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23651.

Question : A dwarf pea plant treated with gibberellic acid becomes tall, then crossed with pure homozygous tall pea plants, then what will be the phenotypic ratio of tall pea plants in F_1 progeny ?

Answer»

100% DWARF plant
50% TALL PLANTS
100% tall plant
all tall PEA plants

Solution : 100% tall plant
23652.

Question : [A]: During evolution of Primates, various groups diverged in a particular sequence from the main line of descent.[R]: Prosimians (Tarsiers, lemurs) which di- verged first, are most distantly related to hu- mans and most closely related to original pri- mates.

Answer»

If both A and R are true and R is the CORRECT EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is false
If both A and R are false

Answer :B
23653.

Question : [A] : During catabolism of food through Krebs cycle, energy is generated by ETS. [R]: Energy is released from electrons, as they pass along a series of reactions

Answer»

If both A and R are true and R is the CORRECT EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is false
If both A and R are false

Answer :A
23654.

Question : A ds DNA is 100 kbp long. The number of nucleotides, number of complete turns in the molecule and the length of the DNA molecule will be:-

Answer»

`1.2xx10^(5),20000,3.4xx10^(4)nm`
`2xx10^(5),10000,3.4xx10^(4)nm`
`2xx10^(5),10000,0.34xx10^(4)nm`
`2xx10^(5),100000,3.4xx10^(4)nm`

Solution :(i) 100 kbp=100000 bp or 200000 bases
(ii) 10 bp forms 1 TURN of DNA & therefore, 100000 bp form 10000 TURNS.
(III) 10 bp are equal to 34Å and therefore, 100000 bp are equal to `3.4xx10^(4)nm` (or `3.4xx10^(5)`Å or `3.4xx10^(-5)m`)
23655.

Question : A drunk person has ill effects the earliest on which part of the brain?

Answer»

Cerebellum
Cerebrum
Pons Varoli
Medulla

Answer :B
23656.

Question : (a) Draw the pedigree of the given family whose ages are given below in the bracket {:("Normal father",(70),"Carrier mother",(65), "Normal son",(40)),("Affected son",(37),"Carrier daughter",(33),"Normal daughter",(30)):} (b) If this family can never have an affected girl then with the help of Punnet square method, whether this diseas can be phenylketonuria, Yes or No ? (Let dominant allel-A, Recessive allele-a)

Answer»

Solution :
(b) If a normal father is crosses with carrier mother then following results are obtained.

Puttingthe cross byy PUNNETT square method the result is WRITTENAS follows :

The result SHOW that this disease cannot be phenylketonuria. Phenylketonuria is arecessive human genetic DISORDER in which the enzyme converting dietary pheylalanie totyprosine is deficient causing EXCRETION of phenylpyruvate in urine.
23657.

Question : [A]: Drosophila is commonly used in the study of genetics. [R]: Because it is very small and its life cycle is short.

Answer»

If both A and R are TRUE and R is the CORRECT explanation of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is false
If both A and R are false

ANSWER :A
23658.

Question : A drug called morphine is obtained from

Answer»

Rauwoiffia
cannabis sativa
cajanus cajan
papaver somniferum

Answer :D
23659.

Question : (a) Draw the longitudinal section of a flower showing growth of pollen tube upto the embryo sac.Label the following parts : (i) Stigma (ii) Pollen tube (iii) Integument (iv) Chalazal end (v) Nucelllus (vi) Synergids (b) What is double fertilisation in Angiosperms? Why is it so called ?

Answer»

Solution :(a) See Q.29, Set-II.., Outside Delhi-2014 (Comptt.) [Page-245].
(b) The SECOND male gamete MOVES TOWARDS the polar nuclei in the central cell and fuses with them the produce a triploid primary endosperm nucleous. SINCE syngamy and triple fusion occur in the embryo sec. The process is called double fertilisation.
23660.

Question : (a) Drawdiagramof femalereproductivesystem ofhuman.Labelthe followingparts: (1) Siteof secondaryoocytedevelopment (2) Structures helpin collection of ovum. (3) Site offertilization. (4) Site whereimplantationof embryooccurs. (b) Namethe hormones secreted by ovary.Alsostatetheirfunctions.

