

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
23601. |
Question : A field of pea has plants bearing both yellow and green seeds green sheet colour is preferred, which of the following cross if performed repatedly has a higher probability for obtaining pure line for green seed colour? |
Answer» `YY × YY` |
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23602. |
Question : A fibrous root system is excellent for |
Answer» FOOD storage |
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23603. |
Question : A few statements with regard to sexual reproduction are give below :(i) Sexual reproduction does not always require two individuals.(ii) Sexual reproduction generally involves gametic fusion. (iii) Meiosis never occurs during sexual reproduction.(iv) External fertilisation is a rule during sexual reproduction.Choose the correct statements from the options below : |
Answer» i and iv Sexual reproduction generally involves gametic fusion. Meiosis OCCURS during sexual reproduction in dipole organisms. External fertilisation is not a rule during sexual reproduction, internal FERTILIZATION also taks PLACE. |
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23604. |
Question : A few statements describing certain features of reproduction are given below : (i) Gametic fusion takes place (ii) Transfer of genetic material takes place (iii) Reduction division takes place (iv) Progeny have some resemblance with parents Select the options that are true for both asexual and sexual reproduction from the options given below : |
Answer» i and ii |
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23605. |
Question : A few organisms which can tolerate and thrive in a wide range of temperature are called: |
Answer» Homoiothermal |
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23606. |
Question : A few plants exhibit unusual flowering phenomenon, in which of them flower only once in their life time generally after 50 - 100 years, produce large numbers of fruits.(A) Strobilanthus kunthiana(B) Bamboo(C) Callistemon linearis(D) Cymbopogon reptoeus |
Answer» Strobilanthus kunthiana |
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23607. |
Question :Assertion : Chicken pox is a mild disease however it leaves scars and marks.Reason : Chicken pox results in rashes which appear first on face and spread on stomach and chest later. |
Answer» bothassertion and REASON are true and reason is correct for ASSERTION |
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23608. |
Question : A : Fertilization is done in the body of female in ZIFT and IVF method. R : GIFT method is done in laboratory. |
Answer» A & R are correct , R is explanation of A |
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23609. |
Question : A fertilised egg is a blue print for future development. Justify the statement. |
Answer» Solution :After fertilisation the repeated cell division takes PLACE in the ovum and it forms zygote. The cells formed by cleavage are known as blastomeres. By repeated cleavage the zygote transforms into a solid MASS of cells which resemble the mulberry fruit known as morula. The morula then forms blastula and then to gastrula. Upto this stage the cells are ENDIF ferentiated. After this stage the cells begin to differentiate and form different organs. So it is SAID that a FERTILIZED egg is a blue print for future development. | |
23610. |
Question : A fern-like character shown by Cycas leaves is |
Answer» CIRCINATE VERNATION |
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23611. |
Question : A female who has no prior history of thalassemia in her family marries a thalassemic man.If their son marries a carrier woman then what will be the probability of grandson to be affected with thalassemia ? |
Answer» `1/2` Both male and female gametes of spirogyra are non - FLAGELLATED |
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23612. |
Question : A femalewhoseblood group is AB^(-)gotconceived and laterit is diagnoisedthather foetuspossess B^(+)Whatmeasureswouldbe takento preventthe focusfromHae molyticdiseaseof New born(HDN |
Answer» Solution :If the mother is Rhnegativeand focusis Rhpositive, anti Dantibodies should be administeredto the mother at `28^(th) and 34^(th)`week of gestationas a prophylactic measure . If the Rh negativemother delieversRhpositivechildthenD antibodies houldbe administeredto the mothersoon after DELIEVERY . Thisdevelopspassive immunityand preventsthe formatin of anti Dantibidiesin the mothers BLOOD by destroying the Rh FOETAL RBC beforethe mother.simmune SYSTEM is sensitized. Thishas to be done whenever the womanattains pregnancy . | |
23613. |
Question : A feature common in gametophyte of both mosses and maximum ferns is- |
Answer» Independent existence |
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23614. |
Question :A feature common in both gametophyte and sporophyte of mosses and ferns is :- |
Answer» INDEPENDENT existance |
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23615. |
Question : A farmer has lot of banana trees in his farm.He wishes to go in for selection to improve the crop.Which method can be adopted in banana? |
Answer» Solution :He can ADOPT clonal selection SINCE BANANA reproduces asexually from the UNDERGROUND stem. | |
23616. |
