

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
23701. |
Question : A distilled alcoholic beverage produced from fruit juice fermentation is |
Answer» Vinegar |
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23702. |
Question : A diseased man marries a normal woman. The couple has 3 doughters and 5 sons. The daughters are diseased while the sones are normal . The gene of the disease is |
Answer» SEX LINKED recessive |
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23703. |
Question : A disease which often produces deformities of fingers and toes is |
Answer» Poliomyelitis |
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23704. |
Question : A disease with social stigma is |
Answer» CHICKEN pox |
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23705. |
Question : A disorder that causes hardening of arteries is called_____. |
Answer» |
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23706. |
Question : A disease showing dew drop like pinkish eruption later turning into scrabs which do not leave any pox marks is |
Answer» Measles |
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23707. |
Question : a Disease producing painless indurated ulcer on the genitals with swelling of local lymph gland is |
Answer» Leprosy |
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23708. |
Question : A disease on the verge of extinction in India is : |
Answer» AIDS |
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23709. |
Question : A disease contracted through wounds, accidents and improperly sterilised surgical instruments is |
Answer» Tetanus |
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23710. |
Question : A disease found only in males is |
Answer» Gaucher's disease |
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23711. |
Question : A disease characterised by burning sensation during urination and pain arround genitalia is |
Answer» Syphillis |
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23712. |
Question : A disease characterised by oozing of semisolid material in throat forming a tough membrane is |
Answer» WHOOPING cough |
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23713. |
Question : A disease characterised by eruption of small red spots and inflammation of nasal mucous membrane is |
Answer» chickenpox |
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23714. |
Question : A disease caused by corkscrew like bacterium is |
Answer» Gonorrhoea |
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23715. |
Question : A disease caused by the inflammation of joints is |
Answer» Answer :b | |
23716. |
Question : A disease caused by autosomal primary non-disjunction is : |
Answer» KLINEFELTER's syndrome |
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23717. |
Question : A disease against which vaccination is resorted only during epidemics |
Answer» DIARRHOEAL disease |
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23718. |
Question : A disease caused by an autosomal primary nondisjunction is |
Answer» down.s SYNDROME |
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23719. |
Question : A disease caused by an autosomal primary non-disjunction is. |
Answer» SICKLE CELL Anaemia |
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23720. |
Question : (a) Discuss postulates of Darwin's theory of natural selection. (b) List two differences between Darwinism and Neo-Darwinism. |
Answer» Solution :HINTS: STATE Darwin.s are of exploration Discuss the key concepts of Darwnism : (i) Rapid multiplicaiton - Define and GIVE exaples (ii) Discuss limited FOOD and space. |
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23721. |
Question : A direct method of gene transfer which is suitable for plants, in this cells are bombarded with high velocity micro-particles of gold or tungsten coated with DNA is ? |
Answer» Mircor-injection |
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23722. |
Question : A diploid organism is heterozygous for five loci and homozygous for 2 loci ,how many types of gametes can be prodeced ? |
Answer» 128 |
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23723. |
Question : A diploid organism is heterozygous for 4 loci, how many types of gametes can be produced ? |
Answer» Solution :The FORMULA `2^n` is APPLIED here where n = NUMBER of loci =The ORGANISM is heterozygous for 4 loci, n = 4. So, `2^n = 2^4 = 2 xx 2 xx 2 xx 2 = 16` =The organism will produce 16 types of gametes. |
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23724. |
Question : When a diploid female plant is crossed with a tetraploid male, the ploidy of endosperm cells in resulting seed is : |
Answer» Tetraploidy |
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23725. |
Question : A diploid egg, formed in embryo sac developed directly from nucellus, parthenogenetically grows into embryo. The apomixis is |
Answer» VEGETATIVE apomixis |
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23726. |
Question : A diploid cell is treated with colchicine .It becomes |
Answer» DIPLOID |
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23727. |
Question : A dinoflagellate which is also known as sea ghost. |
Answer» Euglena |
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23728. |
Question : A dioecious flowering plant prevents both |
Answer» (A) CLEISTOGAMY and xenogamy |
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23729. |
Question : A dioecious flowering plant prevents both …..(A) Self fertilisation or self pollination and cross pollination(B) Autogamy and Geitonogamy(C) Geitonogamy and Cross pollination(D) Cleistogamy and cross pollination |
Answer» SELF FERTILISATION or self POLLINATION and CROSS pollination |
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23730. |
Question :A dilcotyledonous embryo consists of |
Answer» RADICLE only |
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23731. |
Question : A dihybrid test cross yielding a result of 1:1:1 ratio is indicative of |
Answer» four different types of gametes produced by the F1 hybrid |
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23732. |
Question :A dihybrid test cross yielding a result of 1: 1: 1: 1 ratio is indicative of : |
Answer» 4 different TYPE of GAMETES produced by the `F_1` dihybrid |
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23733. |
Question : A dihybrid plant with genotype PpNn. It produces four types of gametes in following number PN = 200, pn = 200, Pn = 800, pN = 800 then what is the distance between linked genes? |
Answer» 30 cM |
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23734. |
Question : A dihybrid test cross ratio for two completely linked genes will be |
Answer» `1:1:1:1` |
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23735. |
Question : A dihybrid heterozygous round, yellow seeded garden pea (Pisum sativum) was crossed with a double reccessive plant. What type of cross is this ? |
