),where Pc = Carrier Power = 400W

where MODULATION Index (µ) = 0.65,

 so Pt = 400 (1 +^0.65^2⁄2). On solving it we get Pt = 484.5W.
60.

Inductance and capacitance of a line is 0.8 ^μH⁄m and 32 ^pF⁄m. FindZ0?(a) 158(b) 166(c) 143(d) 127I got this question in class test.My query is from Problems of AM in chapter Amplitude Modulation of Analog Communications

Answer»

The correct CHOICE is (a) 158

To explain: The characteristic impedance or surge impedance (Z0) of a uniform TRANSMISSION line is the RATIO of the AMPLITUDES of voltage and current of a single wave propagating along the line; which is, a wave travelling in one direction in the absence of reflections in the other direction.

.

61.

Find VSWR of a line having maximum and minimum value equals to 120mV and 40mV respectively?(a) 3(b) 2(c) 1(d) 4I have been asked this question in semester exam.The origin of the question is Problems of AM topic in chapter Amplitude Modulation of Analog Communications

Answer»

Right choice is (a) 3

Easy explanation: The voltage standing wave ratio (VSWR) is defined as the ratio of the maximum to minimum voltage on a loss-less LINE. In this way, the VSWR is measured at a particular point and the voltage MAXIMA and MINIMA do not need to be determined along the length of the line.

62.

A 1000 KHz carrier is modulated with 300 Hz, 8000 Hz and 2 KHz waves. Determine the frequencies whose chances of occurring in output is least?(a) 1000 KHz(b) 1002 KHz(c) 998 KHz(d) 999.2 KHzI had been asked this question by my college director while I was bunking the class.The query is from Problems of AM topic in division Amplitude Modulation of Analog Communications

Answer»

The CORRECT answer is (a) 1000 KHz

Best EXPLANATION: Frequencies present in output are of the form FC ± fm, fc ± 2fm, fc ± 3fm. And 1000 KHz is a MULTIPLE of NONE in the range. Whereas, rest options are one of the multiples in the range.

63.

If average power of a transmitter is 4kW and maximum power is 20000KW. What is its duty cycle?(a) 2 x 10^-3(b) 2 x 10^-4(c) 3 x 10^-3(d) 0.05I have been asked this question during an interview.Question is from Problems of AM topic in division Amplitude Modulation of Analog Communications

Answer»

Correct ANSWER is (B) 2 x 10^-4

Explanation: Duty cycle is the PROPORTION of TIME during which a component, device, or system is operated. The duty cycle can be expressed as a ratio or as a percentage.

64.

Frequency difference between WDM (Wavelength Division Multiplexing) and FDM (Frequency Division Multiplexing) is ________(a) 1(b) 0(c) slightly greater than 1(d) infinityThe question was posed to me during an online interview.My question is taken from FDM System topic in chapter Amplitude Modulation of Analog Communications

Answer»

The correct answer is (d) INFINITY

The explanation is: WDM (WAVE Division Multiplexing) is partly similar to FDM (Frequency Division Multiplexing). FDM is USED for signal TRANSMISSION through a twisted-pair cable while WDM is used to transmit signals through optical fiber cables. Frequency difference between WDM and FDM is infinity.

65.

The voltage and electric current of a line are respectively 5kV and 1000μA. Find its power?(a) 12W(b) 13W(c) 5W(d) 10WI got this question in homework.My question is based upon Problems of AM topic in portion Amplitude Modulation of Analog Communications

Answer»

The correct option is (c) 5W

The best I can explain: Electrical power is the RATE at which electrical energy is CONVERTED to another FORM, such as motion, heat, or an electromagnetic field.

Power, P = V x I. By SUBSTITUTING the values of voltage(V) and current(I), we have P = (5×10^3)(1000×10^-6) = 5W.

66.

If modulation index of an AM wave is increased from 1.5 to 2, then the transitted power ________(a) remains same(b) increases by 20%(c) increases by 41%(d) increases by 50%I have been asked this question in exam.My question is from Problems of AM in portion Amplitude Modulation of Analog Communications

Answer» RIGHT CHOICE is (c) INCREASES by 41%

To explain I would say: When m=1.5, transmitted power

.

