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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 651. |
`LiHCO_(3)` and `Ca(HCO_(3))_(2)` are not found in solid state . |
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Answer» Correct Answer - T They are highly soluble in water |
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| 652. |
Which of the following has the least dipole moment?A. `NF_(3)`B. `CO_(2)`C. `SO_(2)`D. `NH_(3)` |
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Answer» Correct Answer - b `O = C =O`. The values of `C = O` bond dipole are same but acting in opposite direction so cancels out. Thus dipole moment of `CO_(2)` is zero. |
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| 653. |
The increassing order of bond order of `O_(2),O_(2)^(+),O_(2)^(-)`and O_(2)^(--)` is :A. `O_(2)^(+),O_(2),O_(2)^(-),O_(2)^(--)`B. `O_(2)^(--),O_(2)^(-),O_(2)^(+),O_(2)`C. `O_(2),O_(2)^(+),O_(2)^(-),O_(2)^(--)`D. `O_(2)^(2-),O_(2)^(-),O_(2),O_(2)^(+)` |
| Answer» Correct Answer - D | |
| 654. |
Out of `SO_(2),BeCl_(2),O_(3),H_(2)O and HgCl_(2),` the linear species are:A. `SO_(2) and O_(3)`B. `SO_(2) and H_(2)O`C. `BeCl_(2) and HgCl_(2)`D. `O_(3) and H_(2)O` |
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Answer» Correct Answer - C Both are Inear in nature. |
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| 655. |
HCl gas is covalent and NaCl is an ionic compound. This is becauseA. sodium is highly electropositiveB. hydrogen is a non-metalC. HCl is a gasD. electronegativity difference between H and Cl is less then 2.1 |
| Answer» Correct Answer - D | |
| 656. |
Why is HCl predominantly covalent in the gaseous state but is ionic in squeous solution ? |
| Answer» In HCl, the electronegativity difference in Cl and H atoms (3.0-2.1) is 0.9. Therefore, it is predominantly covalent in the gaseous state. When dissoved in water which is of polar nature, there an attraction between the atoms of the acid and polar `H_(2)O` molecules. Energy is released dureing attraction. This helps in the ionisation of the acid. Therefore, `C Cl_(4)` molecule, C-Cl bonds are polar but molecule is non ploar in aqueous solution. | |
| 657. |
Atom A,B and C occur in the same period and have one, six and seven valence electron respectively. (a) Will the bonds between B and C be predominantly ionic or covalent ? (b) Will the bond between A and B be predominantly ionic or covalent ? (c ) Write he electronic structure of the compound between B and C |
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Answer» (a) The bond between atoms B and C will be predominantly covalent as the difference of electronegatively is expected to be very small. (b) The bond between A and B will be predominantly ionic due to large difference in the electronegativity values. (c ) The electronic structure of compound formed between B and C (C-B-C) is `overset(* *)underset(* *)(":"C)overset(* *)underset(* *)(":"B":")overset(* *)underset(* *)(C":")` |
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| 658. |
Statement 1: Molecular nitrogen is less reactive than molecular oxygen Statement 2: The bond length of `N_(2)` is less as compared to that of `O_(2).`A. Statemetn-1 is true, Statrment-2 is also true, Statement -2 is the correct explanation of statement-10B. Statement -1 is true , Statement 2 is also true, Statement-2 is not the correct ezplanation of Statement-10C. Statement-1 is true, Statement-2 is false.D. Statement-1 is false, Statement-2 is true. |
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Answer» Correct Answer - a Statement 2 is is correct explanation foe Statement 1. |