Answer» SOLUTION :It is a DIHYBRID TEST CROSS. | |
23736. |
Question : A dihybrid heterozygous round, yellow seeded garden pea (Pisum sativum) was crossed with a double reccessive plant.What princip,e of Mendel is illustrated through the result of this cross ? |
Answer» SOLUTION :PRINCIPLE of INDEPENDENT ASSORTMENT. | |
23737. |
Question : A dihybrid heterozygous round, yellow seeded garden pea (Pisum sativum) was crossed with a double reccessive plant. Work out the genotype and phenotyepe of the progeny. |
Answer» SOLUTION :![]() ![]() |
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23738. |
Question : a dihybrid for the traits is crossed with homozygous recessive individual of its type, thePhenotypic ratio is |
Answer» I:2:I |
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23739. |
Question : A dihybrid for qualitative trait is crossed with homozygous recessive individual of its type, the phenotypic ratio is |
Answer» `1:2:1` |
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23740. |
Question : A dihybrid for qualitative trait is crossed with homozygous recessive individual of its type , the phenotypic ratio is : |
Answer» `1:2:1` |
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23741. |
Question : A dihybrid for qualitative trait is crossed with homozygous recessive individual of its type the monotypic ratio is |
Answer» `1:2:1` |
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23742. |
Question : a. Differentiate oviparous and viviparous with examples. b. In which of these two types, is the chances of survival of young ones, greater? Why? |
Answer» Solution :a. Oviparous animals are those which lay eggs, covered by hard calcare-ous shell in a safe place. These eggs after a period of INCUBATION hatch out as young ones. e.g. Reptiles and birds Viviparous animals are those which keep the fertilization product - ZYGOTE within the body of female organism and after attaining a CERTAIN stage of growth are delivered from the body. e.g. Human beings b. Viviparous. Because of PROPER embryonic CARE and protection inside the body. |
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23743. |
Question : A dicotyledonous plant bears flowers but never produces fruits and seeds. The most probable cause for the above situation is(A) Plant is dioecious and bears only pistillate flowers(B) Plant is dioecious and bears both pistillate and staminate flower(C) Plant is monoecious(D) Plant is dioecious and bears only staminate flowers |
Answer» Plant is dioecious and BEARS only pistillate FLOWERS While if plant is dioeciacs, following circumstances can be possible (i) If the plant is dioecious and bear flowers having only pistil then fertilisation can be possible by pollenating agents. (ii) If the plant is dioecious and bear flowers having only stamens then fertilisation is not possible because female gamete is immotile. Which can not reach towards male gamete so syngamy is not possible. When plant is monocieous means both Adrocium and Gynoecium both together then only self fertilisation (AUTOGAMY) and PRODUCTION of seed can be possible |
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23744. |
Question : A dicotyledonous plant bears flowers but never produces fruits and seeds. The most probable cause for the above situation is |
Answer» PLANT is dioecious and BEARS only pistillate flowers |
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23745. |
Question : A diagram showing axon terminal and synapse is given. Identify correctly at least two of A-D. |
Answer» A-Receptor, C-Synaptic vesicles |
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23746. |
Question : A diagram showing axon terminal and synapse is given. Identify correctly at least two of A-D |
Answer» A-Receptor,C-Synaptic vesicles |
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23747. |
Question : A: Detrivores and decomposers hold up a part of nutrientscontained in detritus. R: Immobilised after the death of saprotrophs. |
Answer» If both ASSERTION &Reason are true and the reason is the corect explanation of the assertion , then MARK (1) |
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23748. |
Question : (a) Describe the stage of ooogenesis in human female. (b) Draw a labbed diagram of a human ovam released after ovulation |
Answer» SOLUTION :(a) SeeQ.30 (or) , Set-II, DEHI BOARD 2008.![]() |
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23749. |
Question : (a) Describe the structure of a Cicer seed (dicot seed) with labelled diagram. |
Answer» Solution :Structure of a Cicer seed as an EXAMPLE for DICOT seed The mature seeds are attached to the fruit wall by a stalk called funiculus. The funiculus disappears leaving a scar called hilum, Below the hilum a small pore called MICROPYLE is present. It facilitates entry of oxygen and water into the seeds during germination. Each seed has a thick outer covering called seed coat. The seed coat is developed from integuments of the ovule. The outer coat is called testa and is hard whereas the inner coat is thin, membranous and is called tegmen. ![]() In PEA plant the tegmen and testa are fused. Two cotyledons laterally attached to the embryonic axis are present. It stores the FOOD materials in pea whereas in other seeds like castor the endosperm contains reserve food and the cotyledons are thin. The portion of embryonal axis projecting beyond the cotyledons is called radicle or embryonic root. The other end of the axis called embryonic shoot is the plumule. Embryonal axis above the level of cotyledon is called epicotyl whereas the cylindrical region between the level of cotyledon is called hypocotyl. The epicotyl terminates in plumule whereas the hypocotyl ends in radicle. |
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23750. |
Question : (a) Describe the histological structure of human testis with the help of a labelled diagram. (b) Discuss the significance of extra-abdominal location of testes. |
Answer» Solution :(a) Internally each testis is divided into about250 testicular lobules by ingrowths of capsule of testis. Each testicular lobule has one to threeconvoluted tubules called seminiferous tubules or crypts. Each crypt is lined by germinal epitheliumwhich is formed of cuboidal germ cells (formsperms) and pyramidal-shaped sertoli or nursecells (PROVIDE NUTRITION to developing sperms).Scattered in interstitial SPACES between seminiferous tubules, there are groups of endocrine cells, called Leydig.s cells, which secrete androgens, mostimportant of which is testosterone. (b) In human male, testes are extra-abdominal in position and lie in skin pouches, called scrotal sacs, whichact as thermoregulators and keep the testicular temperature `2^@C`lower than the body temperature for normal spermatogenesis. ![]() |
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