= 0.41 X 100

= 41%

Therefore,there is an increase in total power by 41%.
67.

________ microphones works on piezoelectric effect.(a) Crystal(b) Carbon(c) Moving coil(d) CondenserThis question was posed to me in examination.I'm obligated to ask this question of Problems of AM topic in section Amplitude Modulation of Analog Communications

Answer»

The correct answer is (a) Crystal

The explanation: Piezoelectric effect is the ability of MATERIALS to generate an electric CHARGE in response to applied mechanical stress. Crystals which DEMONSTRATE the piezoelectric effect produce voltages when they are deformed. The crystal microphone uses a thin strip of piezoelectric material attached to a diaphragm. The two SIDES of the crystal ACQUIRE opposite charges when the crystal is deflected by the diaphragm.

68.

FDM stands for ________(a) Frequency Density Multiplexing(b) Frequency Difference Multiplexing(c) Frequency Division Multiplexing(d) Frequency Data ManagerThe question was posed to me in a national level competition.Enquiry is from FDM System in division Amplitude Modulation of Analog Communications

Answer» CORRECT answer is (C) Frequency Division Multiplexing

Easy EXPLANATION: FDM stands for Frequency Division Multiplexing. The total bandwidth is divided into a series of non-overlapping frequency bands and each BAND is used to carry a separate SIGNAL.
69.

TDM stands for ________(a) Time Division Multiplexing(b) Time Difference Multiplexing(c) Time Duration Multiplexing(d) Time Data ManagerThis question was addressed to me in exam.This is a very interesting question from FDM System topic in division Amplitude Modulation of Analog Communications

Answer»

The correct choice is (a) TIME DIVISION MULTIPLEXING

For explanation I would say: TDM stands for Time Division Multiplexing. It is used to transmit and receive independent signals over a common signal PATH with the help of synchronized switches.

70.

TDM and FDM are used to multiplex multiple signals into a single carrier.(a) False(b) TrueThis question was posed to me in a job interview.The above asked question is from FDM System topic in chapter Amplitude Modulation of Analog Communications

Answer»

Right answer is (b) True

For explanation: Multiplexing is the method of COMBINING two or more than two signals into one, in such a WAY that each individual signal can be retrieved at the receiver. Both TDM and FDM are used to multiplex DIFFERENT signals into a single carrier. However, TDM is used to transmit and RECEIVE independent signals over a common signal path with the help of synchronized switches. WHEREAS, in case of FDM, the total bandwidth is divided into a series of non-overlapping frequency bands and each band is used to carry a separate signal.

71.

What is Synchronous TDM?(a) gives same amount of time to each device(b) gives same amount of frequency to each device(c) gives variable time to each device(d) gives variable frequency to each deviceI have been asked this question in an online quiz.Origin of the question is FDM System in chapter Amplitude Modulation of Analog Communications

Answer»

The CORRECT option is (a) GIVES same AMOUNT of time to each device

For explanation: TDM is a method of putting multiple data streams in a single signal by separating the signal into many segments, each having a very short duration. Each individual data stream is reassembled at the receiving end based on the timing. Synchronous TDM gives EXACTLY the same amount of time to each connected device. It allocates time to every device EVEN if a device has nothing to transmit.

72.

FDM is an analog multiplexing technique used to combines ________(a) analog signals(b) digital signals(c) both analog and digital signals(d) alternatively passes analog and digital signalsI got this question during an interview for a job.This interesting question is from FDM System topic in portion Amplitude Modulation of Analog Communications

Answer»

Right choice is (a) analog signals

The explanation: Frequency Division Multiplexing (FDM) is a networking TECHNIQUE in which MULTIPLE data signals are combined for simultaneous transmission VIA a shared communication medium. FDM uses a carrier SIGNAL at a discrete frequency for each data stream and then combines many modulated signals. FDM is used to multiplex multiple analog signals. FDM is APPLIED when the bandwidth of the link is greater than the combined bandwidth of signals to be transmitted.

