

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
51. |
What do you understand by the term “carrier”?(a) waveform with constant frequency, phase and amplitude(b) waveform for which frequency, amplitude or phase is varied(c) waveform with high amplitude, low frequency and constant phase(d) waveform to be transmittedI got this question during an online exam.My question is taken from Detection of AM Waves in section Amplitude Modulation of Analog Communications |
Answer» The correct choice is (b) waveform for which frequency, amplitude or PHASE is varied |
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52. |
According to Fourier analysis, square wave can be represented as ________(a) fundamental sine wave and even harmonics(b) fundamental sine wave and odd harmonics(c) fundamental sine wave and harmonics(d) fundamental and sub harmonic sine waveThis question was posed to me during an online interview.The question is from Detection of AM Waves in division Amplitude Modulation of Analog Communications |
Answer» Right choice is (b) fundamental sine WAVE and ODD harmonics |
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53. |
Mass of any moving system is represented by ________(a) a resistance(b) a conductance(c) a resistivity(d) an inductanceI had been asked this question in my homework.This intriguing question comes from Detection of AM Waves topic in section Amplitude Modulation of Analog Communications |
Answer» CORRECT option is (d) an inductance To elaborate: Inductance can also be seen as ELECTROMAGNETIC inertia, a property that opposes changes in ELECTRIC currents and magnetic FIELDS. Mass has inertia so it is represented by an inductance. |
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54. |
Contrast function in TV is done by ________(a) Luminance amplifier(b) Schmitt trigger(c) Band Pass Filter(d) Chroma amplifierI had been asked this question at a job interview.The doubt is from Detection of AM Waves in division Amplitude Modulation of Analog Communications |
Answer» The correct choice is (a) Luminance amplifier |
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55. |
Bandwidth of RF amplifier for a color TV receiver is ________(a) equal to channel width(b) more than channel width(c) less than channel width(d) twice of channel widthThe question was asked in quiz.This is a very interesting question from Detection of AM Waves in section Amplitude Modulation of Analog Communications |
Answer» RIGHT answer is (b) more than channel width Easiest explanation: RF AMPLIFIERS are tuned amplifiers in which the frequency of OPERATION is controlled by a tuned CIRCUIT. BANDWIDTH of RF amplifier is generally kept a little more than channel so that there is no problem in reception. |
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56. |
FSK system involves ________(a) frequency modulation(b) pulse modulation(c) amplitude modulation(d) phase modulationI got this question in unit test.The above asked question is from Detection of AM Waves topic in portion Amplitude Modulation of Analog Communications |
Answer» Correct option is (a) frequency MODULATION |
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57. |
Diameter of antenna is doubled. The maximum range will ________(a) be doubled(b) be halved(c) become four times(d) decrease to one fourthThis question was addressed to me in exam.My question comes from Detection of AM Waves in chapter Amplitude Modulation of Analog Communications |
Answer» The correct OPTION is (a) be doubled |
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58. |
If the modulating frequency of a carrier wave varies between 700Hz and 7KHz, find it’s bandwidth?(a) 10 KHz(b) 23 KHz(c) 17.3 KHz(d) 12.6 KHzThis question was addressed to me by my college professor while I was bunking the class.This question is from Problems of AM in division Amplitude Modulation of Analog Communications |
Answer» The correct answer is (d) 12.6 KHz |
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59. |
A 400W carrier wave is modulated to a depth of 65%. Find the total power of modulated wave?(a) 512.5W(b) 493W(c) 484.5W(d) 609.6WI got this question in an internship interview.This question is from Problems of AM in division Amplitude Modulation of Analog Communications |
Answer» RIGHT answer is (c) 484.5W Explanation: TOTAL power,Pt = PC (1 + ^µ^2⁄2),where Pc = Carrier Power = 400W where MODULATION Index (µ) = 0.65, so Pt = 400 (1 +^0.65^2⁄2). On solving it we get Pt = 484.5W. |
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60. |
Inductance and capacitance of a line is 0.8 ^μH⁄m and 32 ^pF⁄m. FindZ0?(a) 158(b) 166(c) 143(d) 127I got this question in class test.My query is from Problems of AM in chapter Amplitude Modulation of Analog Communications |
Answer» The correct CHOICE is (a) 158 |
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61. |
Find VSWR of a line having maximum and minimum value equals to 120mV and 40mV respectively?(a) 3(b) 2(c) 1(d) 4I have been asked this question in semester exam.The origin of the question is Problems of AM topic in chapter Amplitude Modulation of Analog Communications |
Answer» Right choice is (a) 3 |
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62. |
