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11251.

Question : The alpha cells of islets of langerhans secrete ......

Answer»

SOLUTION :(GLUCAGON)
11252.

Question : The all-or-none principle states that

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A) the PROPERTIES of an action potential are independent of the strength of the depolarising stimulus
B) all STIMULI will produce action POTENTIALS
C) all graded potentials will generate action potential
D) any cell membrane can generate and propagate an action potential if STIMULATED to threshold

11253.

Question : The alkaloid, colchicine, used in biological laboratories toinduce polyploidy is extracted from the :

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CORMS of COLCHICUM luteum
leaves of Phormium tenax
ROOTS of WITHANIA somnifera
stems of Glycyrrhiza glabra

Solution :corms of Colchicum luteum
11254.

Question : The alimentary canal of nematodes has

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only MOUTH
only ANUS
mouth and anus
no INTESTINE

11255.

Question : The alimentary canal of frog is short because, it is a

Answer»

HERBIVORE 
OMNIVORE 
FRUGIVORE 
CARNIVORE 

ANSWER :D
11256.

Question : The alga Chara is called stonewort because its plant body is encrusted with

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CALCIUM BICARBONATE
Calcium carbonate
Calcium chloride
Calcium OXALATE

Answer :B
11257.

Question : The age of a tree can be determined with the help of …………..

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SOLUTION :ANNUAL RINGS
11258.

Question : The affect ofapical dominance can be overcome by which of the following hormone:

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IAA
Ethylene
Gibberellin
Cytokinin

Answer :D
11259.

Question : The affect of apical dominance can be overcome by which of the following hormone ?

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IAA
Ethylene 
GIBBERELLIN 
CYTOKININ

Solution :Cytokinin
11260.

Question :The aestivation of corolla in pea flowers is called

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Valvate
Contorted
IMBRICATE
Vexillary

Answer :D
11261.

Question : The additional chambers in the digestive tract of birds are

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CROP and cloaca
GIZZARD and cloaca
crop and gizzard
INTESTINE and crop

ANSWER :C
11262.

Question : The actual process of respiration occurs in protoplasmof the cell.

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Solution :The respiratory substrate like glucose undergoes combustion and PYRUVIC acidis produced by glycolysis. Pyruvic acid enters mitochondria to TAKE place KREBS. CYCLE and oxidative phosphorylation. Where respiratorysubstrateis completelyoxidised and energyis producedin the FORM of ATP
11263.

Question : The activity of cambium is under the control of

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Enivronmental FACTORS
PHYSIOLOGICAL factors
Both A and B
NONE of the above

Solution :The ACTIVITY of CAMBIUM is under thecontrol of environmental and physiological factors
11264.

Question : The action potential occurs in respnse to a threshold stimulus, but not at sub threshold stimuli. What is the name of the principle involved ?

Answer»

SOLUTION :All or NONE PRINCIPLE.
11265.

Question : The ............. acting on agglutinogen B is called anti B.

Answer»

SOLUTION :AGGLUTININ
11266.

Question : The accompanying figure shows reabsorption of some constituents of glomerular filtrate in different parts of mammalian nephron. What can these constituents be?

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`A-Na^(+),B-"Water",C-"UREA"`
A-Urea, `B-Na^(+)`, C-Water
A-Water , B-`Na^(+)`,C-Urea
A-`Na^(+)`,B-urea, C-water

Solution :Graph A is for `Na^+`, as the `Na^+` PASSES through proximal TUBULE, it's absorption increases. About 60% of `Na^(+)` from glomerular filtrate is absorbed here. Loop of HENLE is divided into two parts: (i) descending limb and (ii) ascending limb. Descending lib is impermeable but ascending limb is permeable for `Na^(+).Na^+` reabsorption again increases in distal convoluted tubule under the influence of aldosterone. its absorption also occur in collecting duct but itstabilises here. Graph B is for water. Much of the water is absorbed in proximal tubule. Descending lib of loop of Henle is permeable but ascending limb of loop of Henle is impermeable to water. As the water passes through distal tubule and collecting duct its absorption increases. Graph C is for urea. much of the urea is absorbed in proximal tubule. Descending limb is impermeable but ascending limb is partially permeable to urea. As it passes through in proximal tubule. Descending limb is impeable to urea. As it passes through distal and collecting tubule its absorption also increases.
11267.