73.

Frequency Division Multiplexing (FDM) is based on orthogonality.(a) True(b) FalseThe question was asked by my college director while I was bunking the class.Question is taken from FDM System in portion Amplitude Modulation of Analog Communications

Answer»

Right choice is (a) True

The best explanation: Frequency Division Multiplexing (FDM) is a networking technique in which multiple data signals are COMBINED for SIMULTANEOUS transmission via a shared communication medium. FDM uses a carrier signal at a discrete frequency for each data stream and then combines many MODULATED signals. Orthogonal frequency division multiplexing is used to encode multiple carrier frequencies. It is mainly used for latest WIRELESS telecommunications.

74.

Which multiplexing technique transmits digital signals?(a) FDM(b) TDM(c) WDM(d) Both FDM and TDMI got this question in quiz.I'm obligated to ask this question of FDM System in chapter Amplitude Modulation of Analog Communications

Answer»

Correct choice is (b) TDM

The best explanation: Time Division Multiplexing is used to transmit DIGITAL signals. FDM and WDM techniques are used to transfer analog signals. WDM (Wave Division Multiplexing) is PARTLY similar to FDM (Frequency Division Multiplexing). FDM is used for SIGNAL transmission through a twisted-pair CABLE while WDM is used to transmit signals through optical fiber cables.

75.

Time Division Multiplexing (TDM) is based on orthogonality.(a) True(b) FalseI had been asked this question in homework.Question is from FDM System in division Amplitude Modulation of Analog Communications

Answer»

Right CHOICE is (a) True

To elaborate: Both Frequency Division Multiplexing (FDM) and TIME Division Multiplexing (TDM) are based on orthogonal multiplexing.Orthogonal multiplexing is a method of encoding digital data on MULTIPLE carrier frequencies.

76.

To get constant time delay, we should use ________(a) FDM technique(b) WDM technique(c) Synchronous TDM(d) Non synchronous TDMI have been asked this question in an online interview.My question is taken from FDM System topic in chapter Amplitude Modulation of Analog Communications

Answer»

The CORRECT answer is (c) Synchronous TDM

The explanation is: TDM is a method of allowing multiple data streams in a single signal by separating the signal into many segments, each having a very short duration. Each INDIVIDUAL data stream is reassembled at the receiving end based on the timing. Synchronous TDM gives exactly the same amount of time to each connected device. It allocates time to every device even if a device has nothing to transmit. Thus, Synchronous Time Division Multiplexing is used to provide constant time DELAY. It can ALSO provide constant bandwidth.

77.

As distance increases ________(a) Packet size also increases(b) Packet size decreases(c) Packet size becomes twice of its previous value(d) Packet size becomes halfThis question was addressed to me in semester exam.Asked question is from FDM System topic in chapter Amplitude Modulation of Analog Communications

Answer»

Right option is (a) PACKET SIZE ALSO increases

Explanation: DISTANCE is directly proportional to packet size. So as distance increases packet size also increases.

78.

If 32 equally probable events exists and we have to select one of them, number of required bits is?(a) 2(b) 4(c) 8(d) 5I had been asked this question in exam.My question is taken from FDM System in section Amplitude Modulation of Analog Communications

Answer» CORRECT answer is (d) 5

Explanation: 2^5 = 32, so number of bits REQUIRED is 5.
79.

Quantization error occurs in ________(a) Time Division Multiplexing(b) Frequency Division Multiplexing(c) Pulse Code Modulation(d) Pulse Width ModulationThis question was addressed to me during a job interview.This intriguing question comes from Methods of Reducing Distortion in chapter Amplitude Modulation of Analog Communications

Answer»

The correct answer is (C) Pulse Code Modulation

Explanation: The difference between an input VALUE and its quantized value is called quantization error or we can also see it as that when an ANALOG number is not CONVERTED into an exact digital number. It takes place in pulse code modulation (PCM). Pulse Code Modulation is a TECHNIQUE in which the amplitude of an analog signal is converted to a binary value represented as a series of pulses.

80.