A 1000 KHz carrier is modulated with 300 Hz, 8000 Hz and 2 KHz waves. Determine the frequencies whose chances of occurring in output is least?(a) 1000 KHz(b) 1002 KHz(c) 998 KHz(d) 999.2 KHzI had been asked this question by my college director while I was bunking the class.The query is from Problems of AM topic in division Amplitude Modulation of Analog Communications |
Answer» The CORRECT answer is (a) 1000 KHz |
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63. |
If average power of a transmitter is 4kW and maximum power is 20000KW. What is its duty cycle?(a) 2 x 10^-3(b) 2 x 10^-4(c) 3 x 10^-3(d) 0.05I have been asked this question during an interview.Question is from Problems of AM topic in division Amplitude Modulation of Analog Communications |
Answer» Correct ANSWER is (B) 2 x 10^-4 |
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64. |
Frequency difference between WDM (Wavelength Division Multiplexing) and FDM (Frequency Division Multiplexing) is ________(a) 1(b) 0(c) slightly greater than 1(d) infinityThe question was posed to me during an online interview.My question is taken from FDM System topic in chapter Amplitude Modulation of Analog Communications |
Answer» The correct answer is (d) INFINITY |
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65. |
The voltage and electric current of a line are respectively 5kV and 1000μA. Find its power?(a) 12W(b) 13W(c) 5W(d) 10WI got this question in homework.My question is based upon Problems of AM topic in portion Amplitude Modulation of Analog Communications |
Answer» The correct option is (c) 5W |
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66. |
If modulation index of an AM wave is increased from 1.5 to 2, then the transitted power ________(a) remains same(b) increases by 20%(c) increases by 41%(d) increases by 50%I have been asked this question in exam.My question is from Problems of AM in portion Amplitude Modulation of Analog Communications |
Answer» RIGHT CHOICE is (c) INCREASES by 41% To explain I would say: When m=1.5, transmitted power . = 0.41 X 100 = 41% Therefore,there is an increase in total power by 41%. |
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67. |
________ microphones works on piezoelectric effect.(a) Crystal(b) Carbon(c) Moving coil(d) CondenserThis question was posed to me in examination.I'm obligated to ask this question of Problems of AM topic in section Amplitude Modulation of Analog Communications |
Answer» The correct answer is (a) Crystal |
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68. |
FDM stands for ________(a) Frequency Density Multiplexing(b) Frequency Difference Multiplexing(c) Frequency Division Multiplexing(d) Frequency Data ManagerThe question was posed to me in a national level competition.Enquiry is from FDM System in division Amplitude Modulation of Analog Communications |
Answer» CORRECT answer is (C) Frequency Division Multiplexing Easy EXPLANATION: FDM stands for Frequency Division Multiplexing. The total bandwidth is divided into a series of non-overlapping frequency bands and each BAND is used to carry a separate SIGNAL. |
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69. |
TDM stands for ________(a) Time Division Multiplexing(b) Time Difference Multiplexing(c) Time Duration Multiplexing(d) Time Data ManagerThis question was addressed to me in exam.This is a very interesting question from FDM System topic in division Amplitude Modulation of Analog Communications |
Answer» The correct choice is (a) TIME DIVISION MULTIPLEXING |
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70. |
TDM and FDM are used to multiplex multiple signals into a single carrier.(a) False(b) TrueThis question was posed to me in a job interview.The above asked question is from FDM System topic in chapter Amplitude Modulation of Analog Communications |
Answer» Right answer is (b) True |
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71. |
What is Synchronous TDM?(a) gives same amount of time to each device(b) gives same amount of frequency to each device(c) gives variable time to each device(d) gives variable frequency to each deviceI have been asked this question in an online quiz.Origin of the question is FDM System in chapter Amplitude Modulation of Analog Communications |
Answer» The CORRECT option is (a) GIVES same AMOUNT of time to each device |
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72. |
FDM is an analog multiplexing technique used to combines ________(a) analog signals(b) digital signals(c) both analog and digital signals(d) alternatively passes analog and digital signalsI got this question during an interview for a job.This interesting question is from FDM System topic in portion Amplitude Modulation of Analog Communications |
Answer» Right choice is (a) analog signals |
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73. |
Frequency Division Multiplexing (FDM) is based on orthogonality.(a) True(b) FalseThe question was asked by my college director while I was bunking the class.Question is taken from FDM System in portion Amplitude Modulation of Analog Communications |
Answer» Right choice is (a) True |
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74. |
Which multiplexing technique transmits digital signals?(a) FDM(b) TDM(c) WDM(d) Both FDM and TDMI got this question in quiz.I'm obligated to ask this question of FDM System in chapter Amplitude Modulation of Analog Communications |
Answer» Correct choice is (b) TDM |
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75. |
