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351.

Which one of the following molecule has complete octet?(a) BF3 (b) BeCl2 (c) BCl3 (d) CCl4

Answer»

The correct answer is- (d) CCl4

352.

The value of carbon – carbon triple bond length is ……………..(a) 1.33A(b) l.20Å(C) 1.54A(d) 1.43A

Answer»

The correct option is- (b) 1.20Å

353.

Among the following which one has bond order as 3?(a) N2(b) O2(c) HCHO(d) CH4

Answer»

The correct option is- (a) N2

354.

Which one of the flowing has bond order as 2?(a) N2(b) C2-H4(c) CH4(d) HCN

Answer»

The correct option is -(b) C2H4

355.

Identify the molecule with bond order 1.(a) N2(b) O2(c) H2(d) C2H4

Answer»

The correct option is- (c) H2

356.

What is dipole moment?

Answer»

1. The polarity of a covalent bond can be measured in terms of dipole moment which is defined as: 

µ = q x 2d, where µ is the dipole moment, q is the charge, 2d is the distance between the two charges.

2. The dipole moment is a vector quantity and the direction of the dipole moment points from the negative charge to positive charge.

3. The unit of dipole moment is Coulomb metre (C m). It is usually expressed in Debye unit (D).

4. 1 Debye = 3.336 x 10-30 Cm

357.

Why are atoms held together in chemical compounds?

Answer»

Atoms are held together in chemical compounds due to chemical bonds.

358.

What do you mean by formal charge ? Explain its significance with the help of suitable example.

Answer»

Formal charge is the charge assigned to an atom in a molecule, assuming that all electrons are shared equally between atoms, regardless of their relative electronegativities.

Structure (I) :

Number of atomTotal number of electrons in free atom (V.E.)Total number of non-bonding electrons(N.E.)Total number of shared electrons in bond(B.E.)

Formal charge
F.C=(V.E)-(N.E)-\(\frac{1}{2}\)(B.E.)

1644F.C = 6-4-\(\frac{1}{2}\)(4) = 0
2408

F.C = 4-0-\(\frac{1}{2}\)(8) = 0

3644

F.C = 6-4-\(\frac{1}{2}\)(4) = 0

Structure (II) :

Number of atomTotal number of electrons in free atom (V.E.)Total number of non-bonding electrons(N.E.)Total number of shared electrons in bond(B.E.)

Formal charge
F.C=(V.E)-(N.E)-\(\frac{1}{2}\)(B.E.)

1626

F.C = 6-2-\(\frac{1}{2}\)(6) = ±1

2408

F.C = 4-0-\(\frac{1}{2}\)(8) = 0

3662

F.C = 6-6-\(\frac{1}{2}\)(2) = -1

Structure (III) :

Number of atomTotal number of electrons in free atom (V.E.)Total number of non-bonding electrons(N.E.)Total number of shared electrons in bond(B.E.)

Formal charge
F.C=(V.E)-(N.E)-\(\frac{1}{2}\)(B.E.)

1662

F.C = 6-6-\(\frac{1}{2}\)(2) = -1

2408

F.C = 4-0-\(\frac{1}{2}\)(8) = 0

3626

F.C = 6-2-\(\frac{1}{2}\)(6) = +1

While determining the best Lewis structure per molecule, the structure is chosen such that the formal charge is as close to zero as possible. 

The structure having the lowest formal charge has the lowest energy.

In structure (I),

The formal charge on each atom is 0 while in structures (II) and (III) formal charge on carbon is 0 while oxygens have formal charge -1 or +1. 

Hence, 

The possible structure with the lowest energy will be structure (I). 

Thus,

Formal charges help in the selection of the lowest energy structure from a number of possible Lewis structures for a given species.

359.

Which one of the following has an ionic bond?(a) CO2 (b) CH4 (c) CaF2(d) BeCI2

Answer»

The correct answer is- (c) CaF2

360.

What is an ionic bond? Explain about the formation of ionic bond with a suitable example.

Answer»

1. The complete transfer of electrons leads to the formation of a cation and an anion. Both these ions are held together by electrostatic attractive forces which is known as ionic bond.

2. KCl: Potassium chloride

Electronic configuration of K[Ar] 4s

Eleçtronic configuration of Cl = [N]3s23p5

3. Potassium has 1 electron in its valence shell and chlorine has 7 electrons in its valence shell.

4. By losing one electron potassium attains the nearest inert gas configuration of Argon and becomes a unipositive cation (K) and chlorine accepts this electron to become uninegative chloride ion (CI) to attain the stable configuration of nearest noble gas, Argon.