If power transmitted is 90kW, what is the field at a distance of 45km?(a) 2(b) 1(c) 0.036(d) 0.01The question was posed to me in unit test.This is a very interesting question from Methods of Reducing Distortion in section Amplitude Modulation of Analog Communications

Answer»

The correct choice is (C) 0.036

Best explanation: ELECTRIC Field a region AROUND a charged PARTICLE or object WITHIN which a force would be exerted on other charged particles or objects.

81.

Find the number of pulses, if the number of quantization levels is 32 in PCM?(a) 3(b) 6(c) 4(d) 5This question was addressed to me in an international level competition.Question is taken from Methods of Reducing Distortion in section Amplitude Modulation of Analog Communications

Answer»

The correct option is (d) 5

Explanation: Quantization is a process in which the continuous range of VALUES of an analog signal is sampled and DIVIDED into non-overlapping (but not necessarily equal) subranges, and a DISCRETE, unique value is assigned to each sub-range.

Therefore, number of PULSE in quantisation level =2^n = 32, so n = 5, where n = Quantization Level.

82.

Which transistor amplifier is most commonly used?(a) Common Base(b) Common Emitter(c) Common Collector(d) None of theseThis question was posed to me during an interview for a job.This question is from Methods of Reducing Distortion topic in chapter Amplitude Modulation of Analog Communications

Answer»

Right choice is (B) Common Emitter

The explanation: Common Emitter is most widely used because it has high POWER gain and voltage gain. In this method of connection, small changes in base/emitter CURRENT CAUSE large changes in collector/emitter current. Therefore, the circuit is that of a current amplifier. Moreover, it also provides maximum transconductance for a given load.

83.

A device uses a 8 bit word then the maximum number of words it can transmit is ________(a) 64(b) 256(c) 1024(d) 512This question was addressed to me during an online interview.Asked question is from Methods of Reducing Distortion in section Amplitude Modulation of Analog Communications

Answer» RIGHT choice is (B) 256

Explanation: MAXIMUM number of WORDS which an n-bit device can transmit = 2^n

Therefore, when n = 8,

Number of words it can transmit is 2^8 = 256.
84.

Peak voltage of a carrier is 8kV, each sideband has an amplitude of 800V. Find its modulation index?(a) 0.28(b) 0.09(c) 0.02(d) 0.08I had been asked this question during an internship interview.My question is from Methods of Reducing Distortion in division Amplitude Modulation of Analog Communications

Answer»

The correct answer is (c) 0.02

To elaborate: (mPc)/2 = Psb, wherem = Modulation Index, Pc = Carrier POWER and,

Psb = Power of each sideband

THEREFORE, (mVc ^2)/2 = Vsb 2^2 (Vc= 8000 V, and Vsb = 800)

Therefore, m = (800^2 X 2) / 8000^2 = 0.02.

85.

What do you understand by the term Cross talk?(a) generation of closely lying sidebands(b) a method of increasing bandwidth(c) a method of decreasing bandwidth by converting DSB-SC signal to SSB-SC(d) disturbance caused in nearby circuit due to transmitted signalThis question was addressed to me in exam.I'm obligated to ask this question of Methods of Reducing Distortion in chapter Amplitude Modulation of Analog Communications

Answer»

Right answer is (d) disturbance CAUSED in nearby circuit due to transmitted signal

The explanation is: Crosstalk is a disturbance caused by the ELECTRIC or MAGNETIC fields of one telecommunication signal affecting a signal in an adjacent circuit. It is generally caused by undesired COUPLING. In a TELEPHONE circuit, crosstalk can result in the hearing part of a voice conversation from another circuit.

86.

Which modulation technique uses minimum bandwidth?(a) DSB-SC(b) SSB-SC(c) FM(d) VSBI have been asked this question during an internship interview.My question comes from Methods of Reducing Distortion topic in division Amplitude Modulation of Analog Communications

Answer»

The CORRECT answer is (b) SSB-SC

To EXPLAIN I would SAY: SSB-SC modulation technique uses minimum BANDWIDTH as it suppresses the carrier and transmits either of the two side-bands while DSB-SC suppresses the carrier and transmits both the side-bands.