Time Division Multiplexing (TDM) is based on orthogonality.(a) True(b) FalseI had been asked this question in homework.Question is from FDM System in division Amplitude Modulation of Analog Communications |
Answer» Right CHOICE is (a) True |
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76. |
To get constant time delay, we should use ________(a) FDM technique(b) WDM technique(c) Synchronous TDM(d) Non synchronous TDMI have been asked this question in an online interview.My question is taken from FDM System topic in chapter Amplitude Modulation of Analog Communications |
Answer» The CORRECT answer is (c) Synchronous TDM |
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77. |
As distance increases ________(a) Packet size also increases(b) Packet size decreases(c) Packet size becomes twice of its previous value(d) Packet size becomes halfThis question was addressed to me in semester exam.Asked question is from FDM System topic in chapter Amplitude Modulation of Analog Communications |
Answer» Right option is (a) PACKET SIZE ALSO increases |
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78. |
If 32 equally probable events exists and we have to select one of them, number of required bits is?(a) 2(b) 4(c) 8(d) 5I had been asked this question in exam.My question is taken from FDM System in section Amplitude Modulation of Analog Communications |
Answer» CORRECT answer is (d) 5 Explanation: 2^5 = 32, so number of bits REQUIRED is 5. |
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79. |
Quantization error occurs in ________(a) Time Division Multiplexing(b) Frequency Division Multiplexing(c) Pulse Code Modulation(d) Pulse Width ModulationThis question was addressed to me during a job interview.This intriguing question comes from Methods of Reducing Distortion in chapter Amplitude Modulation of Analog Communications |
Answer» The correct answer is (C) Pulse Code Modulation |
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80. |
If power transmitted is 90kW, what is the field at a distance of 45km?(a) 2(b) 1(c) 0.036(d) 0.01The question was posed to me in unit test.This is a very interesting question from Methods of Reducing Distortion in section Amplitude Modulation of Analog Communications |
Answer» The correct choice is (C) 0.036 |
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81. |
Find the number of pulses, if the number of quantization levels is 32 in PCM?(a) 3(b) 6(c) 4(d) 5This question was addressed to me in an international level competition.Question is taken from Methods of Reducing Distortion in section Amplitude Modulation of Analog Communications |
Answer» The correct option is (d) 5 |
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82. |
Which transistor amplifier is most commonly used?(a) Common Base(b) Common Emitter(c) Common Collector(d) None of theseThis question was posed to me during an interview for a job.This question is from Methods of Reducing Distortion topic in chapter Amplitude Modulation of Analog Communications |
Answer» Right choice is (B) Common Emitter |
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83. |
A device uses a 8 bit word then the maximum number of words it can transmit is ________(a) 64(b) 256(c) 1024(d) 512This question was addressed to me during an online interview.Asked question is from Methods of Reducing Distortion in section Amplitude Modulation of Analog Communications |
Answer» RIGHT choice is (B) 256 Explanation: MAXIMUM number of WORDS which an n-bit device can transmit = 2^n Therefore, when n = 8, Number of words it can transmit is 2^8 = 256. |
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84. |
Peak voltage of a carrier is 8kV, each sideband has an amplitude of 800V. Find its modulation index?(a) 0.28(b) 0.09(c) 0.02(d) 0.08I had been asked this question during an internship interview.My question is from Methods of Reducing Distortion in division Amplitude Modulation of Analog Communications |
Answer» The correct answer is (c) 0.02 |
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85. |
What do you understand by the term Cross talk?(a) generation of closely lying sidebands(b) a method of increasing bandwidth(c) a method of decreasing bandwidth by converting DSB-SC signal to SSB-SC(d) disturbance caused in nearby circuit due to transmitted signalThis question was addressed to me in exam.I'm obligated to ask this question of Methods of Reducing Distortion in chapter Amplitude Modulation of Analog Communications |
Answer» Right answer is (d) disturbance CAUSED in nearby circuit due to transmitted signal |
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86. |
Which modulation technique uses minimum bandwidth?(a) DSB-SC(b) SSB-SC(c) FM(d) VSBI have been asked this question during an internship interview.My question comes from Methods of Reducing Distortion topic in division Amplitude Modulation of Analog Communications |
Answer» The CORRECT answer is (b) SSB-SC |
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87. |
AM waves is represented by Et cos ωc t. What does Etdenotes?(a) envelope(b) carrier signal(c) modulating signal(d) amplitudeThe question was posed to me by my school principal while I was bunking the class.I need to ask this question from Methods of Reducing Distortion topic in division Amplitude Modulation of Analog Communications |
Answer» Right CHOICE is (a) envelope |