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| 659. |
Write which one out of `O_(2)^(+) and O_(2)^(2-) ` is more stable on the basis of bond order calculations . |
| Answer» Bond order of `O_(2)^(+) = 2.5 `, Bond order of `O_(2)^(-)m = 1.5 . Hence, O_(2)^(+)` is more stable than `O_(2)^(-)` . | |
| 660. |
The type of hybrid orbitals of nitrogen in ` NO_(2)^(+), NO_(3)^(-) and NH_(4)^(+)` respectively are expected to beA. `sp, sp^(3) and sp^(2)`B. `sp, sp^(2) and sp^(3)`C. `sp^(2), sp and sp^(3)`D. `sp^(2) , sp^(3) and sp ` |
| Answer» Correct Answer - B | |
| 661. |
A reutral molecule `XF_(3)` has zero dipole menent. The element X is is most likelyA. chlorineB. boronC. nitrogenD. bromine |
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Answer» Correct Answer - B ` BF_(3)` is planar triangular |
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| 662. |
Which of the following hydrocarbons has the lowest dipole menent ?A. B. `CH_(3) -=C CH_(3)`C. `CH_(2)CH_(2) C-= CH`D. `CH_(2) -= CH - C -= CH` |
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Answer» Correct Answer - B It is symmetrical and linear . |
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| 663. |
Indicate which one from `O_(2)^(+) and O_(2)^(2-)` may exhibit paramagnetism ? |
| Answer» `O_(2)^(-)` shows paramagnetic because it contains one unpaired electron. | |
| 664. |
Which is expected to show paramagnetism ?A. `CIO_(2)`B. `SO_(2)`C. `CO_(2)`D. `SiO_(2)` |
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Answer» Correct Answer - a `ClO_(2)` has `33` electrons, i.e. , one unpaired. |
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| 665. |
The species which does not show paramagnetism is .A. `O_(2)`B. `O_(2)^(o+)`C. `O_(2)^(2-)`D. `H_(2)^(o+)` |
| Answer» Correct Answer - C | |
| 666. |
Paramagnetism is exhibited by molecules whichA. are not attracted by magnetic fieldB. contain only paired electronsC. contain unpaired electronsD. carry positive charge. |
| Answer» Correct Answer - C | |
| 667. |
In which of the following molecule , the contral atom does not have `sp^(2)` hybridization ?A. `CH_(4)`B. `SF_(4)`C. `BF_(4)^(-)`D. `NH_(4)` |
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Answer» Correct Answer - b `SF_(4) rarr sp^(3)` d hybrization and `CH_(4)` `{:(BF_(4)^(-)),(NH_(4)^(+)):}]rarr sp^(3) -"hybridization"`. |
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| 668. |
For the four successive transition elements (Cr, Mn, Fe, and Co), the stability of `+2` oxidation state will be there in which of the following order ? `(At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)`A. `Cr gt Mn gt Co gt Fe`B. `Mn gt Fe gt Cr gt Co`C. `Fe gt Mn gt Co gt Cr`D. `CogtMngtFegtCr` |
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Answer» Correct Answer - b `Mn^(2+)` is not most sttable because it has half -filled d-orbitals. |
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| 669. |
Valence-bond theory is one of the two quantum mechanical approaches that explains bonding in molecules In some cases, valence bond theroy cannot cannot satisfactorily account for observed properties of molecules Valnce-bond theroy can explain molecular geometries .A. predicated by `VSEPR` modelB. predicated by `MO` theoryC. predicated by both (a) and (b)D. predicated by none of these |
| Answer» Correct Answer - A | |
| 670. |