Answer»

Solution :(a) (1)Site of secondaryoocytedevelopment: Ovary.
(2) Structures helpin collectionof ovum : Filmbriae of infun-dibulum.
(3)Site of fertilization :Ampulla of fallopiantube.
(4) Sitewhereimplantationof embryooccurs :Uterus
(b)Hormonessecretedby the ovaryare estrogenand PROGESTERONE.
(i)Estrogen: Stimulationand growthof femalereprodutiveorgans. Controlssecondarysexualcharacters. Regulatesfemale sexualbehaviour.
(II) Progesterone : It is a getational hormonewhich maintains the pregnancy . These is also ACTIONON mammaryglands.Mammaryglands arestimulatedand milksecretionis possibledue toproges-terone . It also maintains corpus luteum for some timebefore the placenta is formed.
23661.

Question : (A) Draw the embryo sac of a flowering plant and label (i) central cell (ii) chalazal end of the embryo sac and (iii ) synergids. (b) Name the cell that develops into the embryo sac and explain how this cell leads to the formation of embryo sac. Alsomention the role played by the various cells of the embryo sac .

Answer»

Solution :(a)
(b) One of the nucellus cells develops into embryo sac . The process of formation of megaspores from the megaspore MOTHER cell is called megasporogenesis . The nucleous of the funtional megaspore divides mitotically to form two nuclei which move to the opposite poles forming the 2 nucleate embryo sac. Again one more mitotic DIVISION results in the formation of4 nucleate and later 8 nucleate STAGE of the embryo sac. Two nuclei present in central cell are called polar nuclei . Three cells grouped together at the microphar end constitute the egg apparatus and synergid . Three cells at the chalazal end are called the antipodals. A typical angiosperm embryo sac at maturity though 8 nucleate is 7 celled.
23662.

Question : (a) Draw an L.S. of pistil showing pollen tube entering into the embryo sac. Label the following : (i) Nucellus(ii) Antipodals(iii)Synergids(iv) Micropyle(b) Write the functions of the following :(i) Synergids(ii) Micropyle

Answer»

Solution :
(b) (i) Synergids : Synergids have special cellular thickenings at the MICROPYLAR tip called FILIFORM apparatus which plays an important ROLE in guiding the pollen tube into the SYNERGID.
(b) Micropyle : It helps pollen tube to enter the ovule and then enters one of the synergids through the filiform apparatus.
23663.

Question : (a) Draw a shematic labelled diagram of a fertilised embryo sac of an angiosperm. (b) Describe the stages in embryo development in a dicot plant .

Answer»

Solution :(a)
(b) Embryo develops at the micropylar end of the embryo sac where the zygote is situated . Must zygotes divide only after certain amount of endosperm is FORMED . This adaptation provides assured nutrition to the developing embryo . The later stages of embryo development ( embryogeny ) are similar in monocotyledons and dicotyledons .
In dicotyledonous embryo the zygots given rise rise to the preembryo and subsequently to the globular heart shaped and mature embryo. In the dicot seed the embryo CONSISTS of an EMBRYONAL axis two cotyledons plumule radicle or root tip . The root tip is covered with root cap.
23664.

Question : (a) Draw a schematic representation of the structure of a transcription unit and show the following in it : (i) Direction in which transcription occurs (ii) Polarity of the two strands involved (iii) Template strand (iv) Terminator gene. (b) Mention the function of promoter gene is transcription.

Answer»

SOLUTION :The MACHINERY and the ENZYME
23665.

Question : Draw a neat labelled diagram of a typical Biogas plant.

Answer»

SOLUTION :
23666.

Question : Endothecium, Tapetum, Epidermis ,Middle layers. These are the parts of anther wall . (a ). Arrange them in an order according to occurrence in the anther wall . (b) What is the function of tapetum ?

Answer»

Solution :(a)
(B) In embryo sac double fertilisation takes PLACE .
The pollen tube releases the male gametes into the cytoplasm of the synergid .
The FUSION of THREE haploid nuclei is termed fusion . Syngamy and triple fusion take place in embryo sac. This phenome non is termed double FERTILIZATION
23667.