5. These two ions combine to form an ionic crystal in which they are held together by electrostatic attractive forces.

6. During the formation of one mole of potassium chloride crystal from its constituent ions, 718 kJ of energy is released. This favours the formation of KCl and its stabilisation.

361.

Prove that bond order is inversely proportional to bond length.

Answer»

1. Bond order \(\propto\) \(\frac{1}{Bond\,length}\)

2. An example for illustrating the above equation is Carbon – carbon single bond length (I .54Å) is longer than the carbon-carbon double bond length (1.34Å) and the carbon- carbon triple bond length (1 .20Å).

362.

Define Bond angle.

Answer»

Covalent bonds are directional in nature and are oriented in specific direction in space. This directional nature creates a fixed angle between two covalent bonds in a molecule and this angle is termed as bond angle.

363.

Define Resonance.

Answer»

The similar structures in which the relative position of the atoms are same but they differ in the position of bonding and lone pair of electrons are called resonance structures and this phenomenon is called resonance.

364.

Choose the odd one out.(a) NaCl (b) CO2 (c) LiF (d) MgO

Answer»

(b) CO2

It contains covalent bond whereas others have ionic bond.

365.

How many σ and π-bonds are present in CH2 = CH - CH = CH2?

Answer»

There are 9 σ-bonds and 2π-bonds.

366.

What is the total number of σ and π-bonds in the following molecules?C7H8, C6H5OH, CH3 - CH = C = CH - C ≡ CH.

Answer»

(i) C7H8  15σ and 3π

(ii) C6H5OH  13σ and 3π

(iii) CH3 - CH = C = CH - C ≡ CH  11σ and 4π

367.

Explain how V.B. theory differs from the Lewis concept.

Answer»

The Lewis concept of describe the formation of bond in terms of sharing of one or more electron pairs and the octet rule. It does not explain the energetic of the bond formation and shapes of the polyatomic molecules.

The VB theory describes the bond formation in terms of hybridization and overlap of the orbitals. The overlap of orbitals along the intermolecular axis increases the electron-density between the two nuclei resulting in a decrease in the energy and formation of a bond.

368.

How is VBT different from Lewis concept?

Answer»

In Lewis concept, bond formation is explained in terms of sharing of electron pairs and the Octet rule whereas in VBT bond formation is described in terms of hybridization and overlap of the orbitals.

369.

Malleability and ductility of metals can be accounted due to the capacity of layers of …………………. to slide over one another.

Answer»

metal ions

Malleability and ductility of metals can be accounted due to the capacity of layers of metal ions to slide over one another.

370.

O-Nitrophenol is more volatile than p-Nitrophenol (Or) boiling point of p- nitrophenol is greater than O-nitrophenol)

Answer»

In O-Nitrophenol there exists intra molecular hydrogen bonding within the molecule where as in p-nitrophenol there exists inter molecular hydrogen bonding between the molecule.

371.

Why is o-nitrophenol steam volatile whereas p-nitrophenol is not?

Answer»

p-nitrophenol, is associated through intermolecular H-bonding and hence less volatile.

372.

out of NaCl and MgO which has higher value of lattice energy?

Answer»

MgO has higher value of lattice energy due to stronger force of attraction between divalent Mg2+ and O2- than monovalent Na= and Cl- ions.

373.

State three differences between ‘X’ and ‘X1+ ’ i.e. an atom and an ion. 

Answer»

Atoms – ‘X’

1. Electrically – neutral particles

2. May or may not exist – independently

3. Outermost shell – may or may not have duplet or octet.

Ions – X1+

1. Electrically-charged particles [cations, anions]

2. Exist – independently in solution

3. Outermost shell -have complete duplet or octet.

374.

What are the differences between sodium atom and sodium ion?

Answer»

1. Sodium atom is neutral whereas sodium ion has unipositive charge. 

2. The size of sodium ion is smaller than sodium atom. 

3. The properties of sodium ion is different when compared with sodium.

375.

In the formation of compound XY2 , atorix X gives one electron to each Y atom. What is the nature of bond to XY2 ? Give four properties of XY2 . 

Answer»

The bond in XY2 is ionic.

Properties:

(i) It is hard and brittle.

(ii) It is soluble in water.