Valence-bond theory is one of the two quantum mechanical approaches that explains bonding in molecules In some cases, valence bond theroy cannot cannot satisfactorily account for observed properties of molecules Which of the following statements is correct about `O_(2),O_(2)^(Θ),O_(2)^(2-)` species ? .A. `KO_(2)` and `K_(2)O_(2)` are diamagnetic while `O_(2)` is paramagnetic .B. `KO_(2)` and `O_(2)` are paramagnetic while `K_(2)O_(2)` is diamagnetic .C. Bond length increase in the order `O_(2)ltO_(2)^(Θ)ltO_(2)^(2-)`D. Bond enthalpy increases in the order `O_(2)^(2-) ltO_(2)^(Θ) ltO_(2)` . |
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Answer» Correct Answer - A `O_(2)^(Θ)` (Superoxide ion) is paramagnetic . |
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| 671. |
Which of the following is (are) correct? .A. A double bond is shorter than a single bond .B. A sigma- vbond is weaker than a pi-bond .C. Adouble bond is stronger than a single bond .D. A covalent bond is stronger than a hydrogen bond . |
| Answer» Correct Answer - A::C::D | |
| 672. |
Valence-bond theory is one of the two quantum mechanical approaches that explains bonding in molecules In some cases, valence bond theroy cannot cannot satisfactorily account for observed properties of molecules Bond order and magnetic behaviour shown by different species have been matched Which is the incorrect matching .A. `{:("Species",,"Bond order",,"Magentic behaviour"),(CN^(Θ)(14),,3.0,,"dimagnetic"):}`B. `{:("Species",,"Bond order",,"Magentic behaviour"),(BN(14),,2.0,,"dimagnetic"):}`C. `{:("Species",,"Bond order",,"Magentic behaviour"),(C_(2)(12),,2.0,,"dimagnetic"):}`D. `{:("Species",,"Bond order",,"Magentic behaviour"),(B_(2)(10),,3.0,,"paramagnetic"):}` |
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Answer» Correct Answer - D Bond order of `B_(2)` is one |
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| 673. |
Valence-bond theory is one of the two quantum mechanical approaches that explains bonding in molecules In some cases, valence bond theroy cannot cannot satisfactorily account for observed properties of molecules Consider the following molecular geometries `{:(NO,,CO,,O_(2)):}` Select correct statement`(s)` about these (More than one correct) .A. `NO` is paramagnetic `CO` and `O_(2)` are diamagneticB. `NO` and `O_(2)` are paramagnetic `CO` is diamagenticC. Bond order is in order `O_(2) lt NO lt CO`D. Number of unpaired electrons are `{:(NO,,1,,),(CO,,0,,),(O_(2),,0,,):}` |
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Answer» Correct Answer - B::C Bond order of `NO,O_(2)` and `CO` and `CO` are 1,2 and 0 respectively Hence `NO` and `H_(2)` are paramagnetic `CO` is diamagentic Statement (b) is correct . |
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| 674. |
Valence-bond theory is one of the two quantum mechanical approaches that explains bonding in molecules In some cases, valence bond theroy cannot cannot satisfactorily account for observed properties of molecules `MO` electronic configuration of superoxide ion is .A. `KK^(**)(sigma2s)^(2),(sigma^(**)2s)^(2),(sigma2p_(z))^(2) (pi2p_(y))^(2) (pi^(**)2p)^(2)(pi^(**)2p_x)^(1)`B. `KK^(**)(sigma2s)^(2),(sigma^(**)2s)^(2),(sigma2p_(z))^(2) (pi2p_(y))^(2) (pi^(**)2p)^(2)(pi^(**)2p_x)^(2)`C. `KK^(**)(sigma2s)^(2),(sigma^(**)2s)^(2),(sigma2p_(z))^(2) (pi2p_(y))^(2) (pi^(**)2p)^(2)(pi^(**)2p_x)`D. none of these |
| Answer» Correct Answer - A | |
| 675. |
Which of the following is correct order of repulsive interactions ?A. Ip-lp gt Ip-bp gt bp-bpB. lp-bpgt lp-lp gt bp-bpC. bp-bp gt Ip-bp gt Ip-lpD. Any of the three depending upon the type of molecule. |
| Answer» Correct Answer - A | |
| 676. |