Question :(a) Draw a labelled diagram of the human female reproductive system. (b) Enumerate the events in the ovary of a human female during (i) Follicular phase (ii) Luteal phase of menstrual cycle.

Answer»

SOLUTION :(a) (b) In the follicular phase, following events occur (i) The primary follicles in the OVARY grow to form a fully MATURE graffian follicle.
(ii) The endometrium of uterus regenerates through proliferation.
(iii) The secretion of GONADOTROPIN (LH and FSH) gradually increase
In the luteal phase, following events occurs
The parts of graaflan follicle REMAINING after the rupture, transform as the corpus luteum.
The corpus luteum secretes large amounts of progesterone
23668.

Question :(a) Draw a diagram of a fertilized embryo sac of a dicot flower. Label all its cellular components. (b) Explain the development of a mature embryo from this embryo

Answer»

Solution : (b) Embryo developsat the micropylar end of the embryo sac where the zygote is present. Most of the zygotesdivide only after certain amount of endosperm is formed. This is an adaptation to provide assured nutrition to the developing embryo. The zygote GIVES RISE to embryo and SUBSEQUENTLY to globular, heat shaped ANDMATURE embryo. Embryo development is known as Embryogeny.
DICOT embryo consists of an embryonalaxis and two cotyledons. The portion of embryonal axis above the level of cotyledons is the epicotyl, which terminateswith plumule or stem tip.
23669.

Question : A double strand DNA measures 34 mu . How many nucleotide pairs will be present ?

Answer»

10
104
100
105

Answer :C
23670.

Question : A double equatorial plate is formed in

Answer»

METAPHASE I
Metaphase II
MITOTIC Metaphase
CYTOKINESIS

ANSWER :A
23671.

Question : a double helix model of Watson and Crick is known as:

Answer»

C DNA
Z DNA
D DNA
B DNA

Answer :A
23672.

Question : a_ donates high energy and phosohate to ADP, production of ATP b_ is again formed B_ is again formed in relaxing muscel is using c_ and b_ . Choose the option which correctly fills up the blanks a, b,c, d

Answer»

a = Creatin ,B=Phosphocreatine , C=ADP , d= CREATINE
a=Phosphocreatine ,b=Phosphocreatine , c= ATP ,d=creatine
a = Creatin ,b= Creatin ,c=ADP, d= Creatin
a=Phosphocreatine, b =Creatine, c=ATP d= Phonephocreatine

Answer :B
23673.

Question : A dominant , independent, photosynthetic, thalloid or erect body is represented by a haploid gametophyte and it alternates with the short–lived multicellular sporophyte totally or partially dependent on the gametophyte for its anchorage and nutrition. This type of pattern is present in:-

Answer»

BRYOPHYTES (MOSSES and liverworts)
Pteridophytes (ferns and HORSETAILS)
Gymnosperms (Cycas and PINUS)
Most of the ALGAE (Ulothrix and Spirogyra)

Answer :B
23674.

Question : [A]: Domestication is a type of plant breeding. [R]: Selection is the basis for the improve- ment of crops through prant breeding.

Answer»

If both A and R are TRUE and R is the correct EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is FALSE
If both A and R are false

Answer :A
23675.

Question : [A]: Dolly, a sheep is an example of cloning. [R]: Cloning in another sense is sexual re- production.

Answer»

If both A and R are true and R is the CORRECT EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is false
If both A and R are false

ANSWER :B
23676.

Question : A dog bites his own master. Sometimes in human body this type of action takes place. a. Name the disease. b. Give symptomsfor this disease.

Answer»

Solution :a. AUTO immune disease
B. Rheumatoid arthritis (affecting the joints) Myasthenia gravis (neuromuscular disease leading to muscle weakness)
DIABETES MELLITUS type 1 (destruction of beta cells of pancreas)
23677.

Question : A doctor while ocprating on an HIV positive patient accidentally cut himself with a scalpel. He comes to you, suspecting himself to have contracted the virus. Which test will you advise him to rule out/confirm his suspision?