87.

AM waves is represented by Et cos ⁡ωc t. What does Etdenotes?(a) envelope(b) carrier signal(c) modulating signal(d) amplitudeThe question was posed to me by my school principal while I was bunking the class.I need to ask this question from Methods of Reducing Distortion topic in division Amplitude Modulation of Analog Communications

Answer»

Right CHOICE is (a) envelope

The EXPLANATION: AM wave is represented by (A + XT)cos⁡ωc t or Etcos⁡ωc t, where xt is modulating SIGNAL, A is amplitude and therefore, Et is the envelope of the AM wave.

88.

Wireless communication takes place through ________(a) EM waves(b) X-Rays(c) Optical Fibres(d) Infrared WavesThis question was posed to me in an interview for job.Question is taken from Methods of Reducing Distortion topic in division Amplitude Modulation of Analog Communications

Answer» CORRECT option is (a) EM WAVES

Explanation: Wireless COMMUNICATION takes PLACE through electromagnetic waves. Waves are transmitted through an antenna.
89.

If peak voltage of a carrier wave is 10V, what is the peak voltage of modulating signal if modulation index is 50%?(a) 10V(b) 20V(c) 8V(d) 5VI have been asked this question in an internship interview.Enquiry is from Power Calculation topic in portion Amplitude Modulation of Analog Communications

Answer» RIGHT OPTION is (d) 5V

Best explanation: From the relation, Modulation Index (µ) = Vm/Vc = 50% = 0.5,

where Vm = Peak voltage of modulating signal,

 Vc = Peak voltage of a carrier wave = 10V,

Therefore, Vm = 10 X 0.5 = 5V.
90.

Maximum Amplitude of an amplitude modulated 10V and minimum amplitude is 5V. Find its modulation index?(a) 0.65(b) 0.9(c) 0.33(d) 1This question was posed to me during a job interview.My question is taken from Power Calculation topic in division Amplitude Modulation of Analog Communications

Answer»

Correct CHOICE is (C) 0.33

Explanation: We know, Modulation INDEX(µ) = (Vmax-Vmin)/(Vmax+Vmin),

Where, Vmax = Maximum Amplitude of an amplitude MODULATED = 10V

Vmin = Minimum amplitudeof an amplitude modulated = 5V

Therefore, µ = (10-5)/(10+5) = 0.33.

91.

Sampling frequency of a signal is 6 KHz and is quantized using 7 bit quantizer. Find its bit rate?(a) 48kbPs(b) 64kbPs(c) 16kbPs(d) 8kbPsI got this question in an interview for job.I need to ask this question from Power Calculation in section Amplitude Modulation of Analog Communications

Answer»

Right choice is (a) 48kbPs

For EXPLANATION I WOULD say: Bit RATE refers to the rate at which data is processed or transferred. It is USUALLY measured in SECONDS, ranging from bps for smaller values to kbps and mbps.

Bit rate is also known as bitrate or data rate.

Bit rate, Rb = ^1⁄Tbwherewhere n = number of bits and fs = Sampling Frequency

Tb = 1/42, therefore Bit rate = 42 Kbps.

92.

24 channels, each band limited to 3.4 KHz, are to be time division multiplexed. Find the bandwidth required for 128 quantization level?(Given that sampling frequency is 8 KHz)(a) 2436 KHz(b) 1002 KHz(c) 1536 KHz(d) 1337 KHzThis question was posed to me in homework.Origin of the question is Power Calculation in division Amplitude Modulation of Analog Communications

Answer»

Right CHOICE is (c) 1536 KHz

The best EXPLANATION: N = 24, fm = 3.4 kHz

m = 128,

2^n = m = 128, n = 7

But fs = 2FM, where, fs = samplingfrequency

instead at 2fm2 x 3.4 kHz6.8 KHz.

B.W. = N(n+1)X fs= [24(7 + 1)] 8 kHz = 1536 KHz.

93.