Amongst the following elements whose electronic configuration are given below, the one having the highest enthalpy isA. `[Ne]3s^(2)3p^(1)`B. `[Ne]3s^(2)3p^(3)`C. `[Ne]3s^(-2)3p^(2)`D. `[Ar]3d^(10)4s^(2)4p^(3)` |
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Answer» Correct Answer - B b) The electronic configured of options b) and d) have exactly half-filled 3p orbitals b), represents phosphorus and c) represents arsenic but b) is smaller in size than d). Hence, b) has highest ionisation enthalpy. Ionisation enthalpy increases left to right in the periodic table as the size decreases. |
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| 677. |
Amongst the following elements whose electronic configuration are given below, the one having the highest ionisation enthalpy isA. `[Ne] 3s^(2) 3p^(1)`B. `[Ne] 3s^(2) 3p^(3)`C. `[Ne] 3s^(2) 3p^(2)`D. `[Ar] 3d^(10) 4s^(2) 4p^(3)` |
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Answer» Correct Answer - A::D (b) and (d) have exactly half -filled 3p orbitals but (b) is smaller in size than (d) . Hence ,(b) has higest ionization enthalpy. |
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| 678. |
Complete the following table (b) Which of the sets of hybridised orbitals `sp sp^(2),sp^(3),dsp^(3),d^(2),sp^(3),sp^(3)d^(2)` do (does) not maximise the angles between electron pairs ? (c ) Fluorine molecule is formed by the overlap of __ (d) Predict the shapes of the following species and desribe the type of hybrid orbitals on the central atom (i) `PbCI_(4)`, (ii) `N_(2)CI_(4)` ,(iii) `PCI_(3)` ,(iv) `BH_(4)^(Θ), (v) SbF_(6)^(Θ)` (e) How many `sigma` and `pi` bonds are present in a benzene molecule ? . |
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Answer» (i) sp (ii) Square planar (iii) `dsp^(3)` (iv) `d^(2) sp^(3)` or `sp^(3) d^(2)` (v) Trigonal planar (b) The `sp^(3)` d hybrids have `90^(@)` and `120^(@)` angles Rearrangement of bond angles could produce angles greater that `90^(@)` but at the expenes of the highly symmetrical structure (c ) Overlap of p-p orbitals (d) (i) Tetrahedral `sp^(3)` (ii) Two pyramidal N-atoms with `sp^(3)` hybridisation on each, yield a non-planar molecule (iii) Pyramidal `sp^(3)` (a lone pair occupies the fourth) tetrahedral position) (iv) Tetrahedral `sp^(3)` (v) Octahedral `sp^(3)` `d^(2)` (e) `12sigma` and `3pi` bonds . |
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| 679. |
Explain (a )Which d-orbital in involved in (i) `sp^(3)`d hybridisation (ii) `sp^(3) d^(2)` hybridisation (iii) `dsp^(2)` hybridisation (iv) `sp^(3)d^(3)` hybridisation (b) Why `H_(2)O` is liquid while `H_(2)S` is gas (c ) Why `KHF_(2)` exists but `KHCI_(2)` does not (d) Benzene ring contains alternate single and double bonds yet all the `C-C` bonds are of equal lenght why (e) Out of `P-F,CI-F,S-F` and `F-F` bonds, which bond is the least ionic? . |
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Answer» (i) `dz^(2)` (ii) `dx^(2) -y^(2)` and `dz^(2)` (iii) `dx^(2)-y^(2)` (iv) `dxy,dyz,dxz` (b) Due to intermolecular H-bonding in `H_(2)O` association of `H_(2)O` molecules occurs but in `H_(2)S` there is no H-bonding (d) Due to resonance in benzene (e) `F-F` is the least ionic or more covalent due to the zero `EN` difference in `F-F` atoms Greater the difference in `EN` value of two atoms more ionic is the compound and vice versa . |
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| 680. |
Atomic orbitals involved in hybridisation of `SF_(6)` moleculeA. `3 s , 3p_(x) , 3 p_(y) , 3p_(z) , 3d_(z^(2)) , d_(x^(2) - y^(2))`B. `3 s 3 p_(x) , 3p_(y) , 3 p_(z) , 3 d_(z^(2))`C. ` 3 s , 3p_(x) , 3p_(y) , 3 p_(z) , 3 d_(x^(2) - y^(2)) , d_(xy)`D. `3s , 3p_(x) , 3p_(y) , 3d_(xy) , 3d_(yz) , 3d_(xz)` |