Question : The accumulation of uric acid crystals in the region of joints resulting in painful movements causes

Answer»

Fluorodosis
gout
arthritis
rheumatoid arthritis

Solution :Gout is inflammation of joints due to ACCUMULATION of uric ACID crystals. This RESULT in PAINFUL MOVEMENTS.
11268.

Question : The acrosome is formed from __________ .

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SOLUTION :GOLGI BODY
11269.

Question : The accessory gland present in male cockroach is

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SEMINAL VESICLE 
collaterial GLAND 
phallomeres
mushroom SHAPED gland 

ANSWER :D
11270.

Question : The above structure represents a …………………

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POLYNUCLEOTIDE
AMINO ACID
NUCLEOSIDE
Nucleotide

Answer :D
11271.

Question : The above diagram shows the germs layer. The animals having structures shown in the figure. (A) and (B) are respectively called.

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Diphoblastic, Triploblastic
Triploblastic, diploblastic
Diploblastic, Diploblastic
Triphoblastic, Triphoblastic

Answer :A
11272.

Question : The above diagram shows some stages in microgametogenesis.Identify A, B and C

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A - Symmetric spindleB - GENERATIVE cell, C VEGETATIVE cell
A - Symmetric SPINDLE, B - Vegetative cell, C Generative cell
A - Asymmetric spindle, B - Vegetative cell, C Generative cell
A - Asymmetric spindle, B - Generative cell, C Vegetative cell

ANSWER :3
11273.

Question : State whether the following statement is true or false. The ability of plasma membrane to engulf macromoleculesis known as pinocytosis. A. TrueB. False

Answer»


ANSWER :FALSE
11274.

Question : In the figure, masses m_(1), m_(2) and M are 20kg, 5kg, and 50kg respectively. The coefficient of friction between M and ground is zero. The coefficient of friction between m_(1) and M and that between m_(2) and ground is 0.3. The pulleys and the strings are massless. The string is perfectly horizontal between P_(1) and m_(1) also between P_(2) and m_(2). The string is perfectly vertical between P_(1) and P_(2). An external horizontal force F is applied to the mass M. Let the magnitude of the force of friction between m_(1) and M be f_(1) and that between m_(2) and ground be f_(2). For a particular F it is found that f_(1) = 2f_(2). [Take g = 10 m/s^(2)] (i) Findf_(1)in Newton (ii) Find f_(2)in Newton (iii) Find F in Newton (iv) Find tension in the string in Newton (v) Find acceleration of the masses inm//s^(2)

Answer»


ANSWER :TRUE
11275.

Question : The 8th, 9th and 10th pairs of ribs are called .............ribs.

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SOLUTION : FLASE /vertebro-chondral
11276.

Question : The 80S ribosome has two sub units which are

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A) 30S and 50S
B) 40S and 60S
C) 40S and 40S
D) 20S and 60S

Answer :B
11277.

Question : The 3^(rd),6^(th) and 11^(th) cranial nerves are respectively

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oculomotor, ABDUCENS and accessory
oculomotor, TRIGEMINAL and accessory
optic, FACIAL and accessory
trochlear, abducens and vagus.

Solution :NA
11278.

Question : The 3.-5. phosphodiester linkages inside a polynucleotide chain serve to join

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One DNA strand with the other DNA strand
One nucleoside with ANOTHER NUCLEOTIDE
One nucleotide with another nucleotide
One NITROGENOUS base with PENTOSE sugar

Answer :B
11279.

Question : The 11th and 12th pairs of ribs are called as ........... ribs.

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SOLUTION :FLOATING /VERTEBRAL
11280.

Question : Thallus is flattened, leaf like and anchors to the rocks with the help of holdfast in

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LAMINARIA
POLYSIPHONIA
Batrachospermum
ECTOCARPUS

ANSWER :A
11281.