Calculate power in each sideband, if power of carrier wave is 96W and there is 40% modulation in amplitude modulated signal?(a) 11.84W(b) 6.84W(c) 3.84W(d) 15.84WI had been asked this question in quiz.The above asked question is from Power Calculation topic in chapter Amplitude Modulation of Analog Communications

Answer»

Right option is (c) 3.84W

The EXPLANATION is: MODULATION index = 0.4 and Pc = 96W. POWER in sidebands may be CALCULATED as

94.

For 50% modulation, power in each sideband is ________ of that of carrier.(a) 10%(b) 4.32%(c) 5%(d) 6.25%I got this question by my college director while I was bunking the class.Query is from Power Calculation in division Amplitude Modulation of Analog Communications

Answer»

The CORRECT answer is (d) 6.25%

Explanation: MODULATION index = 0.5. POWER in sidebands MAY be CALCULATED as

95.

For 100% modulation, total power is ________(a) 1.5Pc(b) 2Pc(c) 3.75Pc(d) 1.25PcI got this question during an interview for a job.The question is from Power Calculation in portion Amplitude Modulation of Analog Communications

Answer»

The CORRECT choice is (a) 1.5Pc

The explanation: Total power, Pt = Pc (1 + ^µ^2⁄2),where Pc = CARRIER Power

where µ = 1 (for 100% modulation),

 so Pt = Pc(1 +(1^2/2)). On SOLVING it we GET Pt = 1.5Pc.

96.

If each element of signal occupies 70ms, what will its speed?(a) 11.23 bauds(b) 14.28 bauds(c) 17.39 bauds(d) 13.33 baudsThis question was posed to me in an interview for internship.This intriguing question comes from Power Calculation topic in section Amplitude Modulation of Analog Communications

Answer»

Right choice is (B) 14.28 bauds

To elaborate: The carrier SIGNAL is characterized by the number of signal intervals, or PULSES, that are transmitted per second. Each pulse is called a BAUD. BPS stands for bits per second. Bps is a measure of how many bits can be transmitted during one pulse (one baud).

97.

If a wave is modulated by two waves. One of them has modulation index equal to 0.75 and other has 0.2, the total modulation index will be ________(a) 0.67(b) 0.58(c) 0.77(d) 0.35I have been asked this question in a national level competition.Asked question is from Power Calculation topic in division Amplitude Modulation of Analog Communications

Answer»

The correct OPTION is (c) 0.77

Explanation: GIVEN that m1 = 0.75 and M2 = 0.2. Total MODULATION index will be equal toBy SUBSTITUTING values we havewhich is equal to 0.77.

98.

Power of carrier wave is 300W and modulation index is 0.75. Find its total power?(a) 465W(b) 384W(c) 323W(d) 502WI have been asked this question in quiz.The question is from Power Calculation topic in chapter Amplitude Modulation of Analog Communications

Answer»

Correct choice is (b) 384W

Explanation: TOTAL POWER, Pt = PC (1 + ^µ^2⁄2),where Pc = Carrier Power = 300W

where Modulation INDEX (µ) = 0.75,

So Pt,

99.

Find the power saving for DSB-SC wave with 100% modulation?(a) 66%(b) 86%(c) 50%(d) 33%I had been asked this question during a job interview.Query is from Power Calculation in section Amplitude Modulation of Analog Communications

Answer»

Correct OPTION is (a) 66%

To explain I would say: In DSB-SC CARRIER is suppressed.

So Total Power required in DSBSC Modulation = (u^2XPc)/2 = Pc/2

In NORMAL AM, carrier is not suppressed.

So total power required in AM Modulation = (1+(u^2/2))XPc = 3Pc/2

Therefore, Power saving = ((Pc/2)/(3Pc/2)) x 100% = 66%.

100.

If power transmitted is 45kW, field at a distance of 23km will be ________(a) 0.02(b) 0.75(c) 0.05(d) 0.03The question was asked in an online interview.I'm obligated to ask this question of Power Calculation topic in portion Amplitude Modulation of Analog Communications

Answer»

Right answer is (c) 0.05

To elaborate: Field is a REGION around a charged particle or OBJECT within which a force WOULD be EXERTED on other charged particles or objects.