| Answer» Correct Answer - A | |
| 681. |
The d-orbitals involved in `sp^(3)d` hybridisation is:A. `d_((x^(2)-y^(2)))`B. `d_(xy)`C. `d_(z2)`D. `d_(zx)` |
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Answer» Correct Answer - C `d_(2)^(z)` orbital is involved in `sp^(3)d hybridisation. |
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| 682. |
In acetylene molecule, the carbon atoms are linked by:A. one sigma bond and two pi bondsB. two sigma bonds and one pi bondC. Three sigma bondsD. Three pi bonds. |
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Answer» Correct Answer - A (a) Acetylene `(H-C-=-H)` molecules has one sigma `(sigma)` and two pi `(pi)` bonds. |
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| 683. |
Which of the following at ordinary temperature and pressure exists as linear polymer due to extensive hydeogen bonding ?A. `H_(2)O`B. HClC. HFD. `NH_(3)` |
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Answer» Correct Answer - C HF moledcules exist as linear polymers due to extensive hydrogen bonding (…H-F…H-f…H-f…)n |
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| 684. |
In which of the following molecular/ions `BF_(2),NO_(2)^(-),NH_(2)` and ` H_(2)O` the correct atom is `sp^(2)` hybridized ?A. `BF_(3) and NO_(2)^(-)`B. ` NO_(2)^(-) and NH_(2)^(-)`C. `NH_(2)^(-) and H_(2)O`D. `NO_(2)^(-) and H_(2)O` |
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Answer» Correct Answer - a `{:("Molecule","hybridisation"),(BF_(3),sp^(2)),(NO_(2)^(-),sp^(2)),(NH_(2)^(-),sp^(3)),(H_(2)O,sp^(3)):}` `rArr BF_(3)` and ,`NO_(2)^(-)` are ,`sp^(2)`hybridized. Hence,option (a) is correct. |
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| 685. |
Compare the relative stability of the following species and indicate their magnetic properties: `O_(2)`,`O_(2)^(o+)`,`O_(2)^(ө)`(super oxide),`O_(2)^(-2)`(peroxide). |
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Answer» There are 16 electrons in a molecule of dioxygen,8 from each oxygen atom. The electronic configuration of oxygen molecule can be written as: `[sigma -(1s)]^(2)[sigma^(**)(1s)]^(2)[sigma(2s)]^(2)[sigma^(**)(2s)]^(2)[sigma(1p_(z))]^(2)[pi(2p_(x))]^(2)[pi(2p_(y))]^(2)[pi^(**)(2p_(x))]^(1)[pi^(**)(2p_(y))]^(1)` Since the 1s orbital of each oxygen atom is not involved in bonding, the number of bonding electrons=8=`N_(b)` and the number of anti-bonding orbitals=4=`N_(a)` Bond order `=(1)/(2)(N_(b)-N_(*a))` `=(1)/(2)(8-4)` `=2` Similarly, the electronic configuration of `O_(2)^(+)` can be written as: `KK[sigma(2s)]^(2)[sigma^(**)(2s)]^(2)[sigma(2p_(z))]^(2)[pi(2p_(x))]^(2)[pi(2p_(y))]^(2)[pi^(**)(2p_(x))]^(1)` `N_(b)=8` `N_(a)=3` Bond order of `O_(2)^(+)=(1)/(2)(8-3)=2.5 ` Electronic configuration of `O_(2)^(-)` ion will be : `KK[sigma(2s)]^(2)[sigma^(**)(2s)]^(2)[sigma(2p_(z))]^(2)[pi(2p_(x))]^(2)[pi(2p_(y))]^(2)[pi^(**)(2p_(x))]^(2)[pi^(**)(2p_(y))]^(1)` `N_(b)=8` `N_(a)=5` Bond order of `O_(2)^(-)=(1)/(2)(8-5)=1.5` Electronic configuration of `O_(2)^(2-)` ion will be : `KK[sigma(2s)]^(2)[sigma^(**)(2s)]^(2)[sigma(2p_(z))]^(2)[pi(2p_(x))]^(2)[pi(2p_(y))]^(2)[pi^(**)(2p_(x))]^(2)[pi^(**)(2p_(y))]^(2)` `N_(b)=8` ` N_(a)=6` Bond order of `O_(2)^(2-)=(1)/(2)(8-6)=1` Bond dissociation energy is directly proportional to bond order. Thus, the higher the bond order, the greater will be the stability. On this basis, the order of stability is `O_(2)^(+) gt O_(2) gt O_(2)^(-) gt O_(2)^(2-)`. |
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| 686. |