Question : Thallus is an unbranched filament in this algae

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Spirogyra
Chlamydomonas
Cladophora
Dictyota

Answer :A
11282.

Question : Thallospores are produced by ……………….

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ASPERGILLUS
Erysiphe
SACCHAROMYCES
FUSARIUM

ANSWER :B
11283.

Question : Thallus of the Marchantia is

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DORSIVENTRAL
Isobilateral
Both A and B
None of the above

Solution :THALLUS of the MARCHANTIA is dorsiventral
11284.

Question : Thalloid plant body shows parts like holdfast, stipe and frond in this class of algae

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PHAEOPHYCEAE
Chlorophyceae
Rhodophyceae
CYANOPHYCEAE

ANSWER :A
11285.

Question : Thalamus (torus/receptacle) is condensed end of floral axis on which floral leaves are inserted. This thalamus represents

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4 internodes
3 internodes
2 internodes
1 internodes

Answer :B
11286.

Question : Tetradynamous condition of the androecium is a characteristic feature of the family :

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BRASSICACEAE
FABACEAE
POACEAE
MALVACEAE

SOLUTION :Brassicaceae
11287.

Question : Testosterone is secreted by

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sertoli cells
leydig cells
spermatogenic cells
all of the above

11288.

Question : Testes of cockroach are present in abdomen at

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dorsal side of 4TH to 6th segment 
VENTRAL side of 4-6th segments 
LATERAL sides of 4th to 6th abdominal segments
all the above 

Answer :C
11289.

Question : Testes are attached to dorsal body wall of kidney by

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MESOVARIUM 
MESORCHIUM 
MESOTHELIUM 
all the above 

ANSWER :B
11290.

Question : Testa of a seed is produced from

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OVARY wall
hilum
OUTER INTEGUMENT of ovule
funicle

Answer :C
11291.

Question : Tessellated epithelium is

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SIMPLE SQUAMOUS 
simple cuboidal 
Simple COLUMNAR 
Transitional 

ANSWER :A
11292.

Question : Terrestrial animals are generally either ureotelic or uricotelic, not ammonotelic, why ?

Answer»

Solution :Ammonotellic animals EXCRETE ammonia along with a large quantity of water. Ammonia is highly TOXIC and is SOLUBLE in water. So all ammonotelic animals are aquatic. But terrestial ureotelie-animals are mainly ureotelic or uricotelic because they NEED only very little water for excretion. i.e., TERRESTRIAL animals have to conserve water and cannot lose more water from their body.
11293.

Question : Terrestrial animals are either ureotelic or uricotelic not ammonotelic. Evaluate the statement.

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Solution :Terrestrial animals do not have SURPLUS SUPPLY of water. AMMONOTELIC over NEED abundant supply of water.
11294.

Question : Terminal leaflets are not involved inphotosynthesis in

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Wild pea
Sweet pea
GARDEN pea
CHICK pea

Answer :C
11295.

Question : Terminalisation of chiasmata occurs at ............ .

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Zygotene
Leptotene
Diakinesis
Pachytene

Answer :C
11296.

Question : Terminal leaflets are modified into tendrils in

Answer»

PISUM
Bean
Pumpkin
GRAPEVINE

ANSWER :A
11297.

Question : Term meristem was coined by

Answer»

Nageli
Hanstein
HOFMEISTER
Schmidt

Answer :A
11298.

Question : Term meiosis was proposed by

Answer»

FARMER and Moore
Flemming
Strasburger
Darlington

Answer :A
11299.

Question : Term basal body is associated with the development of

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CILIA and flagella
cell plate
phragrnoplast
Kinetocore

Answer :A
11300.

Question : Tendrils of grapevines are homologous to the tendril of pumpkins but are analogous to that of pea . Justify the above statement.

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Solution :Homologous ORGANS : In homologous organs origin is same. They are different in FUNCTIONS means axillary bud is modified into tendril in grape and WATERMELON means homologous while analogous organs origins are different but functions are alike. Leaf is modified into tendril in peas and functions for climbing in the plant.
Hence in peas the origin of tendril is different but its function is same as STEM tendril of grape.
For SEE diagram section - A , Q. No. 6 ( B )