Answer»

PCR
ROUTINE URINE examination
TLC
DLC

Answer :A
23678.

Question : A doctor while operating on an HIV (+)ve patient accidentally cuts himself with a scalpel. Suspecting himself to have contracted the virus which test will he take to rule out/confirm his suspicion ?

Answer»

PCR
Routine urine examination
TLC
DLC

Solution :Very low COUNT of bacteria or viruses (when the symptoms of the disease are not yet visible) CAB be detected by multiplication of their nucletic acid by PCR (PCR can DETECT very low AMOUNTS of DNA). PCR is usually used to detect HIV in suspected AIDS patients.
23679.

Question : A doctor while operating on an HIV (+) patient accidentally cuts himself with a scalpel. Suspecting himself to have contacted the virus, which test he has to do, in order to confirm his doubt ?(A) PCR(B) Routine urine examination(C) TLC(D) DLC

Answer»

PCR
ROUTINE URINE examination
TLC
DLC

SOLUTION :PCR
23680.

Question : A doctor observed the following symptoms in a patient Constipations, abdominal pain and cramps, stools with excess mucus and blood clots. Identify the disease , pathogens and mode of transmission.

Answer»

SOLUTION :Disease: Amoebiasis
Pathogen: ENTAMOEBA histolytica
Mode of transmission: Through contaminated food and water. HOUSEFLY acts as mechanical carrier and TRANSFER the parasite from the faeces of infected person to the food and water.
23681.

Question : A doctor noticed a small internal growth in the abdomen of a patient. He suspected it as a cancer. a. Which biomedical technique enabled the doctor to diagnose the disease? b. Suggest the methods to treat this disease.

Answer»

Solution :a. Biopsy / SCANNING / MRI / Sonography or any other relevant technique
B. • CHEMO therapy
• Surgery
• Hormone TREATMENT
• Immune treatment
• Radiation therapy
23682.

Question : A doctor found that a patient can resist many bacterial diseases by producing antibodies . But he is highly susceptible to viral infections. This may be due to the reduced number of one of the following cells. Identify the cells.a)Thrombocytesb)T-Lymphocytec)Spleen cellsd)Erythrocyte

Answer»

Thrombocytes
T-Lymphocyte
Spleen cells
Erythrocyte

Answer :B
23683.

Question : A DNA template plus primer with the structure (where =a phosphate group ) is placed in an in vitro DNA synthesis systemcontaining Mg^(2+) , an excess of the four deoxyribonucleoside triphosphates, etc. and a mutant formof E. coli DNApolymerase I that lacks 5'rarr 3' exonuclease activity . The 5' rarr 3'polymerase and 3' rarr 5'exonuclease activities of this aberrant enzyme are identical to thisaberrant enzyme are identicalto thoseof normal E. coli DNA polymerase I. It simply has no 5'rarr 3' exonuclease activity . What will be the structure of the final product ?

Answer»




ANSWER :a
23684.

Question : A doctor detected a tumour in the body of a person. The patient feels that he would die soon due to tumour. How can you help him to overcome his fear?. Write your response.

Answer»

Solution :It was tumour, not CANCER. All TUMOURS are not so dangerous. It will not spread. It can be removed by surgery. It is the PERMANENT TREATMENT for tumour.
23685.

Question : A DNA strand is directly involved in the synthesis of all the following except :

Answer»

t-RNA molecule
m-RNA molecule
another DNA strand
protein synthesis

Answer :D
23686.

Question : A doctor advised a pregnant lady not to take any medicines without consulting him especially for the first three months. Give reason.

Answer»

Solution :The basic structure of the baby is formed during the first three MONTHS of pregnancy. During this PERIOD FOETUS is very sensitive to EXTERNAL agents and CHEMICALS.
23687.

Question : A DNA sequence undergoes three subsequent point mutations which result in subsequent changes in transcription of mRNA as shown below: Original mRNA : AUG CAU CUC ACG GAU UAG Point mutation 1: AUG CAU CUU ACG GUA UAGPoint mutation 2 : AUG CAU GCU UAC - GGU AUAPoint mutation 3 : AUG CAU GCU UAA GGU AUA select the correct sequence of point mutations that occurred in the DNA.