Question : A farmer was facing the problem of low yield from his farm. He was advised to keep a beehive in the vicinity. Why? How would the beehive help in enhancing yield ? |
Answer» SOLUTION :Bees are the pollinators of MANY of our crop species such as sunflower, BRASSICA, apple and pear. Keeping beehives in crop FIELDS during flowering period increases pollination efficiency and improves the yield beneficial both from the point of view of crop yield and honey yield. | |
23617. |
Question : A farmer harvests his crop and expresses his harvest in three different ways. (a) I have harvested 10 quintals of wheat. (b) I have harvested 10 quintals of wheat today in one acre of land. I have harvested 10 quintals of wheat in one acre of land, 6 months after sowing. Do the above statements mean one and the same thing. If your answer is yes, give reasons. And if your answer is 'no' explain the meaning of each expression. |
Answer» Solution :The presentation of farmer is for cutting his crop. (a) He has cut 10 QUINTAL wheat. (b) He has DONE cutting of 10 quintal wheat in one acre land. (c) After sowing of 6 month means it was one and only one thing because crop is an artificial ecosystem which prepares biotic and abiotic COMPONENTS. Here water is as abiotic factor given by farmer white LIGHT, moisture, air are given naturally to it. Biotic components like wheat plant is OBTAINED to farmer after cutting. |
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23618. |
Question : A fall in glomerular filtration rate (GFR) activates : |
Answer» Adrenal CORTEX to release aldosterone |
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23619. |
Question : a factal sex determination test based on the chromosomal pattern in the amniotic fluid surrounding the developing embryo is called |
Answer» Amniocentis |
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23620. |
Question : A failure in cell division after DNA replication results into |
Answer» HAPLOIDY |
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23621. |
Question : A factor responsible for cirrhosis of liver is : |
Answer» Vitamins |
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23622. |
Question : [A] :Extracellular fluid serves as the sanitary drainage line of the body [R] : Extracellutar iiuid collects excess H_2O, CO_2 and metabolic wastes from all tissues of the body. |
Answer» If both A and R are TRUE and R is the correct EXPLANATION of A |
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23623. |
Question : (a) Explain the observations and the conclusion Darwin by during his visit to Galapagos Islands. (b) Write the two key concepts of Darwin's theory of natural selection. |
Answer» SOLUTION :SEE Q.29, (or) (a) Set-I.,DELHI BOARD-2014 and See Q.13, Set-III.,Delhi Board -2015. | |
23624. |
Question : Explain the mode of sex determination in honeybees. |
Answer» Solution :Haplodiploidy in Honeybees : In hymenopteran insects such as honeybees, ants and wasps, a mechanism of sex DETERMINATION called haplodiploidy mechanism of sex determination is common. In this system, the sex of the offspring is determined by the number of sets of chromosomes it receives. Fertilized eggs develop into females (Queen or Worker) and unfertilized eggs develop into males (drones) by PARTHENOGENESIS. It means that the males have half the number of chromosomes (HAPLOID) and the females have double the number (diploid), hence the name haplodiplody for this system of sex determination.This mode of sex determination FACILITATES the evolution of sociality in which only one diploid female becomes a queen and lays the eggs for the colony. All other femals which are diploid having developed from fertillized eggs help to raise the queen.s eggs and so contribute to the queen.s reproductive success and indirectly to their own, a phenomenon known as kin Selection. The queen constructs their social environment by releasing a HORMONE that suppresses fertility of the workers. (b) ![]() |
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23625. |
Question : A) Explain the following assisted reproductive technologies : I) IVF-ET II) ZIFT III) ICSI B) Name any two hormone producing IUD's. |
Answer» Solution :a) (i) IVF-ET -Invitro fertilisation -embryo transfer. The fertilisation outside the BODY of the mother in simulated condition. The transfer of embryo to the fallopian TUBE or uterus of surrogate mother. (II) ZIFT -Zygote intra fallopian transfer. ZYGOTES with 8 blastomeres are transferred into the fallopian tube. (ii) ICSL - Intra cytoplasmic SPERM injection. Sperm is directly injected into the ovum in laboratory. b) i) Progestasert, i) LNG -20. |
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23626. |
Question : (a) Explain the events taking place at the time of fertilization of an ovum in a human female. (b) Trace the development of the zygote upto the implanation in the uterus. (c) Name and draw a labelled sectional view of the embryonic stage that gets implanted. |