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88. |
Wireless communication takes place through ________(a) EM waves(b) X-Rays(c) Optical Fibres(d) Infrared WavesThis question was posed to me in an interview for job.Question is taken from Methods of Reducing Distortion topic in division Amplitude Modulation of Analog Communications |
Answer» CORRECT option is (a) EM WAVES Explanation: Wireless COMMUNICATION takes PLACE through electromagnetic waves. Waves are transmitted through an antenna. |
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89. |
If peak voltage of a carrier wave is 10V, what is the peak voltage of modulating signal if modulation index is 50%?(a) 10V(b) 20V(c) 8V(d) 5VI have been asked this question in an internship interview.Enquiry is from Power Calculation topic in portion Amplitude Modulation of Analog Communications |
Answer» RIGHT OPTION is (d) 5V Best explanation: From the relation, Modulation Index (µ) = Vm/Vc = 50% = 0.5, where Vm = Peak voltage of modulating signal, Vc = Peak voltage of a carrier wave = 10V, Therefore, Vm = 10 X 0.5 = 5V. |
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90. |
Maximum Amplitude of an amplitude modulated 10V and minimum amplitude is 5V. Find its modulation index?(a) 0.65(b) 0.9(c) 0.33(d) 1This question was posed to me during a job interview.My question is taken from Power Calculation topic in division Amplitude Modulation of Analog Communications |
Answer» Correct CHOICE is (C) 0.33 |
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91. |
Sampling frequency of a signal is 6 KHz and is quantized using 7 bit quantizer. Find its bit rate?(a) 48kbPs(b) 64kbPs(c) 16kbPs(d) 8kbPsI got this question in an interview for job.I need to ask this question from Power Calculation in section Amplitude Modulation of Analog Communications |
Answer» Right choice is (a) 48kbPs |
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92. |
24 channels, each band limited to 3.4 KHz, are to be time division multiplexed. Find the bandwidth required for 128 quantization level?(Given that sampling frequency is 8 KHz)(a) 2436 KHz(b) 1002 KHz(c) 1536 KHz(d) 1337 KHzThis question was posed to me in homework.Origin of the question is Power Calculation in division Amplitude Modulation of Analog Communications |
Answer» Right CHOICE is (c) 1536 KHz |
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93. |
Calculate power in each sideband, if power of carrier wave is 96W and there is 40% modulation in amplitude modulated signal?(a) 11.84W(b) 6.84W(c) 3.84W(d) 15.84WI had been asked this question in quiz.The above asked question is from Power Calculation topic in chapter Amplitude Modulation of Analog Communications |
Answer» Right option is (c) 3.84W |
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94. |
For 50% modulation, power in each sideband is ________ of that of carrier.(a) 10%(b) 4.32%(c) 5%(d) 6.25%I got this question by my college director while I was bunking the class.Query is from Power Calculation in division Amplitude Modulation of Analog Communications |
Answer» The CORRECT answer is (d) 6.25% |
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95. |
For 100% modulation, total power is ________(a) 1.5Pc(b) 2Pc(c) 3.75Pc(d) 1.25PcI got this question during an interview for a job.The question is from Power Calculation in portion Amplitude Modulation of Analog Communications |
Answer» The CORRECT choice is (a) 1.5Pc |
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96. |
If each element of signal occupies 70ms, what will its speed?(a) 11.23 bauds(b) 14.28 bauds(c) 17.39 bauds(d) 13.33 baudsThis question was posed to me in an interview for internship.This intriguing question comes from Power Calculation topic in section Amplitude Modulation of Analog Communications |
Answer» Right choice is (B) 14.28 bauds |
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97. |
If a wave is modulated by two waves. One of them has modulation index equal to 0.75 and other has 0.2, the total modulation index will be ________(a) 0.67(b) 0.58(c) 0.77(d) 0.35I have been asked this question in a national level competition.Asked question is from Power Calculation topic in division Amplitude Modulation of Analog Communications |
Answer» The correct OPTION is (c) 0.77 |
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98. |
Power of carrier wave is 300W and modulation index is 0.75. Find its total power?(a) 465W(b) 384W(c) 323W(d) 502WI have been asked this question in quiz.The question is from Power Calculation topic in chapter Amplitude Modulation of Analog Communications |
Answer» Correct choice is (b) 384W |
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99. |
Find the power saving for DSB-SC wave with 100% modulation?(a) 66%(b) 86%(c) 50%(d) 33%I had been asked this question during a job interview.Query is from Power Calculation in section Amplitude Modulation of Analog Communications |
Answer» Correct OPTION is (a) 66% |
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100. |
If power transmitted is 45kW, field at a distance of 23km will be ________(a) 0.02(b) 0.75(c) 0.05(d) 0.03The question was asked in an online interview.I'm obligated to ask this question of Power Calculation topic in portion Amplitude Modulation of Analog Communications |
Answer» Right answer is (c) 0.05 |
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