Answer»

Missense MUTATION `to` FRAME shift mutation `to` NONSENSE mutation
SILENT mutation `to` Nonsense mutation `to` Frameshift mutation
Silent mutations `to` Frame shift mutation `to` Nonsense mutation
Missense mutation `to` Frameshift mutation `to` Silent mutation

Answer :c
23688.

Question : A DNA sequence undergoes three subsequent point mutations which result in subsequent changes in transcription of mRNA as shown below: select the correct sequence of point mutations that occurred in the DNA.

Answer»

Missense mutation - Frame SHIFT mutation - NONSENCE mutation
Silent mutation - Nonsense mutation - Frame shift mutation
Silent mutation - Frame shift mutation -Nonsense mutation
Missense mutation - Frame shift mutation - Silent mutation

ANSWER :C
23689.

Question : A DNA sequence is provided below: if a nitrogen base is added in between 4th and 5th nitrogen basess what will be its effect on transcription

Answer»

SOLUTION :FRAME SHIFT MUTATION
23690.

Question : A DNA sequence is provided below: TAGGAGTTATATATACAT Write down the triple codon it codes for.

Answer»

Solution :AUG CUS AAU AUA UAU GUA
23691.

Question : [A): DNA replicates after mitosis. [R]: In mitosis, the chromosomal number does not stay constant

Answer»

If both A and R are TRUE and R is the CORRECT explanation of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is FALSE
If both A and R are false

Answer :D
23692.

Question : A DNA molecule having A+G//C+T=0.71 shows that the molecule is:

Answer»

Linear
Circular
Single-stranded
Double-stranded

Answer :C
23693.

Question : A DNA molecule in which both stands have radioactive thymidine is allowed to duplicate in an environment containing non-radioactive thymidine. What will be the exact number of DNA molecules that contain some radioactive thymidine after 3 duplication ?

Answer»

One
Two
Four
Eight

Answer :B
23694.

Question : A DNA molecule of Escherichia coli is heavy (full labelled with N15) and is allowed to duplicate in a medium containg N14. In first generation, the two daughter DNA molecules:-

Answer»

have same density but do not resemble their PARENT DNA
have DIFFERENT densities but resemble their parent DNA
have different densities and ALSO do not resemble the parent DNA
same in density and resemble their parent DNA

Answer :A
23695.

Question : A DNA fragment possesses 32 adenine bases and 32 cytosine bases. How many total number of nucleotides does that DNA fragment contains? Explain.

Answer»

Solution :128 nucleotides. Adenine ALWAYS pair THYMINE base.
If there are 32 adenine bases then there must be 32 Thymine bases. SIMILARLY cytosine pairs with GUANINE. If cytosine bases are 32 in number the guanine bases will be equal to cytosine. So it make a total of 128 nucleotides.
23696.

Question : A DNA fragment is

Answer»

POSITIVELY CHARGED
A buffer
Negatively charged
Neutral

ANSWER :C
23697.

Question : [A]: DNA code is copied in the synthesis of tRNA. [R]: tRNA moves out of the nucleus and after attaching on ribosomes form the template

Answer»

If both A and R are TRUE and R is the CORRECT EXPLANATION of A
If both A and R are true but R is not the correct explanation of A
If A is true and R is false
If both A and R are false

Answer :D
23698.

Question :A DNA finger printing process involves :-

Answer»

CHAIN terminators
DEGENERATED oligonucleotides
Same in lengths of DNA MOLECULES
RFLPs

Answer :D
23699.

Question : A division is formed by combining several :-

Answer»

ORDERS
Families
Classes
Tribes

ANSWER :C
23700.

Question : A distinguishing feature of latex cells is that they are

Answer»

SINGLE CELLED ELEMENTS with anastomosingbranches
Single celled elements with nonanasto mosing branches
Multicelled ELEMENS with anastomosing branches
Multicelled elements with nonanastomosing branches

Answer :B