Answer» Solution :(a) Fertilisation : (i) The process of fusion of a sperm (male gamete) with an ovum (female gamete)is called fertilisation. ![]() (ii) During coitus, semen is released by the penis into the vagina (insemination). (iii) The motile sperms swim rapidly. through the cervix, enter into the vagina (insemination). (iv) The motile sperms swim rapidly, through the cervix, into the uterus and reach the ampullary- isthmic junction of the oviduct. (v) A sperm comes in contact with the zona pellucide LAYER of the ovum and induces changes in the membrane to block the entry of additional sperms. (vi) The enzymes of the acrosome of sperm help to dissolve zona pellucida and plasma membrane of the ovum and sperm head is allowed to enter into the cytoplasm of the ovum, i.e., secondary oocyte. ffitimately, diploid zygote is produced by the fusion of a sperm and an ovum. (b) Implantation : (i) Zygote divides rapidly by mitiotic division called cleavage and as a result 2, 4, 8, 16 daughter cells are produced which are termed as BLASTOMERES. (ii) Embryo with 8-16 blastomeres is called a morula. (iii) The morula changes into a large mass of cells called blastocyst which passes further into the uterus. (iv) Blastomeres in the blastocyst are arranged into an outer layer called trophoblast and an inner group of cells attached to trophoblast called inner cell mass. (v) The trophoblast layer gets attached to the cells of the endometrium and the inner cell mass gives rise to the embryo. (vi) The cell of endometrium DIVIDE rapidly and cover the blastocyst. (vii) The blastocyst gets EMBEDDED in the endometrium of the uterus called implantation of pregnancy. (viii) The Embryonic stage that gets implanted is called blastocyst ![]() |
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23627. |
Question : (a) Explain menstrual cycl in human females (b) How can the scientific understanding of the menstrual cycle of human females help as a contraceptive measure ? |
Answer» Solution :(a) (i) The reproductive cycle in the female primates (E.g monkey apes and human is called) menstural cycle . (ii) The Ist mentrual cycle begins at puberty and is called MENARCHE ltrbgt (III) In human females menstruation is repeated at an average interval about `28//29` days and the cycleof events strarting fromone menstraution till the next one is menstrual cycle. The phase of menstural cycle areas follows : (i) Menstrual phase : It lasts for 3-5 days .Menstrual flow results due to breakdown of endometrial lining of hte uterus and its blood vessel which form liquid that come out thorhg vagina menstruation only OCCURS if the releaaed ovum is not feritslied (ii) Follicular phase: It lasts for 8-10dyas during phase the primary follicles in the ovary grows to become f fully mature graffian folliclea and simultaneously the endometrium fofuterus regenerates through proliferation.The secreation of LH and FSH increses gradually (iii)Obulatory phse: It lasts for 1 day .Ther is release of ovum Luteal phase : It lasts for 13 DYS .There is LH surge .These induces the remaining part of graffian if fertiliztion occurs endometriumstarts preparing for implant ation . In the absence of fertiliztion corpus luteunm degenerates (i) Rhythm method : period absitinenerce in whinc coulples avoid coitius form day 10-17 the menestural cylce .In this method ovultion is expected occur and chancesf of fertizlaiton are very high (ii) Pills used by females also depends on menstrual cycle .oral pills have to be taken dialy fora period of 21 days starting within the first five days menstural cycle oral pills inhibit ovulation and implanation and also modify the equality of cervical mucus to prevent / retard entry of sperms |
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23628. |
Question : (a) Explain Griffith’s series of exeeriments where he witnessed transformatio in bacteria he worked with. (b) Name the scientists responsible for determining the biochemical nature I “transforming principle” in Griffith’s experiments. What did they prove ? |
Answer» Solution :(a) Frederick Griffith, in a series of a EXPERIMENTS with streptococcus pneumonia witnessed a miraculous transformation in the bacteria. During the course of his experiment, living organism had changed in PHYSICAL form. n When streptococcus preumoniae bacteria are grown on a culture plate, some produce smoot ‘ shiny colonies (S) while other produce ROUGH colonies (R). This is because the S strain bacteri have a mucous(polysaccha1ide)coat, while R strain does not. S strairi mice die from pneumonia but R strain mice did not develop pneumonia. S (strain)--Inject into mice `to` Mice die. R (strain)-Inject into mice `to` Mice LIVE. S strain (heat-killed)-Inject into mice-Mice live. S strain (heatrkilledy-Inject into‘ mice-Mice die. + R strain (live) He concluded that the R strain bacteria have been TRANSFORMED by tho heat-killed S-strain bacteria. (b) momma work of Oswald Avery, Colin Macleod and Maclyn McCarty the genetic mater was through to be a protein, They worked to determine the Biochemical nature of 'transforming - Pmmple’ in Griffith’s experiment. They purified biochemicals (proteins, DNA, RNA etc. )from the heat-killid S cells to whichones could transform live R cells into S cells. They discovered that DNA alone from S bacteria caused R bacteria to become transformed. |
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23629. |
Question : (a) Explain in detail about stem cell therapy. |