(iii) It has high melting and boiling point.

(iv) It does not conduct electric current in the solid state but conducts electric current in the molten or dissolved state.

376.

In the formation of the compound XY2, an atom X gives one electron to each Y atom. What is the nature of bond in XY2 ? Give two properties of XY2.

Answer»

Two electrons are transferred from X to Y. X forms positive ion and Y forms a negative ion. So the bond formed is ionic in nature. 

Properties of ionic compounds : 

a) They are hard crystals. 

b) They have high boiling point and melting point. 

c) They are soluble in water.

377.

What type of compounds are usually formed between metals and non-metals and why?

Answer»

Ionic compounds are generally formed between metals and non-metals as metals always lose  electrons to form cations while non-metals gain electrons forming anions to complete their octet.  These oppositely charged ions are held together by electrostatic force of attraction and hence  results in an ionic compound.

378.

The common features among the species CO and NO+ are : ……………(A) isoelectronic species and bond order 3 (B) isoelectronic species and bond order 2 (C) odd electron species and unstable (D) odd electron species and bond order 1

Answer»

Correct Option is : (A) isoelectronic species and bond order 3

Both CO and \(NO^+\) have 14 electrons . It means they are isoelectronic species.

Both species have bond order = 3

Option : (A) isoelectronic species and bond order 3

379.

Which of the following species has tetrahedral geometry?(i) BH4–(ii) NH2–(iii) CO32–(iv) H3O+

Answer»

The correct answer is (i) BH4

380.

Give reasons for the followingWater molecule has bent structure whereas carbon dioxide molecule is linear.

Answer»

In water, the central oxygen atom is sp3? hybridised whereas inCO2, the central carbon atom issp-hybridised. Net dipole moment of CO2  is zero whereas H2O has a considerable value. This shows COis linear whereas water has bent structure.

381.

Why most of the covalent compounds have density less than that of water ?

Answer»

The covalent molecules are held very weakly by van der Waal’s forces. Thus, there are large inter molecular spaces between the molecules. In other words the number of molecules per unit volume is less. Thus mass per unit is also less and hence, covalent compound have low density. 

382.

Why covalent compounds have low melting point and boiling point ?

Answer»

The force of attraction between the molecules is very weak and so the amount of energy needed to separate them is small, consequently they have low melting points and boiling points. 

As the bond is formed by sharing of electrons between two atoms. Intermolecular forces are small between the covalent compounds. These bonds break easily.

383.

Predict the reasons for low melting point for covalent compounds when compared with ionic compounds. (OR) “Covalent compounds have low melting point.” What Is the reason for this statement? Explain.

Answer»

They are covalent compounds.

1. The melting point is low due to the weak Vander Waal’s forces of attractions between the covalent molecules. 

2. The force of attraction between the molecules of a covalent compound is very weak. 

3. Only a small amount of heat energy is required to break these weak molecular forces, due to which covalent compounds have low melting points and low boiling points. 

4. Please note that some of the covalent solids like diamond and graphite have, however very high melting points and boiling points.

384.

Explain the Coordinate bond.  

Answer»

Coordinate Bond: It is a type of covalency which involves one of the combining atoms contributing both of the shared electrons, i.e. a bond formed by a shared pair of electrons with both electrons coming from the same atom.

385.

Which compounds exhibit low melting and boiling points?

Answer»

Covalent compounds exhibit low melting and boiling points when compared to ionic compounds.

386.

Give reasons :Iron displaces copper from a solution of a copper salt. The reaction is deemed as a redox reaction.

Answer»

Fe (s) + CuSO4 (aq) → FeSO4 (aq) + Cu (s) 

Ionic equation for the reaction can be written as ;

Fe (s) + Cu2+ (aq) → Fe2+ (aq) + Cu (s)

In this reaction iron loses two electron and is oxidized to Fe2+ .

Fe (s) → Fe2+ (aq) (-2e ) (Oxidation)

On the other hand Cu2+ gains two electrons and is reduced to copper.

Cu2+ (aq) → 2e → Cu (s) (Reduction)

Thus the given reaction is a redox reaction.

387.

Explain Octet rule with an example.

Answer»

The tendency of atoms to have eight electrons in the valence shell is known as the ‘Octet rule’ or the ‘Rule of eight’.

Example: Sodium with atomic number 11 will readily loose one electron to attain Neon’s stable electronic configuration

388.