Out of `sigma and pi` -bonds, which one is stronger and why ? |
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Answer» `sigma `-bond is stronger . This is because `sigma `-bond is formed by head-on overlapping of atomic orbitals and , therefore , the overlapping is large . `pi` -bond is formed by sideway overlapping which is small . |
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| 687. |
The CGS unit of dipole moment is …………. Whereas its SI unit is ………….. |
| Answer» Debye, coulomb metre (C m) | |
| 688. |
What are SI unit of dipole moment ? |
| Answer» Coulomb meter (C m) . | |
| 689. |
Compare the shapes of p-orbital and sp-hybrid orbital Which on has a greater directional orientation ? (b) What are the hybridisation state of each C-atom in the following molecules ? (i) Benzene (ii) `CH_(3) CH_(2) CH_(2) CH_(3)` (iii) `HC -= CH` (iv) `CH_(2) =CH- CH= CH_(2)` (v) `CH_(3) - CH =CH - CH_(3)` (c ) What hybidisation is expected on the central atom of each of the following molecules ? (d) (i) Which molecule `AX_(3),AX_(4),AX_(5),AX_(6)` is likely to have to a trigonal bipyramid structure (ii) If the central atom A has no lone pairs, what type of hybridisation will it have . |
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Answer» The p-orbital has equal sized lobes most of the sp probability density is on one side making the latter more directrional in character (b) `All sp^(2)` (ii) `All sp^(3)` (iii) Both sp (iv) `All sp^(2)` (v) `sp^(3),sp^(2),sp^(2) ,sp^(3)` (c ) (i) `sp^(2)` (ii) `sp^(3) d^(2)` (ii) `sp^(3)` (iv) sp (d) (i) `AX_(5)` is the only molecule with five atoms bonded to central atom it is only possible molecule listed which could be trigonal bipyramidal (ii) In the absence of lone pairs, it must be `dsp^(3)` or `sp^(3)` d (An inner or velence d-orbital may be involved) . |
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| 690. |
Which of the following diatomic molecule would be stabilised by the removal of an electron ? .A. `O_(2)`B. `CN^(Θ)`C. `N_(2)`D. `C_(2)` |
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Answer» Correct Answer - A From `O_(2)` the electron is removed from antibonding orbital `KK^(**) sigma 2s^(2), sigma^(**) 2s^(2) , sigma2p_(z)^(2),(pi2p_(x)^(2))pi^(**)2p_(y)^(1)pi^(**)2p_(x)` . |
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| 691. |
In Which of the following species the bonds are non-directional ? .A. `NCI_(3)`B. `RbCI`C. `BeCI_(2)`D. `BCI_(2)` |
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Answer» Correct Answer - B `RbCI` is ionic compound and non directional |
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| 692. |
Assertion . Boiling points of cis-isomers are higher than trans-isomers. Reason. Dipole moment of cis-isomers are higher than trans-isomersA. If both assertion and reason are correct, and reason is the correct explanation of the assertion.B. If both assertion and reason are correct , but reason is not the correct explanation of the assertion.C. If assertion is correct, but reason is incorrect .D. If both assertion and reason are incorrect. |
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Answer» Correct Answer - a cis-isomers have greater dipole moment . Greter the dipole moment, higher is the boiling point |
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| 693. |
Define hydrogen bond. Is it weaker or stronger than the van der Waals forces ? |
| Answer» Hydrogen bond represents strong dipole dipole interactions between the H the highly electronegative atoms (F,0 are N) present in different bonds belonging to either different molecules or some molecule van Waals forces are also dipole forces, consult unit-5 on State of Matter. | |