Answer» Solution :Stem cells are undifferentiated cells found in most of the multi cellular ANIMALS. These cells maintain their undifferentiated state even after UNDERGOING numerous mitotic divisions. Stem cell research has the potential to revolutionize the future of medicine with the ability to regenerate damaged and diseased organs. Stem cells are capable of self renewal and exhibit .cellular potency.. Stem cells can differentiate into all types of cells that are derived from any of the three germ layers ectoderm, endoderm and mesoderm. In mammals there are two main types of stem cells - EMBRYONIC stem cells (ES cells) and adult stem cells. ES cells are pluripotent and can produce the three primary germ layers ectoderm, mesoderm and endoderm. Embryonic stem cells are multipotent stem cells that can differentiate into a number of types of cells. Es cells are isolated from the epiblast tissue of the inner cell mass of a blastocyst. When stimulated ES can develop into more than 200 cells types of the adult body. ES cells are immortal i.e. they can proliferate in a sterile culture medium and maintain their undifferentiated state. Adult stem cells are found in various tissues of children as well as adults. An adult stem cell or somatic stem cell can divide and create another cell similar to it. Most of the adult stem cells are multipotent and can act as a repair system of the body, replenishing adult tissues. The RED bone marrow is a rich source of adult stem cells. The most important and potential application of HUMAN stem cells is the generation of cells and tissues that could be used for cell based therapies. Human stem cells could be used to tes new drugs. |
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23630. |
Question : What are the objectives of Afforestation programme? |
Answer» Solution :(a) The crossing of two plants differing in two pairs of contrasting traits is called dihybrid cross. In dihybrid cross, two characters (colour and shape) are considered at a time. Mendel considered the seed shape (round and wrinkled) and cotyledon colour (yellow & green) as the two characters. In seed shape round (R ) is dominant over wrinkled (r ), in cotyledon colour yellow (Y) is dominant over green (y). Hence the pure breeding round yellow parent is represented by the genotype RRYY and the pure breeding green wrinkled parent is represented by the genotype rryy. During gamete formation the genes of a character assort out independetly of the other pair. During the `F_(1)XX F_(1)` fertillization each zygote with an equal probability receives one of the four combinations from each parent. The resultant gametes thus will be genetically different and they are of the following four types : (1) Yellow round (YR) - 9/16 (2) Yellow wrinkled (Yr) - 3/16 (3) Green round (yR) - 3/16 (4) Green wrinkled (yr) - 1/16 These four types of gametes of `F_(1)` dihybrids unite randomly in the process of fertillization and produce sixteen types of individuals in `F_(2)` in the ratio of 9:3:3:1 as shown in the figure. Mendel.s 9:3:3:1 dihybrid ratio is an ideal ratio based on the probability including segregation, independent assortment and random fertillization. In sexually reproducing organism / plants from the garden peas to human beings, Mendel.s findings laid the foundation for understanding inheritance and revolutionized the field of biology. The dihybrid cross and its result led Mendel to propose a second set of generalisations that we called Mendel.s Law of independent assortment. ![]() Afforestation Objectives : • To increase forest cover, PLANTING more tress, increases `CO_(2)` production and air quality. • Rehabilitation of degraded forest to increase carbon flaxation and reducing `CO_(2)` from atmosphere. • RAISING bamboo planatations. •Mixed plantations of minor forest produce and medicinal plants. •REGENERATION of indigenous herbs / shrubs. •Awareness creation, monitoring and evalution. •To increase the level and availability of water table or ground water and also to reduce nitrogen leaching in soil and nitrogen contamination of drinking water, thus making it pure not polluted with nitrogen. •Nature aided artificial regeneration. |
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23631. |
Question : (a) Expand VNTRs and describe its role in DNA fingerprinting (b) List any two applications of DNA finger printing techniques |
Answer» SOLUTION :(a) VNTRs(variable Number tandem repeates) each individual inherits these repeats from his/her parents which isused as genetic markeer s.one half of VNTR alleles of thec hild resembles that of mother and other half the father .The copy number varies from CHROMOSOMES to chromosome in an individual .The number of repeat show very high degree of polymorphism (b) Application of DNA finger printing: (i) Identify criminals if their DNA from blood HAIR follide , skin bone , saliva , SPERM etc is available in forensic labs (ii) DETERMINE paternity |
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23632. |
Question : [A]: Exchange of genetic material occurs dur- ing meiosis. [R]: There is chiasma formation in meiosis. |
Answer» If both A and R are true and R is the correct EXPLANATION of A |
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23633. |
Question : [A]: Evolution is a theory.[R]: As it is based on causes and evidences. |
Answer» If both A and R are true and R is the correct EXPLANATION of A |
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23634. |
Question : [A]: Evolution is not occurring at present.[R]: Evolution is a very lengthy process |