Why do covalent compounds exist as gases, liquids or soft solids ?

Answer»

Covalent compounds exists as gases, liquids or soft solids because they have weak forces of attraction between their molecules. 

389.

Write a note on different types of bonds.

Answer»

All the elements differ with each other in their valence shell electronic configuration. So the way in which they combine to form compounds also differs. Hence, there are different types of chemical bonding possible between atoms which make the molecules. Depending on the type of bond they show different characteristics or properties. Such types of bonding that are considered to exist in molecules are categorized as the Ionic bond, Covalent bond and Coordinate bond. 

390.

Why hydrogen chloride can be termed as a polar covalent compound ?

Answer»

Pure covalent bond exists between two elements which have similar electro negativities. In hydrogen chloride, chlorine being more electro negative attracts the shared pair of electrons towards itself. As a result hydrogen acquires partial positive charge and chlorine gets partial r negative charge. Thus, hydrogen chloride can be termed as a polar covalent compound.

391.

Fill in the following table according to the type of bonds formed in the given molecule CaCl2 , H2O, CaO, CO, KBr, HCl, CCl4 , HF, CO2 , Al2Cl6

Answer»
Ionic bondCovalent bondCoordinate covalent bond
CaOH2O, HFCO
CaCl2CO2
KBrCCl4 , Al2Cl6
392.

What are Ions?

Answer»

Ions are charged particles.

393.

How are atoms charged ?

Answer»

The atom which loses electron acquire positive charge and the atoms gain electrons acquire a negative charge.

394.

Choose the correct answer from the choices given below. The property which is characteristics of an Ionic compound is that 1. it often exists as gas at room temperature 2. it is hard and brittle 3. it undergoes molecular reactions 4. it has low melting point 5. it is hard and brittle

Answer»

2. It is hard and brittle

395.

Compound ‘X’ consists of only molecules. ‘X’ will have –(A) A Crystalline hard structure(B) A low (m.p.) melting point and low (b.p.) boiling point(C) An ionic bond(D) A strong force of attraction between its molecules.

Answer»

(B) A low (m.p.) melting point and low (b.p.) boiling point

396.

How ionic compounds formed?

Answer»

The formation of ionic compounds involves the formation of ions and the attraction of ion pairs.

397.

Identify the following reactions as oxidation or reduction 1. Na ➝ Na+ + e- 2. Fe3+ + 2 e- ➝ Fe+

Answer»

1. It is an Oxidation reaction. 

Oxidation: A chemical reaction which involves addition of oxygen or removal of hydrogen or loss of electrons is called oxidation. 

2. It is a Reduction reaction.

 Reduction: A chemical reaction which involves addition of hydrogen or removal of oxygen or gain of electrons is called reduction.

398.

State which of the following are Oxidation ,Reduction , Reduction , Oxidation1. Zn → Zn2+2. S → S2-3. Sn2+ →  Sn4. Fe2+ → Fe3+

Answer»

(1) Oxidation

(2) Reduction

(3) Reduction

(4) Oxidation

399.

State which of the following are oxidation reactions and which are reduction reactions.1. Cu → Cu2+ + 2e–2. Cu2+ + 2e– → Cu3. Sn4+ + 2e–→Sn2+4. 2Cl-  →  Cl2  +  2e-5. Fe2+ →  Fe3+ + Ie–6. X  +  2e-  → X2- 7. Y -  Ie– → Y1+8. Z3+ +  Ie– → Z2+

Answer»

Oxidation reactions: 

(3)  Sn4+ + 2e–  → Sn2+

(6)  X + 2e– → X2-

(7)  Y - Ie → Y1+

(8)  Z3+ + Ie–  →  Z2+

 Reduction reactions.

(1) Cu → Cu2+ + 2e

(2)  Cu2+ + 2e → Cu 

(4)  2Cl- → Cl2 + 2e-

(5)  Fe2+ → Fe3+ +  Ie 

400.

Explain the terms ‘oxidation’ and reduction’ with reference to an atom or ion. 

Answer»

Oxidation: Loss of one or more electrons by an atom or ion is called oxidation.

For example,

Na → Na+ + e

Fe2+ → Fe3+ + e-

Mg → Mg2+ + e-

Reduction: Gain of one or more electrons by an atom or ion is called reduction.

For example,

F + e → F

O + 2e- → O2–

Cu2+ + e → Cu+

Zn2 + 2e– → Zn