| 694. |
Out of `N_(2) O , SO_(2), I_(3)^(+), I_(3)^(-), H_(2)O, NO_(2)^(-) and N_(3)^(-)` the linear species areA. `NO_(2)^(-), I_(3)^(+), H_(2)O`B. `N_(2)O,I_(3)^(-), N_(3)^(-)`C. `N_(2)O, I_(3)^(-), N_(3)^(-)`D. `N^(3-),I_(3)^(+), SO_(2)` |
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Answer» Correct Answer - C `N_(2)O` is linear with 2 bp and 3 lp `N_(3)^(-)` is linear with 2 bp around the central atom |
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| 695. |
Which of the following orders are correct for property indicated in brackets ? .A. `NH_(3)gtNF_(3)gtBF_(3)` (dipole moment)B. `CI gt S gt O gt N` (electron affinity)C. `Si gt Mg gt A1 gt Na` (first ionisation enthalpy)D. `HCIO_(4) gt HBrO_(4) gt HIO_(4)(pK_(a) "values")` |
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Answer» Correct Answer - A::B::C All are correct and all conceptual statements (d) is wrong Correct order for `pK_(a)` value is `HIO_(4) gt HBrO_(4) gt HCIO_(4)` Acidic strenght `HCIO_(4) gt HBrO_(4) gt HIO_(4)` weaker the acid higher is its `pK_(a)` value . |
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| 696. |
Which of the following have identical bond order ?A. `CN^(-)`B. `NO^(+)`C. `O_(2)^(-)`D. `O_(2)^(2-)` |
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Answer» Correct Answer - A::B Both `CH^(-) and NO^(+)` ions have bond order equal to 3.0 |
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| 697. |
Which of the following have identical bond order?A. `CN^(-)`B. `NO^(+)`C. `O_(2)^(-)`D. `O_(2)^(2-)` |
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Answer» Correct Answer - A::B (a,b) `CN^(-)` (number of electrons = 6+6+1=14 `NO^(+)` (number of electrons =`7+8-1=14)` `O_(2)^(-)` (number of electrons `=8+8+2=17)` `O_(2)^(2-)` (number of electrons =`8+8+2=18)` Thus, `CN^(-)` and `NO^(+)` because of the presence of same number of electrons, have same bond order. |
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| 698. |
Which of the following attain the linear structure ?A. `BeCl_(2)`B. `NCO^(+)`C. `NO_(2)`D. `CS_(2)` |
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Answer» Correct Answer - A::D (a,d) `BeCl_(2)(Cl-Be-Cl)` and `CS_(2)(S=C=S)` both are linear. `NCO^(+)` is non-linear. However, [remember that `NCO(-N=C=O)` is linear because it is isoelectric with `CO_(2)`. `NO_(2)` is angualr with bond angle `132^(@)` and each O-N bond begin of `1.20Å` (intermediate between single and double bond). |
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| 699. |
Which one of the following does not correctly represent the correct order of the property indicated against it ?A. `Ti lt V lt Cr lt Mn`: increasing number of oxidation statesB. `Ti^(3+) lt V^(3+) lt Cr^(3+) lt Mn^(3+)`: increasing magnetive momentC. `Ti lt V lt Cr lt Mn`: increasing melting pointsD. `Ti lt V lt Mn lt Cr `: increasing 2nd ionization enthalpy. |
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Answer» Correct Answer - c Correct order of melting point is `Mn(1246^(@)C) Ti(1668^(@)C) lt V =~ Cr (1907^(@)C)` |
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| 700. |
Which of the following has a regular geometry ?A. `CHCl_(3)`B. `PCl_(3)`C. `XeF_(6)`D. `SF_(4)` |
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Answer» Correct Answer - A `CHCl_(3)` = tetrahedral ," "`PCl_(3) ` = pyramidal `XeF_(6)` tetrahedral octahedral `SF_(4)` = distorted trigonal bipyramidal . |
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