Answer» If both A and R are TRUE and R is the CORRECT explanation of A |
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23635. |
Question : [A]: Evolution is descent with modification.[R]: Evolution is derivation of new species of plants and animals from those existed in past. |
Answer» If both A and R are TRUE and R is the correct EXPLANATION of A |
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23636. |
Question : A : Euro-II norms are framed to reduce the content of CO and aromatic compounds from fuels. R : These compounds lead to reduce visibility and carboxyhemoglobin formation. |
Answer» If both Assertion & REASON are true and the reason is the correct EXPLANATION of the assertion, then mark (1). |
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23637. |
Question : (a) Eutrophication, (b) Algal bloom, (c ) Accelerated Eutrohication, (d) Biomagnification |
Answer» SOLUTION :BIOMAGNIFICATION: It is the increase in CONCENTRATION of a TOXICANT at successive trophic level. | |
23638. |
Question : A. Enzymes for the glycolysis are present in cytoplasm B. Enzymes for the anaerobic respiration are present in the cytoplasmC. Enzymes for the lactic acid fermentation are present in cytoplasm of plant cellD. Enzymes for alcoholic fermentation are present in cytoplasm of the animal cell Read the above given all the statement A to D and choose the correct option |
Answer» A is CORRECT and B and D are INCORRECT |
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23639. |
Question : [A]: Entry of sperm brings about a nearrange- ment of materials of cytoplasmic egg. [R]: Path of male nucleus is marked in ovum as copulation path. |
Answer» If both A and R are true and R is the correct EXPLANATION of A |
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23640. |
Question : [A]: Environment resistance does not limit population growth.[R]: Environment resistance decreases as a population approaches the environment's carrying capacity |
Answer» If both A and R are TRUE and R is the CORRECT explanation of A |
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23641. |
Question : (a) Enlist the name and functions of two lobes of corpora quadrtgemina. (b) Give the functions of crura cerebrt of mesencephalon. |
Answer» Solution :(a) CORPORA quadrigemina corisists of two lobes called superior and inferior colliculi. Inferior colliculi CONTROL and COORDINATE auditory reflexes. Superior colliculi control head and eye movements. (b) Crura cerebri are thick bands of LONGITUDINAL nerve fibres which are present on the FLOOR of the midbrain. They connect the cerebrum to cerebellum and Spinal Cord. |
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23642. |
Question : [A]: Emboly involves the invagination and in- volution through bottling process by the mesentoblast cells.[R]: Emboly is exhibited by the _formation, elongation and ultimate recession of the primitive streak. |
Answer» If both A and R are true and R is the CORRECT EXPLANATION of A |
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23643. |
Question : [A] : Emboly involves the invagination and in- volution. Enmbloy is exhibited by the formation elongation and ultimate recession of the primitive streak |
Answer» If both A and R are TRUE and R is the CORRECT EXPLANATION of A |
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23644. |
Question : [A] : Elephants have lophodont type of teeth.[R]: There is an intricate folding of the enamel and dentine to form transverse ridges. |
Answer» If both A and R are true and R is the CORRECT EXPLANATION of A |
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23645. |
Question : A: Eight cells of octant stage in dicot embryogeny are made by 2 vertical and one tranverse divisions in embryonal cell R: These cells are arranged in epibasal and hypobasal tier |
Answer» if both assetion A REASON are TURE and the reason is the correct EXPLANATION of the assertion then mark |
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23646. |
Question : [A]: Ear muscles of external ear in man arewell developed.[R]: These muscles do not move external ear freely to detect sound |
Answer» If both A and R are TRUE and R is the CORRECT explanation of A |
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23647. |
Question : [A]: Each testis is attached to the abdominal wall by a ligament and under testosterme influence it is drawn into the scrotum during development.(R]: Leydig or interstitial cells secrete andro- gens most potent being testosterone |
Answer» If both A and R are true and R is the correct EXPLANATION of A |
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23648. |
Question : (a) Eco RI : Eccherichia coli RY13 (b) Taq polymerase : _____ |
Answer» SOLUTION :Thermus aquaticus. | |
23649. |
Question : [A]: Each gemete has only one allele for each trait. [R]: It is true of single trait crosses only. |
Answer» If both A and R are TRUE and R is the correct EXPLANATION of A |
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23650. |
Question : A : Each chromosome of bivalent attaches with two spindles in metaphase. |
Answer» IF both Assertion &REASON are TRUE and the reason followed is the correct EXPLANATION of the assertion then mark (1). |
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